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All questions of Alcohols for EmSAT Achieve Exam
Fermentation of Glucose to alcohol undergoes in presence of :- a)ZnO
- b)Cr2O3
- c)Invertase
- d)Zymase
Correct answer is option 'D'. Can you explain this answer?
Fermentation of Glucose to alcohol undergoes in presence of :
a)
ZnO
b)
Cr2O3
c)
Invertase
d)
Zymase
|
Lavanya Menon answered |
The correct answer is option D
Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and carbon dioxide. It occurs naturally in yeasts. Zymase activity varies among yeast strains. Zymase is also the brand name of the drug pancrelipase.
Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and carbon dioxide. It occurs naturally in yeasts. Zymase activity varies among yeast strains. Zymase is also the brand name of the drug pancrelipase.
Which alkene is obtained on dehydration of the following alcohol in the presence of H2SO4 ?
- a)
- b)
- c)
- d) None of the above
Correct answer is option 'B'. Can you explain this answer?
Which alkene is obtained on dehydration of the following alcohol in the presence of H2SO4 ?
a)
b)
c)
d)
None of the above
|
Mohit Rajpoot answered |
Carbonium ion formed in 1st step undergoes rearrangement to give tert. carbonium ion since tert-carbonium ions are more stable than secondary one.
Phenol is acidic due to resonance stabilization of its conjugate base :- a)O-H
- b)Benzyl alcohol
- c)Alkoxide ion
- d)Phenoxide ion
Correct answer is option 'D'. Can you explain this answer?
Phenol is acidic due to resonance stabilization of its conjugate base :
a)
O-H
b)
Benzyl alcohol
c)
Alkoxide ion
d)
Phenoxide ion
|
|
Rishika Patel answered |
Polarity of Phenol
Phenol, also known as benzenol or carbolic acid, is an aromatic compound that consists of a benzene ring bonded to a hydroxyl group (-OH). The presence of the hydroxyl group makes phenol a polar molecule because oxygen is more electronegative than carbon and hydrogen.
Acidity of Phenol
Phenol is considered an acid because it can donate a proton (H+) and form a conjugate base. The acidity of phenol is attributed to resonance stabilization of its conjugate base, the phenoxide ion.
Resonance Stabilization of Phenoxide Ion
When phenol loses a proton, it forms the phenoxide ion (C6H5O-). The phenoxide ion is resonance stabilized, which means that the negative charge can be delocalized over the entire ring system through resonance structures.
Resonance Structures of Phenoxide Ion
The resonance structures of the phenoxide ion can be represented as follows:
1. In the first resonance structure, the lone pair on the oxygen atom forms a double bond with carbon, while the negative charge is located on the oxygen atom.
2. In the second resonance structure, the lone pair on the oxygen atom forms a double bond with one of the carbon atoms in the ring, while the negative charge is located on that carbon atom.
3. In the third resonance structure, the lone pair on the oxygen atom forms a double bond with another carbon atom in the ring, while the negative charge is located on that carbon atom.
The resonance structures demonstrate that the negative charge of the phenoxide ion is delocalized over the entire ring system, resulting in stability.
Comparison with Other Options
a) O-H: The O-H bond in phenol is the source of acidity, but it does not explain the resonance stabilization of the conjugate base.
b) Benzyl alcohol: While benzyl alcohol also has an -OH group, it lacks the aromatic ring required for resonance stabilization of the conjugate base.
c) Alkoxide ion: Alkoxide ions are formed when an alcohol loses a proton, but they do not have the same resonance stabilization as the phenoxide ion.
Conclusion
The correct answer is option 'D' (Phenoxide ion) because the resonance stabilization of the phenoxide ion is responsible for the acidity of phenol. The delocalization of the negative charge over the aromatic ring system increases the stability of the conjugate base, making phenol acidic.
Phenol, also known as benzenol or carbolic acid, is an aromatic compound that consists of a benzene ring bonded to a hydroxyl group (-OH). The presence of the hydroxyl group makes phenol a polar molecule because oxygen is more electronegative than carbon and hydrogen.
Acidity of Phenol
Phenol is considered an acid because it can donate a proton (H+) and form a conjugate base. The acidity of phenol is attributed to resonance stabilization of its conjugate base, the phenoxide ion.
Resonance Stabilization of Phenoxide Ion
When phenol loses a proton, it forms the phenoxide ion (C6H5O-). The phenoxide ion is resonance stabilized, which means that the negative charge can be delocalized over the entire ring system through resonance structures.
Resonance Structures of Phenoxide Ion
The resonance structures of the phenoxide ion can be represented as follows:
1. In the first resonance structure, the lone pair on the oxygen atom forms a double bond with carbon, while the negative charge is located on the oxygen atom.
2. In the second resonance structure, the lone pair on the oxygen atom forms a double bond with one of the carbon atoms in the ring, while the negative charge is located on that carbon atom.
3. In the third resonance structure, the lone pair on the oxygen atom forms a double bond with another carbon atom in the ring, while the negative charge is located on that carbon atom.
The resonance structures demonstrate that the negative charge of the phenoxide ion is delocalized over the entire ring system, resulting in stability.
Comparison with Other Options
a) O-H: The O-H bond in phenol is the source of acidity, but it does not explain the resonance stabilization of the conjugate base.
b) Benzyl alcohol: While benzyl alcohol also has an -OH group, it lacks the aromatic ring required for resonance stabilization of the conjugate base.
c) Alkoxide ion: Alkoxide ions are formed when an alcohol loses a proton, but they do not have the same resonance stabilization as the phenoxide ion.
Conclusion
The correct answer is option 'D' (Phenoxide ion) because the resonance stabilization of the phenoxide ion is responsible for the acidity of phenol. The delocalization of the negative charge over the aromatic ring system increases the stability of the conjugate base, making phenol acidic.
The process of converting alkyl halides into alcohols involves_____________.- a)rearrangement reaction
- b)substitution reaction
- c)dehydrohalogenation reaction
- d)addition reaction
Correct answer is option 'B'. Can you explain this answer?
The process of converting alkyl halides into alcohols involves_____________.
a)
rearrangement reaction
b)
substitution reaction
c)
dehydrohalogenation reaction
d)
addition reaction
|
Gaurav Kumar answered |
Converstion of alcohol to alkyl halide is via substitution reaction.
When aryl halide is heated with 6-8% NaOH solution ,at 623 K under 300 atm pressure we get:- a)Phenol
- b)Benzyl ether
- c)Ethyl alcohol
- d)Cumene
Correct answer is option 'A'. Can you explain this answer?
When aryl halide is heated with 6-8% NaOH solution ,at 623 K under 300 atm pressure we get:
a)
Phenol
b)
Benzyl ether
c)
Ethyl alcohol
d)
Cumene
|
Divey Sethi answered |
The correct answer is Option A.
The aryl halide is heated with 6-8%. NaOH solution at 623K under 300 atm pressure 1) it gives sodium phenoxide 2) sodium phenoxide treated with HCl(acidification) then it gives phenol.
The aryl halide is heated with 6-8%. NaOH solution at 623K under 300 atm pressure 1) it gives sodium phenoxide 2) sodium phenoxide treated with HCl(acidification) then it gives phenol.
An ether is more volatile than an alcohol having the same molecular formula. This is due to- a)dipolar character of ethers
- b)alcohols having resonance structures
- c)inter-molecular hydrogen bonding in ethers
- d)inter-molecular hydrogen bonding in alcohols
Correct answer is option 'D'. Can you explain this answer?
An ether is more volatile than an alcohol having the same molecular formula. This is due to
a)
dipolar character of ethers
b)
alcohols having resonance structures
c)
inter-molecular hydrogen bonding in ethers
d)
inter-molecular hydrogen bonding in alcohols
|
|
Ashish Kumar Sahoo answered |
Inter molecular h bonding in alcohol makes its bond more stronger hence less volatile
What is the product formed when excess of ethanol reacts with concentrated sulphuric acid at 383 K and then the temperature of reaction mixture is increased to 443 K?- a)Ethene
- b)Ethyl hydrogen sulphate
- c)Ethyl chloride
- d)Ethoxy ethane
Correct answer is 'A'. Can you explain this answer?
What is the product formed when excess of ethanol reacts with concentrated sulphuric acid at 383 K and then the temperature of reaction mixture is increased to 443 K?
a)
Ethene
b)
Ethyl hydrogen sulphate
c)
Ethyl chloride
d)
Ethoxy ethane
|
EduRev Support answered |
Identify the alcohol or phenol from the following which is most soluble in water.
- a)CH3– OH
- b)CH(CH3)2 CH2O-H
- c)CH3(CH2)2CH2OH
- d)C6H5OH
Correct answer is option 'A'. Can you explain this answer?
Identify the alcohol or phenol from the following which is most soluble in water.
a)
CH3– OH
b)
CH(CH3)2 CH2O-H
c)
CH3(CH2)2CH2OH
d)
C6H5OH
|
Aryan answered |
As...the ...linear chain in alcohol increase ...the solubility decrease .....due to ....staeric + vanderwall force inreacse ...
- a)NaHCO3
- b)Na
- c)CH3MgBr
- d)NaOH
Correct answer is 'D'. Can you explain this answer?
|
Dishani Kulkarni answered |
Phenol forms salt with NaOH while a liphatic alcohols do not.
Identify the alcohol or phenol having a stronger acidic nature from the following.- a)CH3CH2OH
- b)C6H5OH
- c)CH3CHOHCH2CH3
- d)CH3CH2CH2CH2OH
Correct answer is option 'B'. Can you explain this answer?
Identify the alcohol or phenol having a stronger acidic nature from the following.
a)
CH3CH2OH
b)
C6H5OH
c)
CH3CHOHCH2CH3
d)
CH3CH2CH2CH2OH
|
|
Mohit Rajpoot answered |
- Phenol (C₆H₅OH) is more acidic than typical alcohols.
- This is due to the resonance stabilization of the phenoxide ion formed when phenol loses a hydrogen ion (H⁺).
- The negative charge on the oxygen atom in phenoxide ion is delocalized over the aromatic ring, increasing stability and acidity.
- In contrast, alcohols like ethanol (CH₃CH₂OH) do not have such resonance stabilization, making them less acidic.
- Therefore, phenol is the strongest acid among the given options.
- This is due to the resonance stabilization of the phenoxide ion formed when phenol loses a hydrogen ion (H⁺).
- The negative charge on the oxygen atom in phenoxide ion is delocalized over the aromatic ring, increasing stability and acidity.
- In contrast, alcohols like ethanol (CH₃CH₂OH) do not have such resonance stabilization, making them less acidic.
- Therefore, phenol is the strongest acid among the given options.
Which of the following statement is correct?- a)The -OH group in phenol is meta directing.
- b)The electron releasing groups increase the acidic character of phenols.
- c)Phenols are less acidic than aromatic alcohols.
- d)Boiling point of phenol is higher than that of toluene of comparable molecular mass.
Correct answer is option 'D'. Can you explain this answer?
Which of the following statement is correct?
a)
The -OH group in phenol is meta directing.
b)
The electron releasing groups increase the acidic character of phenols.
c)
Phenols are less acidic than aromatic alcohols.
d)
Boiling point of phenol is higher than that of toluene of comparable molecular mass.
|
|
Divey Sethi answered |
The correct answer is Option D.
Phenols have higher boiling point than toluene due to the presence of intermolecular hydrogen bonding in phenols. The formation of hydrogen bonds increases the intermolecular force of attraction between the phenol molecules and thereby increases its boiling point.
Can you explain the answer of this question below:The acidity of phenols is due to
- A:
Oxidation process
- B:
Resonance stabilization of its ions.
- C:
Hybridisation
- D:
Presence of O-H group
The answer is b.
The acidity of phenols is due to
Oxidation process
Resonance stabilization of its ions.
Hybridisation
Presence of O-H group
|
Rahul Bansal answered |
The acidity of phenols is due to its ability to lose hydrogen ion to form phenoxide ions. In a phenol molecule, the sp2hybridised carbon atom of benzene ring attached directly to the hydroxyl group acts as an electron withdrawing group. This sp2 hybridized carbon atom of benzene ring attached directly to the hydroxyl group has higher electronegativity in comparison to hydroxyl group. Due to the higher electronegativity of this carbon atom in comparison to the hydroxyl group attached, electron density decreases on oxygen atom. The decrease in electron density increases the polarity of O-H bond and results in the increase in ionization of phenols. Thus, the phenoxide ion is formed. The phenoxide ion formed is stabilized by the delocalization of negative charge due to the resonance in benzene ring. Phenoxide ion has greater stability than phenols, as in case of phenol charge separation takes place during resonance.The resonance structures of phenoxide ions explain the delocalization of negative charge. In case of substituted phenols, acidity of phenols increases in the presence of electron withdrawing group. This is due to the stability of the phenoxide ion generated. The acidity of phenols further increases if these groups are attached at ortho and para positions. This is due to the fact that the negative charge in phenoxide ion is mainly delocalized at ortho and para positions of the attached benzene ring. On the other hand, the acidity of phenols decreases in presence of electron donating groups as they prohibit the formation of phenoxide ion.
We can obtain picric acid from phenol by:- a)Sulphonation of phenol
- b)By Reimer Tiemann reaction
- c)Nitration of phenol
- d)Halogenation of phenol
Correct answer is option 'C'. Can you explain this answer?
We can obtain picric acid from phenol by:
a)
Sulphonation of phenol
b)
By Reimer Tiemann reaction
c)
Nitration of phenol
d)
Halogenation of phenol
|
Shreya Gupta answered |
Phenol heated with sulphuric acid gives phenol disulphonic acid, which further on reaction with nitric acid forms picric acid (2,4,6-trinitrophenol).
IUPAC name of m-cresol is ___________.- a)3-methylphenol
- b)3-chlorophenol
- c) 3-methoxyphenol
- d)benzene-1,3-diol
Correct answer is option 'A'. Can you explain this answer?
IUPAC name of m-cresol is ___________.
a)
3-methylphenol
b)
3-chlorophenol
c)
3-methoxyphenol
d)
benzene-1,3-diol
|
Preeti Iyer answered |
Meta-Cresol, also 3-methylphenol, is an organic compound with the formula CH3C6H4(OH). It is a colourless, viscous liquid that is used as an intermediate in the production of other chemicals. It is a derivative of phenol and is an isomer of p-cresol and o-cresol.
One or More than One Options Correct TypeDirection (Q. Nos. 9-14) This section contains 6 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correctConsider the following reaction,
Q. The expected substitution product(s) is/are- a)
- b)
- c)
- d)
Correct answer is option 'B,C'. Can you explain this answer?
One or More than One Options Correct Type
Direction (Q. Nos. 9-14) This section contains 6 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct
Consider the following reaction,
Q.
The expected substitution product(s) is/are
a)
b)
c)
d)
|
Om Desai answered |
Reaction proceeds by SN1 mechanism.
Above carbocations give the desired products.
Above carbocations give the desired products.
Product of above reaction is -- a)Enantiomer
- b)Racemic
- c)Diastereomers
- d)Meso
Correct answer is option 'C'. Can you explain this answer?
Product of above reaction is -
a)
Enantiomer
b)
Racemic
c)
Diastereomers
d)
Meso
|
Krishna Iyer answered |
HCl is formed in above reaction and react with pyridine and gives
Which catalyst is used in Fischer-Speier esterification?
- a)Concentrated H2SO4
- b)Dry HCl gas
- c)Concentrated HNO3
- d)Pyridine
Correct answer is option 'A'. Can you explain this answer?
Which catalyst is used in Fischer-Speier esterification?
a)
Concentrated H2SO4
b)
Dry HCl gas
c)
Concentrated HNO3
d)
Pyridine
|
|
Pooja Mehta answered |
Esterification is a relatively slow process at room temperature and does not proceed to completion. Concentrated sulfuric acid is used as a catalyst, and has a dual role: Speeds up the reaction. Acts as a dehydrating agent, forcing the equilibrium to the right and resulting in a greater yield of ester.
Phenols do not respond to which of these tests?- a)Schiff’s reagent test
- b)FeCl3 test
- c)Br2 water test
- d)Litmus test
Correct answer is option 'A'. Can you explain this answer?
Phenols do not respond to which of these tests?
a)
Schiff’s reagent test
b)
FeCl3 test
c)
Br2 water test
d)
Litmus test
|
|
Rajeev Saxena answered |
Phenols respond to all the above mentioned tests except Schiff’s reagent test, which is shown by aldehydes.
Which of the following compound reduces by NaBH4 ?- a)
- b)CH3–NO2
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
Which of the following compound reduces by NaBH4 ?
a)
b)
CH3–NO2
c)
d)
|
|
Suresh Iyer answered |
NaBH4 are weak reducing agent so only acid chloride are reduced in alcohal.
Phenol on treatment with Phthalic anhydride gives:- a)Phenolphthalein
- b)Salicylaldehyde
- c)Phthalic acid
- d)Salicylic acid
Correct answer is option 'A'. Can you explain this answer?
Phenol on treatment with Phthalic anhydride gives:
a)
Phenolphthalein
b)
Salicylaldehyde
c)
Phthalic acid
d)
Salicylic acid
|
Infinity Academy answered |
The correct answer is option A
Phenolphthalein gives pink colour with alkali.
Phenolphthalein gives pink colour with alkali.
Phenol can be distinguished from ethanol by the reactions with _________.
- a)Br2/water
- b)Na
- c)Neutral FeCl3
- d)A and C
Correct answer is option 'D'. Can you explain this answer?
Phenol can be distinguished from ethanol by the reactions with _________.
a)
Br2/water
b)
Na
c)
Neutral FeCl3
d)
A and C
|
Nisha Banerjee answered |
- Phenol can be distinguished from ethanol using Br2/water and Neutral FeCl3.
- Br2/water: Phenol reacts with bromine water to give a white precipitate of 2,4,6-tribromophenol, while ethanol does not react.
- Neutral FeCl3: Phenol forms a violet complex with neutral ferric chloride, whereas ethanol shows no color change.
- Therefore, options A and C are correct for distinguishing phenol from ethanol.
Isopropyl alcohol on oxidation forms:- a)Acetone
- b)Ether
- c)Acetaldehyde
- d)Methane
Correct answer is option 'A'. Can you explain this answer?
Isopropyl alcohol on oxidation forms:
a)
Acetone
b)
Ether
c)
Acetaldehyde
d)
Methane
|
|
Rahul Bansal answered |
The oxidation of isopropyl alcohol by potassium dichromate (K 2Cr 2O 7) gives acetone, the simplest ketone: Unlike aldehydes, ketones are relatively resistant to further oxidation, so no special precautions are required to isolate them as they form.
+ 4HIO4 →, Products obtained are
Which of the following compounds will react with sodium hydroxide solution in water?- a)C6H5OH
- b)C6H5CH2OH
- c)(CH3)3COH
- d)C2H5OH
Correct answer is option 'A'. Can you explain this answer?
Which of the following compounds will react with sodium hydroxide solution in water?
a)
C6H5OH
b)
C6H5CH2OH
c)
(CH3)3COH
d)
C2H5OH
|
Vijay Bansal answered |
When phenol reacts with sodium hydroxide solution it gives a colourless solution containing sodium phenoxide.
In this reaction, the hydrogen ion has been removed by the strongly basic hydroxide ion in the sodium hydroxide solution.
How many alcohols with molecular formula C4H10O are chiral in nature?a)2b)1c)4d)3Correct answer is option 'B'. Can you explain this answer?
|
Mansi Nair answered |
Here, again carbon is not chiral in nature.
So, only one alcohol is chiral in nature
So, only one alcohol is chiral in nature
An organic compound X is oxidised by using acidified K2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X is- a)CH3CH2OH
- b)CH3CHO
- c)(CH3)2CHOH
- d)None of the these
Correct answer is option 'C'. Can you explain this answer?
An organic compound X is oxidised by using acidified K2Cr2O7. The product obtained reacts with Phenyl hydrazine but does not answer silver mirror test. The possible structure of X is
a)
CH3CH2OH
b)
CH3CHO
c)
(CH3)2CHOH
d)
None of the these
|
|
Baby Ghosh answered |
Yup...it will be propan-2-ol..by oxidation it..it will convert into acetone and it reacts with phenyl hydrazine,it produces acetone phenyl hydrazone and there is no aldehyde grp in acetone. so it doesn't react in silver mirror test means with tollen's reagent..
(A)product (A) is -- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
(A)product (A) is -
a)
b)
c)
d)
|
|
Baby Ghosh answered |
According to Frice rearrangement...I think...
(a) + (b)
An alcohol has molecular formula C6H12O X and it gives immediate turbidity with cold, concentrated HCI even in the absence of ZnCI2. X can also be obtained by treatment of an ether with excess of CH3MgBr followed by acid hydrolysis. Hence, the correct statement regarding X is- a)It is 3-methyl-3-pentanol
- b)It is 2-methyl-3-pentanol
- c)It is 2-methyl-2-pentanol
- d)Either (b) or (c)
Correct answer is option 'C'. Can you explain this answer?
An alcohol has molecular formula C6H12O X and it gives immediate turbidity with cold, concentrated HCI even in the absence of ZnCI2. X can also be obtained by treatment of an ether with excess of CH3MgBr followed by acid hydrolysis. Hence, the correct statement regarding X is
a)
It is 3-methyl-3-pentanol
b)
It is 2-methyl-3-pentanol
c)
It is 2-methyl-2-pentanol
d)
Either (b) or (c)
|
Arpita Nair answered |
Only One Option Correct TypeDirection (Q. Nos. 1-8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.Q. Identify the final major product of the reaction sequence.
- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
Only One Option Correct Type
Direction (Q. Nos. 1-8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Identify the final major product of the reaction sequence.
a)
b)
c)
d)
|
Dr Manju Sen answered |
One Integer Value Correct TypeDirection (Q. Nos. 19-22) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).In the following reaction,
Q. How many different diols are formed as a result of nucleophilic addition reaction?
Correct answer is '3'. Can you explain this answer?
One Integer Value Correct Type
Direction (Q. Nos. 19-22) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
In the following reaction,
Q.
How many different diols are formed as a result of nucleophilic addition reaction?
|
|
Ritu Singh answered |
What is the correct structure for the major compound produced by the following reaction sequence?
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
What is the correct structure for the major compound produced by the following reaction sequence?
a)
b)
c)
d)
|
Gunjan Lakhani answered |
Reaction involves rearrangement of carbocation
Which of the following compound reduces by DIBAL-H ?- a)CH3–
–OH - b)
- c)CH3–
–O–Et - d)All
Correct answer is option 'D'. Can you explain this answer?
Which of the following compound reduces by DIBAL-H ?
a)
CH3––OH
–OHb)
c)
CH3––O–Et
–O–Etd)
All
|
Kiran Sanodiya answered |
Yes it can reduce ester ,acid n cyanide to corresponding aldehydes.
+CH3–O18H 
(X) + H2O
–O18–CH3 (Trans esterification)
–O18–CH3 (esterification reaction)
–O18–CH3(Saponification)
–O–CH3 (Hydrolysis)
Which reaction(s) given below gives dicarbonyl?
- a)
- b)
- c)
- d)
Correct answer is option 'A,D'. Can you explain this answer?
Which reaction(s) given below gives dicarbonyl?
a)
b)
c)
d)
|
|
Gunjan Lakhani answered |
Syn vicinal diols undergo oxidative cleavage with HIO4 giving diols, Option (b) and option (c) are anti diol and have restricted rotation.
;
Ph–
–O–CH3
Above reaction is known as -- a)Esterification
- b)saponification
- c)Transesterification
- d)Acidic hydrolysis
Correct answer is option 'B'. Can you explain this answer?
Ph––O–CH3
–O–CH3Above reaction is known as -
a)
Esterification
b)
saponification
c)
Transesterification
d)
Acidic hydrolysis
|
Nikita Singh answered |
Hydrolysis of ester in basic Medium is known as saponification.
are not react with NaOH.
(A) 
(B) 
(C)
–O–CH3 
—CH3 
; Product (A) is -
Which of the following is obtained as a major product in Friedel-Craft’s alkylation of phenol ?
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
Which of the following is obtained as a major product in Friedel-Craft’s alkylation of phenol ?
a)
b)
c)
d)
|
Sushil Kumar answered |
The correct answer is option A
P-methyl phenol is the major product.
P-methyl phenol is the major product.
Lucas test is associated with
- a)Phenols
- b)Aldehydes
- c)Carboxylic acid
- d)Alcohols
Correct answer is option 'D'. Can you explain this answer?
Lucas test is associated with
a)
Phenols
b)
Aldehydes
c)
Carboxylic acid
d)
Alcohols
|
|
Vijay Bansal answered |
- The Lucas test is used with alcohols to tell the difference between primary, secondary, and tertiary alcohols based on how they react with a special mixture known as Lucas reagent, which is made up of concentrated hydrochloric acid and zinc chloride.
- Tertiary alcohols react right away, creating a cloudy solution.
- Secondary alcohols take about 5 to 10 minutes to react, also forming a cloudy solution.
- Primary alcohols show very little to no reaction at room temperature.
- The test works because it leads to the creation of alkyl chloride, which does not mix well with water, making it easier to see the reactions.
The correct statement regarding 3-ethyl-3-hexanol is
- a)It changes colour of CrO3/H2SO4
- b)It is oxidised on heating with copper metal, producing ketone
- c)It gives yellow precipitate with NaOH/I2
- d)It changes colour of cerric nitrate [Ce(NO3)4] from yellow to r
Correct answer is option 'D'. Can you explain this answer?
The correct statement regarding 3-ethyl-3-hexanol is
a)
It changes colour of CrO3/H2SO4
b)
It is oxidised on heating with copper metal, producing ketone
c)
It gives yellow precipitate with NaOH/I2
d)
It changes colour of cerric nitrate [Ce(NO3)4] from yellow to r
|
Srestha Choudhury answered |
- 3-ethyl-3-hexanol is a tertiary alcohol. This characteristic influences its chemical behaviour:
- It does not oxidise easily. Therefore, it does not change the colour of CrO3/H2SO4.
- It does not produce a yellow precipitate with NaOH/I2, as this is a characteristic reaction of methyl ketones (Iodoform test).
- When heated with copper, it generally does not produce a ketone, as tertiary alcohols are resistant to oxidation.
- It changes the colour of cerric nitrate from yellow to red, which is a typical reaction for detecting alcohols in general, including tertiary alcohols.
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