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A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:
  • a)
    21 s
  • b)
    29 s
  • c)
    31 s
  • d)
    37 s
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
Displacement in first eight steps = (5 - 3) m = 2 m
Time taken for first eight steps = 8 s
Time taken by the drunkard to cover first 6 m of journey = 8/2 * 6 = 24 s
If the drunkard takes 5 steps more, he will fall into the pit. So the time taken by the drunkard to cover last five steps = 5 s
Total time taken = 24 s + 5 s = 29 s

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