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The free energy change for the following cell reaction is given as :
2Au3+ (aq) + 3Cu (s) → 2Au (s) + 3Cu2+ (aq)
  • a)
    6 FE°cell
  • b)
    3 FE°cell
  • c)
    -2 FE°cell
  • d)
    -6 FE°cell
Correct answer is option 'D'. Can you explain this answer?

Preeti Iyer answered
The correct answer is Option D.
EO = EOCa2+/ Ca  -  EOAu2+/ Au
        = -2.87 - (1.50)
     = -2.87 - 1.50
     = -4.37 V
rGO = -nFEO
           = -6 FEO

In the equation, ΔG° = – nF E° cell ; F is:
  • a)
    Boltzmann constant
  • b)
    Faraday’s constant
  • c)
    Gas constant
  • d)
    Universal gas constant
Correct answer is option 'B'. Can you explain this answer?

Nandini Iyer answered
The correct answer is Option B.
The relationship between ΔGo and Eo is given by the following equation: ΔGo=−nFEo. Here, n is the number of moles of electrons and F is the Faraday constant.

 In an electrochemical cell, the electrode having a lower reduction potential will act as:
  • a)
    Salt bridge
  • b)
    Electrolyte
  • c)
    Anode
  • d)
    Cathode
Correct answer is option 'C'. Can you explain this answer?

Sargam Singh answered
A substance with lower reduction potential has more tendency to oxidize .in a electrochemical cell anode performs oxidation reaction hence the electrode will function as a anode

 Gibbs free energy change for a cell reaction is positive what does it indicates?
  • a)
    cell will discharge easily
  • b)
    Cell reaction is spontaneous
  • c)
    Cell reaction is non spontaneous
  • d)
    Cell will work under standard conditions
Correct answer is option 'C'. Can you explain this answer?

Rajeev Saxena answered
No, reaction cannot be spontaneous (continue to happen) when the change in gibbs free energy is positive. ... For a spontaneous process to happen , the change in Gibbs free energy must be negative. A roaring bonfire is an example of a spontaneous reaction.

During electrolysis, the reaction that takes place at cathode is:
  • a)
    Hydrolysis
  • b)
    Reduction
  • c)
    Oxidation
  • d)
    Neutralization
Correct answer is option 'B'. Can you explain this answer?

Rajat Patel answered
The electrode at which oxidation takes place is known as the anode, while the electrode at which reduction take place is called the cathode. If you see galvanic cell reduction take place at the left electrode, so the left one is the cathode. Oxidation takes place at the right electrode, so the right one is the anode.

For the following cell with hydrogen electrodes at two different  pressure pand p
 emf is given by
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?

Krishna Iyer answered
For SHE E°SHE = 0.00 V
Oxidation at anode (left)

Reduction at cathode (right) 
Net
This is the type of the cell in which electrodes at different pressures are dipped in same electrolyte and connectivity is made by a salt-bridge.
Reaction Quotient (Q) 
∵ 

 During electrolysis, the reaction that takes place at anode is:
  • a)
    Reduction
  • b)
    Neutralization
  • c)
    Hydrolysis
  • d)
    Oxidation
Correct answer is option 'D'. Can you explain this answer?

Rajat Patel answered
Oxidation takes place at the right electrode, so the right one is the anode. While in electrolytic cell reduction takes place at the right electrode, so right one is the cathode. Oxidation takes place at the left electrode, so the left one is the anode.

 At equilibrium:
  • a)
    Cell potential’ E cell‘ becomes zero
  • b)
    Equilibrium constant becomes equal to electrode potential
  • c)
    Equilibrium constant becomes zero
  • d)
    Cell potential ‘E cell‘ becomes unity
Correct answer is option 'A'. Can you explain this answer?

Ayush Joshi answered
E cell is 0 in equilibrium that is E cathode becomes equal to E anode ………. ... So E cell is zero at equilibrium that is when the E(cathode) becomes equal to E(anode). E deg cell is zero in the concentration cell when both the electrodes are of the same metal.

A concentration cell reversible to anion (Cl-) is set up
   
cell reaction is spontaneous ,if 
  • a)
    C1 > C2
  • b)
    C1 < C2
  • c)
    C1 = C2
  • d)
    C1 = 0
Correct answer is option 'A'. Can you explain this answer?

Om Desai answered
This is a type of concentration cell with gas electrodes at the same pressure (1 bar) but dipped in aqueous solution of different concentration. Hence, a potential difference is set up.
At anode 
At cathode



To make cell reaction spontaneous, Ecell > 0, hence C, > C2

If a salt bridge is removed between the half cells, the voltage
  • a)
    Decreases to zero
  • b)
    Increases
  • c)
    Increases rapidly
  • d)
    Do not change
Correct answer is option 'A'. Can you explain this answer?

Om Desai answered
The correct answer is Option A.
The purpose of a salt bridge is not to move electrons from the electrolyte, rather maintain charge balance because the electrons are moving from one-half cell to the other. The electrons flow from the anode to the cathode thus if a salt bridge is removed between the half cells, the voltage becomes zero.
 

"Maintenance-free" batteries now in use in place of commom batteries ,have
  • a)
    electrodes made of lead-lead oxide
  • b)
    electrodes made of calcium-containing lead alloy
  • c)
    non-aqueous solvents as medium
  • d)
    platinum electrodes
Correct answer is option 'B'. Can you explain this answer?

Nishtha Bose answered
In lead-acid storage battery, specific gravity of H2SO4 changes and water is to be added periodically. In maintenance free battery calcium-containing lead alloy that prevents the electrolytic decomposition of H2O. These batteries are sealed and no maintenance is required

 In a Daniel cell, the oxidation and reduction halves occur at:
  • a)
    copper and zinc electrodes respectively
  • b)
    zinc and copper electrodes respectively
  • c)
    both occur at copper electrode respectively
  • d)
    both occur at zinc electrode respectively
Correct answer is option 'B'. Can you explain this answer?

Ameya Pillai answered
The correct answer is option 'B': zinc and copper electrodes respectively.

Explanation:
A Daniel cell is an electrochemical cell that consists of two half-cells connected by a salt bridge. The two half-cells are the oxidation half-cell and the reduction half-cell.

1. Oxidation Half-Cell:
In the oxidation half-cell, oxidation occurs. This means that electrons are lost by the electrode material and transferred to the external circuit. In the Daniel cell, the zinc electrode is the site of oxidation. Zinc atoms lose two electrons to form Zn2+ ions:
Zn(s) → Zn2+(aq) + 2e-

2. Reduction Half-Cell:
In the reduction half-cell, reduction occurs. This means that electrons are gained by the electrode material from the external circuit. In the Daniel cell, the copper electrode is the site of reduction. Copper(II) ions from the copper sulfate solution in the reduction half-cell gain two electrons to form copper atoms:
Cu2+(aq) + 2e- → Cu(s)

3. Overall Cell Reaction:
The overall cell reaction can be obtained by combining the oxidation and reduction half-reactions. Since the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction, the two half-reactions can be added together to obtain the overall cell reaction:
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

4. Cell Diagram:
The cell diagram for a Daniel cell is represented as:
Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s)

In conclusion, in a Daniel cell, the oxidation half occurs at the zinc electrode and the reduction half occurs at the copper electrode. This allows for the flow of electrons from the zinc electrode to the copper electrode through the external circuit, generating an electric current.

Two half-cells are given
For a spontaneous cell reaction, cell set up is    
  • a)
    Ag| AgCI| KCI (0.2M) 11 KBr (0.001 M)| AgBr| Ag
  • b)
    Ag| AgBr| KBr (0.001 M) 11 KCI (0.2 M) | AgCI | Ag
  • c)
    Both (a) and (b)
  • d)
    None of the above
Correct answer is option 'A,B'. Can you explain this answer?

Riya Banerjee answered
Ksp (AgCI) = 2.8 x 10-10
[Ag+] [Cl-] = 2 .8 x 10-10
 
∴ [Ag+]left = 
Ksp (AgBr) = 3.3 x 10-12 
[Ag+][Br-] = 3.3 x 10-13
∴ [Ag+]left =  
Net
= -0.037 V
Thus, cell reaction is non-spontaneous
(b) Cell is reversed of (a), thus spontaneous.

. For an equation: Ni(s) + 2Ag+(aq) → Ni2+ (aq) + 2Ag(s) the Nernst equation is written as:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?

Riya Banerjee answered
The correct answer is Option A.
Oxidation: 
Ni(s) ---> Ni2+(aq) + 2e-
Reduction:
2Ni+(aq) + 2e- ----> 2Aq(s)
2e- are in the above reaction so;
         n = 2
We know that 
Ecell = Eocell – (RT/nF) lnKc
         = Eocell – (RT/nF) ln ([Ni]2+ / [Ag+]2

 In an electrochemical cell, the electrode having a higher reduction potential will act as:
  • a)
    salt bridge
  • b)
    Electrolyte
  • c)
    Anode
  • d)
    Cathode
Correct answer is option 'D'. Can you explain this answer?

Om Desai answered
The correct answer is option D.
Reduction potential refers to the voltage required to reduce a material under standard conditions. If a material has a higher reduction potential it takes more energy to reduce it than a lower reduction potential material. Therefore the higher reduction potential material is actually oxidized to reduce the lower reduction potential material.
Cathode- The electrode where reduction occurs and
The one with the highest reduction potential selected as the reduction half-reaction and therefore is cathode.

Select the correct statement(s).
  • a)
    In lead-storage battery,galvanic cell are linked in series
  • b)
    Cathode and anode compartments are not seperated in a battery as oxidant and reductant both are solids
  • c)
    Recharging of a storage battery is a non-spontaneous (ΔG° > 0)
  • d)
    All of the above
Correct answer is option 'D'. Can you explain this answer?

Kalyan Chavan answered
(a) A typical 12V battery consists of six cells connected in series each cell providing a potential of about 2V -correct
(b) No separation of cathodic and anodic compartment, species being in solid state -correct
(c) During recharging, E° < 0, thus ΔG° > 0-correct.

In the electrorefining of metals, impure metal is
  • a)
    cathode and oxidation taken place
  • b)
    anode and oxidation takes place
  • c)
    anode and reduction takes place
  • d)
    cathode and reduction takes place
Correct answer is option 'B'. Can you explain this answer?

Ameya Basu answered
Electrorefining of Metals:
In the electrorefining process, impure metal is purified through electrolysis.

Impure Metal as Anode:
- In electrorefining, the impure metal is attached to the anode.
- The anode undergoes oxidation, where the impurities present in the metal are oxidized and dissolve into the electrolyte.
- This leaves behind a more pure form of the metal at the cathode.
Therefore, the correct statement is:

Option B: Anode and oxidation takes place

A solution of copper(II) sulphate (VI) is electrolysed between copper electrodes by a currrent of 10.0 A for exactly 9650 s.Which remains unchanged?
  • a)
    Molar concentration of solution
  • b)
    Cathodic plate
  • c)
    Anodic plate
  • d)
    All of these
Correct answer is option 'A'. Can you explain this answer?

Ishani Patel answered

0.5 mole of copper is dissolved from the anode. Thus, its mass decreases. 0.5 mole of copper from the anode is deposited at the cathode. Thus, its mass increases.
Thus, molar concentration of aqueous solution of CuSO4 remains unchanged.

One or More than One Options Correct Type
This section contains 4 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
Q.
Select the correct statement(s).
  • a)
    If salt-bridge is removed,potentials falls to zero
  • b)
    Quinhydrone electrode is reversible to H+ ion
  • c)
    Liquid-junction potential developed across the boundary of the two solutions of different concentration is minimised if concentrations cell are used
  • d)
    Calomel electrode contains calcium chloride solution in contact with Pt electrode
Correct answer is option 'A,B,C'. Can you explain this answer?

a) If salt-bridge is removed, anodic and cathodic solution intermix and potential difference falls to zero — correct.

Quinhydrone is a mixture of A and S in (1:1) molar ratio joined by H-bonding. Above equilibrium is set up in aqueous solution.

If [H+] changes, EQH also changes. Thus, quinhydrone electrode is reversible to H+ ion correct
(c) Liquid junction potential is minimised by use of concentration cell— correct.
(d) Calomel electrode is Hg(/), Hg2Cl2 (s)| Cl-.
Thus, (d) is incorrect.

Select the correct observation about electrolysis.
  • a)
    Electric current is used to drive a non-spontaneous reaction
  • b)
    Ecell is positive and ΔG is negative
  • c)
    Cations and anions are discharged at the cathode and anode respectively
  • d)
    Overvoltage is responsible that a particular reaction takes place
Correct answer is option 'A,C,D'. Can you explain this answer?

Thus, electric current is used to carry out a non-spontaneous reaction.
Thus. (a) is correct.
(b) Since reactions are reverse of electrochemical cell, hence 
thus, (b) is incorrect
(c) cation goes to cathode and anion goes to anode and are discharged. Thus, correct
(d) some additional voltage called overvoltage is set up and thus other reactions also take place. thus correct

In the following batteries, alkaline electrolytes are used
I. Mercury
II. Nickel-cadmium
III. Modified Leclanche cell Cell potential is found to be independent of [OH-] in
  • a)
    I , II , III
  • b)
    I ,II
  • c)
    II , III
  • d)
    Only III
Correct answer is option 'A'. Can you explain this answer?

Upasana Sen answered
Mercury Battery:
- Mercury batteries, also known as mercuric oxide batteries, use a combination of mercuric oxide and zinc as the electrode materials.
- The electrolyte in mercury batteries is typically an alkaline electrolyte, which is a solution of potassium hydroxide (KOH) or sodium hydroxide (NaOH).
- The alkaline electrolyte facilitates the flow of ions between the electrodes, allowing the battery to generate an electric current.
- The cell potential of a mercury battery is not dependent on the concentration of hydroxide ions ([OH-]) in the electrolyte. Therefore, the cell potential remains constant regardless of the [OH-] concentration.

Nickel-Cadmium Battery:
- Nickel-cadmium batteries, also known as NiCd batteries, use nickel oxide hydroxide and metallic cadmium as the electrode materials.
- The electrolyte in NiCd batteries is typically an alkaline electrolyte, which is usually a solution of potassium hydroxide (KOH).
- Similar to mercury batteries, the alkaline electrolyte in NiCd batteries facilitates the flow of ions between the electrodes, allowing the battery to generate an electric current.
- The cell potential of a NiCd battery is also not dependent on the concentration of hydroxide ions ([OH-]) in the electrolyte. Therefore, the cell potential remains constant regardless of the [OH-] concentration.

Modified Leclanche Cell:
- The Leclanche cell is a type of primary battery that uses a zinc anode and a carbon cathode.
- In a modified Leclanche cell, the electrolyte is typically a paste made of ammonium chloride (NH4Cl) and zinc chloride (ZnCl2) dissolved in water.
- The cell potential of a modified Leclanche cell is not dependent on the concentration of hydroxide ions ([OH-]) in the electrolyte. Therefore, the cell potential remains constant regardless of the [OH-] concentration.

Overall Explanation:
- Alkaline electrolytes, such as solutions of potassium hydroxide (KOH) or sodium hydroxide (NaOH), are commonly used in different types of batteries to facilitate ion flow and enable the generation of electric current.
- In the case of mercury batteries, nickel-cadmium batteries, and modified Leclanche cells, alkaline electrolytes are used.
- The cell potential of these batteries is not affected by the concentration of hydroxide ions ([OH-]) in the electrolyte.
- Therefore, the cell potential remains constant regardless of the [OH-] concentration.
- As a result, the correct answer to the given question is option 'A' - I, II, III, meaning that all three types of batteries mentioned (mercury battery, nickel-cadmium battery, and modified Leclanche cell) use alkaline electrolytes and have a cell potential that is independent of [OH-] concentration.

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