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(x-2) person can do a work in x days and (x+7) person can do 75% of the same work in (x-10)days. Then in how many days can (x+10) person finish the work?
- a)27 days
- b)12 days
- c)25 days
- d)18 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
(x-2) person can do a work in x days and (x+7) person can do 75% of th...
3/4 * (x-2)x = (x+7)(x-10)
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
Most Upvoted Answer
(x-2) person can do a work in x days and (x+7) person can do 75% of th...
Given:
(x-2) person can do a work in x days
(x+7) person can do 75% of the same work in (x-10) days
To find:
In how many days can (x+10) person finish the work?
Solution:
Let us assume that the work done is 1 unit.
So, (x-2) persons can do 1 unit of work in x days.
Hence, the work done by 1 person in 1 day = 1/(x(x-2))
(x+7) persons can do 75% of the same work in (x-10) days.
So, the work done by (x+7) persons in 1 day = 0.75/ (x-10)
Let the number of days required for (x+10) persons to complete the work be d.
So, the work done by (x+10) persons in 1 day = 1/d
Now, we know that the work done is the same in all the cases.
Hence, we can equate the work done by (x-2) persons to the work done by (x+7) persons and (x+10) persons.
(x-2)/x = 0.75/(x-10) = (x+10)/d
Solving for d, we get d = 12 days.
Hence, (x+10) persons can finish the work in 12 days.
Answer: Option B) 12 days
(x-2) person can do a work in x days
(x+7) person can do 75% of the same work in (x-10) days
To find:
In how many days can (x+10) person finish the work?
Solution:
Let us assume that the work done is 1 unit.
So, (x-2) persons can do 1 unit of work in x days.
Hence, the work done by 1 person in 1 day = 1/(x(x-2))
(x+7) persons can do 75% of the same work in (x-10) days.
So, the work done by (x+7) persons in 1 day = 0.75/ (x-10)
Let the number of days required for (x+10) persons to complete the work be d.
So, the work done by (x+10) persons in 1 day = 1/d
Now, we know that the work done is the same in all the cases.
Hence, we can equate the work done by (x-2) persons to the work done by (x+7) persons and (x+10) persons.
(x-2)/x = 0.75/(x-10) = (x+10)/d
Solving for d, we get d = 12 days.
Hence, (x+10) persons can finish the work in 12 days.
Answer: Option B) 12 days
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Community Answer
(x-2) person can do a work in x days and (x+7) person can do 75% of th...
3/4 * (x-2)x = (x+7)(x-10)
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
x – 6x – 280 = 0
x = 20; x = -14
(x-2)x = 18 * 20 = 360
360 = 30 * y
y = 12 days
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