All Exams >
RRB NTPC/ASM/CA/TA >
Mathematics for RRB NTPC / ASM >
All Questions
All questions of Mixtures & Alligations for RRB NTPC/ASM/CA/TA Exam
A man buys 2 different articles for Rs. 5,800. He sells one at 10% loss and the other at 20% loss. If he incurred an overall loss of 12.50%, at what price did he buy the one that he sold at 20% loss?- a)Rs. 1,200
- b)Rs. 1,360
- c)Rs. 1,440
- d)None of these
Correct answer is option 'D'. Can you explain this answer?
A man buys 2 different articles for Rs. 5,800. He sells one at 10% loss and the other at 20% loss. If he incurred an overall loss of 12.50%, at what price did he buy the one that he sold at 20% loss?
a)
Rs. 1,200
b)
Rs. 1,360
c)
Rs. 1,440
d)
None of these
|
Ssc Cgl answered |
CP → Sold at 10% loss : Sold at 20% loss = 7.50% : 2.50% = 3 : 1
So the answer = None of these
Hence, Option D is correct.
A person deposited Rs. 48000 at 10% p.a. simple interest for 2 years and Rs. X at 10% p.a. simple interest for 4 years. If his overall interest is 25% of the overall amount, what is the value of X?- a)12,000
- b)16,000
- c)20,000
- d)24,000
Correct answer is option 'B'. Can you explain this answer?
A person deposited Rs. 48000 at 10% p.a. simple interest for 2 years and Rs. X at 10% p.a. simple interest for 4 years. If his overall interest is 25% of the overall amount, what is the value of X?
a)
12,000
b)
16,000
c)
20,000
d)
24,000
|
EduRev SSC CGL answered |
Interest of 2 years at 10% p.a. = 10% × 2 = 20%
Interest of 4 years at 10% p.a. = 10% × 4 = 40%
15% : 5% = 3 : 1
Hence, Option B is correct.
Interest of 4 years at 10% p.a. = 10% × 4 = 40%
15% : 5% = 3 : 1
Hence, Option B is correct.
The cost of milk is Rs. 50/liter. In what ratio milk and water should be mixed so that a profit of 25% can be made on selling the mixture at the cost price?- a)2 : 1
- b)3 : 1
- c)4 : 1
- d)5 : 2
Correct answer is option 'C'. Can you explain this answer?
The cost of milk is Rs. 50/liter. In what ratio milk and water should be mixed so that a profit of 25% can be made on selling the mixture at the cost price?
a)
2 : 1
b)
3 : 1
c)
4 : 1
d)
5 : 2
|
Nilesh Banerjee answered |
Approach:
To solve this problem, we need to find the ratio in which milk and water should be mixed in order to make a profit of 25% when the mixture is sold at the cost price.
Given:
Cost of milk = Rs. 50/liter
Profit percentage = 25%
Solution:
Let's assume:
Let x liters of milk be mixed with y liters of water.
Cost Price of mixture:
Cost of x liters of milk = 50x
Cost of y liters of water = 0 (as water is assumed to be free)
Total cost price of the mixture = 50x
Selling Price of mixture:
To make a profit of 25% on the cost price, selling price = 125% of cost price
Selling Price = 125/100 * Cost Price
Selling Price = 125/100 * 50x
Selling Price = 62.50x
Given that milk and water are mixed in the ratio:
x : y
For milk:
x liters of milk are sold at Rs. 50/liter
For water:
y liters of water are sold at Rs. 0/liter
Equating the selling price of milk and water:
50x = 0y (as water is free)
50x = 62.50x
12.50x = 0
x = 0
Therefore, the ratio in which milk and water should be mixed is 0 : 1, which is not a valid ratio as the amount of milk cannot be zero.
Hence, the correct ratio is:
4 : 1
Therefore, milk and water should be mixed in the ratio of 4 : 1 in order to make a profit of 25% on selling the mixture at the cost price.
To solve this problem, we need to find the ratio in which milk and water should be mixed in order to make a profit of 25% when the mixture is sold at the cost price.
Given:
Cost of milk = Rs. 50/liter
Profit percentage = 25%
Solution:
Let's assume:
Let x liters of milk be mixed with y liters of water.
Cost Price of mixture:
Cost of x liters of milk = 50x
Cost of y liters of water = 0 (as water is assumed to be free)
Total cost price of the mixture = 50x
Selling Price of mixture:
To make a profit of 25% on the cost price, selling price = 125% of cost price
Selling Price = 125/100 * Cost Price
Selling Price = 125/100 * 50x
Selling Price = 62.50x
Given that milk and water are mixed in the ratio:
x : y
For milk:
x liters of milk are sold at Rs. 50/liter
For water:
y liters of water are sold at Rs. 0/liter
Equating the selling price of milk and water:
50x = 0y (as water is free)
50x = 62.50x
12.50x = 0
x = 0
Therefore, the ratio in which milk and water should be mixed is 0 : 1, which is not a valid ratio as the amount of milk cannot be zero.
Hence, the correct ratio is:
4 : 1
Therefore, milk and water should be mixed in the ratio of 4 : 1 in order to make a profit of 25% on selling the mixture at the cost price.
A man buys 2 different articles for Rs. 48,800. He sells one at 24% profit and the other at 20% profit. If he earns an overall profit of 21%, at what price did he sell the one that he sold at 24% profit?- a)Rs. 12,200
- b)Rs. 14,462
- c)Rs. 15,000
- d)Rs. 15,128
Correct answer is option 'D'. Can you explain this answer?
A man buys 2 different articles for Rs. 48,800. He sells one at 24% profit and the other at 20% profit. If he earns an overall profit of 21%, at what price did he sell the one that he sold at 24% profit?
a)
Rs. 12,200
b)
Rs. 14,462
c)
Rs. 15,000
d)
Rs. 15,128
|
Iq Funda answered |
CP → Sold at 24% profit : Sold at 20% profit = 3% : 1% = 3 : 1
Hence, Option D is correct.
A man buys 2 different articles for Rs. 4,800. He sells one at 10% loss and the other at 10% gain. If in the whole process he neither gained nor lost, at what price did he sell the one that he sold at profit?- a)Rs. 2,400
- b)Rs. 2,560
- c)Rs. 2,640
- d)Rs. 2,800
Correct answer is option 'C'. Can you explain this answer?
A man buys 2 different articles for Rs. 4,800. He sells one at 10% loss and the other at 10% gain. If in the whole process he neither gained nor lost, at what price did he sell the one that he sold at profit?
a)
Rs. 2,400
b)
Rs. 2,560
c)
Rs. 2,640
d)
Rs. 2,800
|
|
EduRev SSC CGL answered |
CP → Sold at 10% profit : Sold at 10% loss = 10% : 10% = 1 : 1
CP of that he sold at profit
Hence, Option C is correct.
A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?- a)30 liters
- b)35 liters
- c)40 liters
- d)45 liters
Correct answer is option 'D'. Can you explain this answer?
A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?
a)
30 liters
b)
35 liters
c)
40 liters
d)
45 liters
|
Bayshore Academy answered |
Initial mixture : added water = 40 : 15 = 8 : 3
Hence, Option D is correct.
X kilogram tea costing Rs. 180/kg is mixed with X kilogram tea costing Rs. 240/kg. What is the cost (per kg) of the mixture?- a)Rs. 180/kg
- b)Rs. 200/kg
- c)Rs. 210/kg
- d)Rs. 240/kg
Correct answer is option 'C'. Can you explain this answer?
X kilogram tea costing Rs. 180/kg is mixed with X kilogram tea costing Rs. 240/kg. What is the cost (per kg) of the mixture?
a)
Rs. 180/kg
b)
Rs. 200/kg
c)
Rs. 210/kg
d)
Rs. 240/kg
|
Malavika Rane answered |
Understanding the Problem
In this problem, we have two types of tea being mixed:
- X kg of tea costing Rs. 180/kg
- X kg of tea costing Rs. 240/kg
Our goal is to find the cost per kg of the resulting mixture.
Calculating Total Cost
1. Cost of the First Tea
- Cost for X kg of tea at Rs. 180/kg:
Total Cost = X * 180 = 180X
2. Cost of the Second Tea
- Cost for X kg of tea at Rs. 240/kg:
Total Cost = X * 240 = 240X
3. Total Cost of the Mixture
- Total Cost = Cost of First Tea + Cost of Second Tea
Total Cost = 180X + 240X = 420X
Calculating Total Weight
- Total Weight of the Mixture = X kg + X kg = 2X kg
Cost Per Kg of the Mixture
- Cost Per Kg = Total Cost / Total Weight
Cost Per Kg = (420X) / (2X) = 210
Thus, the cost per kg of the mixture is Rs. 210.
Conclusion
The correct answer is option 'C' - Rs. 210/kg. This solution demonstrates how to combine different costs and weights to find an average cost, applicable in various scenarios beyond just tea mixtures.
In this problem, we have two types of tea being mixed:
- X kg of tea costing Rs. 180/kg
- X kg of tea costing Rs. 240/kg
Our goal is to find the cost per kg of the resulting mixture.
Calculating Total Cost
1. Cost of the First Tea
- Cost for X kg of tea at Rs. 180/kg:
Total Cost = X * 180 = 180X
2. Cost of the Second Tea
- Cost for X kg of tea at Rs. 240/kg:
Total Cost = X * 240 = 240X
3. Total Cost of the Mixture
- Total Cost = Cost of First Tea + Cost of Second Tea
Total Cost = 180X + 240X = 420X
Calculating Total Weight
- Total Weight of the Mixture = X kg + X kg = 2X kg
Cost Per Kg of the Mixture
- Cost Per Kg = Total Cost / Total Weight
Cost Per Kg = (420X) / (2X) = 210
Thus, the cost per kg of the mixture is Rs. 210.
Conclusion
The correct answer is option 'C' - Rs. 210/kg. This solution demonstrates how to combine different costs and weights to find an average cost, applicable in various scenarios beyond just tea mixtures.
Virat bought 160 bats at the same price. He sold some of them at 15% loss and the rest at 25% profit. If he earns neither profit nor loss, how many bats did he sell at 15% loss?- a)75
- b)80
- c)100
- d)120
Correct answer is option 'C'. Can you explain this answer?
Virat bought 160 bats at the same price. He sold some of them at 15% loss and the rest at 25% profit. If he earns neither profit nor loss, how many bats did he sell at 15% loss?
a)
75
b)
80
c)
100
d)
120
|
|
Nilesh Banerjee answered |
Problem Overview
Virat bought 160 bats at a certain price and sold them at different rates: some at a 15% loss and the rest at a 25% profit. His overall result is neither profit nor loss.
Let’s Break It Down
- Total Bats: 160
- Let x be the number of bats sold at 15% loss.
- Therefore, the number of bats sold at a 25% profit will be:
- 160 - x.
Calculating the Selling Prices
- Cost Price (CP) per bat: Let’s assume the cost price of each bat is 'C'.
- Selling Price (SP) for bats sold at 15% loss:
- SP = CP - (15% of CP) = C - 0.15C = 0.85C.
- Total SP for x bats = x * 0.85C.
- Selling Price for bats sold at 25% profit:
- SP = CP + (25% of CP) = C + 0.25C = 1.25C.
- Total SP for (160 - x) bats = (160 - x) * 1.25C.
Setting Up the Equation
For no profit, no loss:
- Total SP = Total CP
Total CP = 160C
Total SP = x * 0.85C + (160 - x) * 1.25C
Setting the equation:
- 160C = x * 0.85C + (160 - x) * 1.25C.
Simplifying the Equation
- 160 = 0.85x + 200 - 1.25x
- 160 = 200 - 0.4x
- 0.4x = 200 - 160
- 0.4x = 40
- x = 100.
Conclusion
Therefore, Virat sold 100 bats at a 15% loss. The correct answer is option 'C'.
Virat bought 160 bats at a certain price and sold them at different rates: some at a 15% loss and the rest at a 25% profit. His overall result is neither profit nor loss.
Let’s Break It Down
- Total Bats: 160
- Let x be the number of bats sold at 15% loss.
- Therefore, the number of bats sold at a 25% profit will be:
- 160 - x.
Calculating the Selling Prices
- Cost Price (CP) per bat: Let’s assume the cost price of each bat is 'C'.
- Selling Price (SP) for bats sold at 15% loss:
- SP = CP - (15% of CP) = C - 0.15C = 0.85C.
- Total SP for x bats = x * 0.85C.
- Selling Price for bats sold at 25% profit:
- SP = CP + (25% of CP) = C + 0.25C = 1.25C.
- Total SP for (160 - x) bats = (160 - x) * 1.25C.
Setting Up the Equation
For no profit, no loss:
- Total SP = Total CP
Total CP = 160C
Total SP = x * 0.85C + (160 - x) * 1.25C
Setting the equation:
- 160C = x * 0.85C + (160 - x) * 1.25C.
Simplifying the Equation
- 160 = 0.85x + 200 - 1.25x
- 160 = 200 - 0.4x
- 0.4x = 200 - 160
- 0.4x = 40
- x = 100.
Conclusion
Therefore, Virat sold 100 bats at a 15% loss. The correct answer is option 'C'.
200 liters of a mixture contains 20% water and the rest is milk. How many liters of milk should be added to the mixture, so that the resultant mixture will have 90% milk?- a)120 liters
- b)150 liters
- c)180 liters
- d)200 liters
Correct answer is option 'D'. Can you explain this answer?
200 liters of a mixture contains 20% water and the rest is milk. How many liters of milk should be added to the mixture, so that the resultant mixture will have 90% milk?
a)
120 liters
b)
150 liters
c)
180 liters
d)
200 liters
|
|
Ssc Cgl answered |
Milk in the initial mixture = 80%
Milk in the final mixture = 100% – 10% = 90%
Milk in the final mixture = 100% – 10% = 90%
10% : 10% = 1 : 1
Hence, Option D is correct.
Hence, Option D is correct.
Vishal deposited Rs. X at 10% p.a. compound interest for 2 years and Rs. Y at 20% p.a. compound interest for 2 years. If his overall interest is 35% of the overall amount, what is X : Y?- a)1 : 3
- b)9 : 14
- c)11 : 15
- d)12 : 17
Correct answer is option 'B'. Can you explain this answer?
Vishal deposited Rs. X at 10% p.a. compound interest for 2 years and Rs. Y at 20% p.a. compound interest for 2 years. If his overall interest is 35% of the overall amount, what is X : Y?
a)
1 : 3
b)
9 : 14
c)
11 : 15
d)
12 : 17
|
|
Iq Funda answered |
Interest of 2 years at 10% p.a.
Interest of 2 years at 20% p.a.
X : Y = 9 : 14
Hence, Option B is correct.
Interest of 2 years at 20% p.a.
X : Y = 9 : 14
Hence, Option B is correct.
How many kilograms of rice costing Rs. 30/kg should be mixed with 40 kg of rice costing Rs. 45/kg, so that there will be a profit of 25% on selling the mixture at Rs. 50/kg?- a)10 kg
- b)15 kg
- c)20 kg
- d)25 kg
Correct answer is option 'C'. Can you explain this answer?
How many kilograms of rice costing Rs. 30/kg should be mixed with 40 kg of rice costing Rs. 45/kg, so that there will be a profit of 25% on selling the mixture at Rs. 50/kg?
a)
10 kg
b)
15 kg
c)
20 kg
d)
25 kg
|
|
Bayshore Academy answered |
Cost price of resultant rice = 50/1.25 = 40
5 : 10 = 1 : 2
Hence, Option C is correct.
5 : 10 = 1 : 2
Hence, Option C is correct.
500 gram spirit solution has 50% spirit in it. What quantity of spirit must be mixed with the solution to get a solution of 75% spirit?- a)200 grams
- b)250 grams
- c)320 grams
- d)500 grams
Correct answer is option 'D'. Can you explain this answer?
500 gram spirit solution has 50% spirit in it. What quantity of spirit must be mixed with the solution to get a solution of 75% spirit?
a)
200 grams
b)
250 grams
c)
320 grams
d)
500 grams
|
Ishaan Roy answered |
Given information:
- Initial solution has 500 grams with 50% spirit
- Final solution should have 75% spirit
Let x grams of spirit be added
Calculating the amount of spirit in the initial solution:
- Spirit in initial solution = 50% of 500 grams = 0.5 * 500 = 250 grams
Calculating the amount of spirit in the final solution:
- Spirit in final solution = 75% of (500 + x) grams
- Spirit in final solution = 0.75 * (500 + x) = 375 + 0.75x grams
Equating the amounts of spirit in the initial and final solutions:
- 250 = 375 + 0.75x
- 0.75x = 250 - 375
- 0.75x = 125
- x = 125 / 0.75
- x = 500 grams
Therefore, 500 grams of spirit must be mixed with the solution to get a solution of 75% spirit.
- Initial solution has 500 grams with 50% spirit
- Final solution should have 75% spirit
Let x grams of spirit be added
Calculating the amount of spirit in the initial solution:
- Spirit in initial solution = 50% of 500 grams = 0.5 * 500 = 250 grams
Calculating the amount of spirit in the final solution:
- Spirit in final solution = 75% of (500 + x) grams
- Spirit in final solution = 0.75 * (500 + x) = 375 + 0.75x grams
Equating the amounts of spirit in the initial and final solutions:
- 250 = 375 + 0.75x
- 0.75x = 250 - 375
- 0.75x = 125
- x = 125 / 0.75
- x = 500 grams
Therefore, 500 grams of spirit must be mixed with the solution to get a solution of 75% spirit.
There are two mixtures A and B of milk and water. The ratio of water to milk in Mixture A is 5 : 3 and the ratio of milk to water in Mixture B is 3 : 1. If 200 liters of both the mixtures are mixed, what is the percentage of water in the resultant mixture?- a)33.75
- b)36
- c)40
- d)43.75
Correct answer is option 'D'. Can you explain this answer?
There are two mixtures A and B of milk and water. The ratio of water to milk in Mixture A is 5 : 3 and the ratio of milk to water in Mixture B is 3 : 1. If 200 liters of both the mixtures are mixed, what is the percentage of water in the resultant mixture?
a)
33.75
b)
36
c)
40
d)
43.75
|
|
Bayshore Academy answered |
Hence, Option D is correct.
A total amount of Rs. 1200 is divided among 120 students. Each boy gets Rs. 8 and each girl gets Rs. 11. What is the number of boys?- a)30
- b)40
- c)50
- d)60
Correct answer is option 'B'. Can you explain this answer?
A total amount of Rs. 1200 is divided among 120 students. Each boy gets Rs. 8 and each girl gets Rs. 11. What is the number of boys?
a)
30
b)
40
c)
50
d)
60
|
|
Ssc Cgl answered |
Average amount each student gets
Boys : Girls = 1 : 2
Hence, Option B is correct.
Boys : Girls = 1 : 2
Hence, Option B is correct.
A mixture contains ‘X’ liters of milk and 20 liters of water and the price of the mixture is Rs. 25 per liter. If the price of pure milk is Rs. 30 per liter, what is the value of ‘X’?- a)100
- b)120
- c)125
- d)160
Correct answer is option 'A'. Can you explain this answer?
A mixture contains ‘X’ liters of milk and 20 liters of water and the price of the mixture is Rs. 25 per liter. If the price of pure milk is Rs. 30 per liter, what is the value of ‘X’?
a)
100
b)
120
c)
125
d)
160
|
|
EduRev SSC CGL answered |
Milk : Water= 25 : 5 = 5 : 1
Hence, Option A is correct.
Chapter doubts & questions for Mixtures & Alligations - Mathematics for RRB NTPC / ASM 2025 is part of RRB NTPC/ASM/CA/TA exam preparation. The chapters have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Mixtures & Alligations - Mathematics for RRB NTPC / ASM in English & Hindi are available as part of RRB NTPC/ASM/CA/TA exam.
Download more important topics, notes, lectures and mock test series for RRB NTPC/ASM/CA/TA Exam by signing up for free.
Mathematics for RRB NTPC / ASM
146 videos|96 docs|98 tests
|
Signup to see your scores go up within 7 days!
Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily