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All questions of Comparing Quantities for Class 8 Exam

Find the amount when Rs. 10,800 for 3 years at 12.5% per annum compounded annually.
  • a)
    13,377.34
  • b)
    15377.343
  • c)
    14,377.34
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Given:
Rs. 10,800 for 3 years at 12.5% per annum is compounded annually. We have to find the final amount at the end of three years. This can be easily done as-
Substituting P = 10800, r = 12.5 and t = 3,

The total amount when Rs. 10,800 for 3 years at 12.5% per annum is compounded annually is Rs. 15377.343. This is the required answer.

An item marked at Rs 840 is sold for Rs 714. What is the discount %?
  • a)
    20%
  • b)
    10%
  • c)
    15%
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?

Amita Verma answered
 Given, marked price = 840
 selling price = 714
 We know that Discount = MP - SP
            = 840 - 714
            = 126.
  Discount% = 126/840 * 100
            = 15%.

Rohan bought a second hand refrigerator for Rs 2,500, then spent Rs 500 on its repairs and sold it for Rs 3,300. Find his loss or gain per cent.
  • a)
    Loss 15% 2a
  • b)
    Loss 10%
  • c)
    Profit 10%
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Aditi Saxena answered
Total money spent by sohan (C.P) 
= ₹2500 + ₹500 
= ₹3000 ( CP ) 

SP = ₹3300 

Hence, a gain as CP < SP 
Gain = ₹(3300-3000) = ₹300 
Gain% = 300/3000 x 100 = 10 % 

The price of a motor bike was Rs 60,000 last year. It has increased by 15% this year. What is the price now?
  • a)
    Rs 69,000
  • b)
    Rs 63,000
  • c)
    Rs 66,000
  • d)
    Rs 30,800
Correct answer is option 'A'. Can you explain this answer?

Garima Chauhan answered
Price of the motorbike last year: Rs 60,000
Increase in price this year: 15%

To find the price of the motorbike this year, we need to calculate the increase in price and add it to the price last year.

Calculation:
Step 1: Calculate the increase in price
Increase in price = (15/100) * 60,000 = Rs 9,000

Step 2: Add the increase in price to the price last year
Price this year = Price last year + Increase in price
Price this year = 60,000 + 9,000 = Rs 69,000

Therefore, the price of the motorbike this year is Rs 69,000.

Explanation:
The question states that the price of the motorbike last year was Rs 60,000. This is the base price. To find the price this year, we need to calculate the increase in price and add it to the base price.

The increase in price is given as 15%. To calculate the increase, we multiply the base price by the percentage increase. In this case, the increase is 15% of Rs 60,000, which is Rs 9,000.

To find the price this year, we add the increase in price to the base price. Adding Rs 9,000 to Rs 60,000 gives us Rs 69,000.

Therefore, the price of the motorbike this year is Rs 69,000.

Answer:
The price of the motorbike now is Rs 69,000 (Option A).

A trader marks his goods 30% above the cost price but makes a reduction of 25/4 on the marked price for ready money. What is his gain percent?
  • a)
    23.75
  • b)
    23.25
  • c)
    21.875
  • d)
    20
Correct answer is option 'C'. Can you explain this answer?

Gain % = (SP − CP)/CP
Let cost price be Rs. 100.
The MP is Rs. 130.
After discount of 6 1/4 %
the SP is Rs. 130(93.75/100)
= Rs. 121.875
Gain% = [(121.875 - 100)/100]*100
= 21.875​    
 

The population of a city was 30,000 in the year 2011. It increased at the rate of 5% p.a. Find the population at the end of the year 2013.
  • a)
    33000
  • b)
    24000
  • c)
    25000
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?

Geetika Shah answered
Population of the city in 2011 = 30,000
Percentage increased = 5%
Therefore 5% of 30,000 = 5/100 × 30,000 = 1,500
Population increased in 2 years = 1,500 × 2 = 3,000
Therefore population in 2013 = 30,000 + 3,000 = 33,000

A picnic is being planned in a school for Class VI. Girls are 40% of the total number of students and are 20 in number. Find the ratio of the number of girls to the number of boys in the class.
  • a)
    It is 2:1
  • b)
    It is 3:2
  • c)
    It is 2:3
  • d)
    It is 3:1
Correct answer is option 'C'. Can you explain this answer?

Rohit Sharma answered
Let the total no. of students be x.
No. of girls= 20
No. of boys = x-20
A. T. Q. ,
40% of x= 20
=> 40/100 × x = 20
=> x= 20× 100/40
=> x= 50
So, total no. of students = 50
No. of girls= 20
No. of boys = 50-20 = 30

Ratio of girls to boys = 20:30
= 20/30
=2/3
=2:3 

A shopkeeper purchased 300 bulbs for Rs 10 each. However 10 bulbs were fused and had to be thrown away. The remaining were sold at Rs 12 each. Find the gain or loss %.
  • a)
    15%
  • b)
    13%
  • c)
    16%
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?

Vivek Rana answered
Shopkeeper purchased 300 bulbs for ₹3000
If 10 bulbs were fused, the cost of 10 bulbs is ₹100
If he sell 290 bulbs as ₹12 each = 290×12 =3480
when he sell the the cost of each bulb as ₹12 he got ₹480 profit
As a percentage = 480÷3000×100=16
so he got 16% profit

The population of a city was 40,000 in the year 1999. It increased at the rate of 10% p.a. Find the population at the end of the year 2000.
  • a)
    35000
  • b)
    44000
  • c)
    40000
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Amit Kumar answered
Population of the city in 1999 = 40,000 Percentage increased = 10% Therefore 10% of 40,000 = 10/100 × 40,000 = 4,000 Population of the city in 2000 = 40,000 + 4,000 = 44,000

The C.I. on a certain sum for 2 years is Rs. 410 and S.I. is Rs. 400. What is the rate of interest per annum?
  • a)
    10%
  • b)
    8%
  • c)
    5%
  • d)
    4%
Correct answer is option 'C'. Can you explain this answer?

Kavya Saxena answered
Simple interest for 1 year =400/2=200
CI of 1 year =200
CI for 2nd year=410-200=210
For 2nd year Amount=210 and P=200
A = P (1+R/100)1
210 = 200(1+R/100)
R=5%

The sale price of a shirt is Rs.176. If a discount of 20% is allowed on its marked price, what is the marked price of the shirt?
  • a)
    Rs.160
  • b)
    Rs.180
  • c)
    Rs. 200
  • d)
    Rs. 220
Correct answer is option 'D'. Can you explain this answer?

Rohit Sharma answered
Let x be the marked price
We know
Marked price (Mp)= selling price+discount %of Mp
x=176+20%of x
x=176+0.2x 
x-0.2x=176
0.8x=176
x=176÷0.8
x=220
The marked price is Rs 220

A sum of money, at compound interest, yields Rs. 200 and Rs. 220 at the end of first and second years respectively. What is the rate percent?
  • a)
    20%
  • b)
    15%
  • c)
    10%
  • d)
    5%
Correct answer is option 'C'. Can you explain this answer?

Akshara Iyer answered
Step-by-step explanation:Step 1: Given DataLet r be rate of interestP is initial sumCompound Interest of first year is Rs 200Second year is Rs.220Step 

During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs 1450 and two shirts marked at Rs 850 each?
  • a)
    Rs 2,835
  • b)
    Rs 2,735
  • c)
    Rs 2,635
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Rohit Sharma answered
Given: MP (marked price) of 1 pair of jeans=₹1450
 
MP of 1 shirt= ₹850
 
Total Marked Price (MP) of a pair of jeans and two shirts

= 1450 + 2 x 850 = 3150
 
Total MP= ₹3150

Discount = Marked Price (MP) x % Discount

=3150 × (10/100)= ₹315

New Price After Discount = 3150 - 315 =₹ 2835
A customer would have to pay for a pair of jeans and two shirts =₹2835

Rohit bought a machine for Rs 20,000, then spent Rs 500 on its repairs and sold it for Rs 30,000. Find his loss or gain per cent.
  • a)
    Loss 30%
  • b)
    Profit 46.34%
  • c)
    Loss 50%
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?

Rohit Sharma answered
Cost price of washing machine = 20,000 + 5,00
= 20,500 Rs. 
Selling price = Rs. 30,000
Gain = S.P. - C.P. = 30,000 - 20,500
9,500 Rs. 
Therefore, Gain percent = (Gain * 100)/ C.P. 
= (9,500 * 100)/ 20,500
= 46.34% 

Sohan bought a washing machine for Rs 40,000, then spent Rs 5,000 on its repairs and sold it for Rs 50,000. Find his loss or gain per cent.
  • a)
    Loss 10%
  • b)
    Loss 20%
  • c)
    Profit 11.11%
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?

Vivek Rana answered
Cost price of washing machine = 40,000 + 5,000
= 45,000 Rs. 
Selling price = Rs. 50,000
Gain = S.P. - C.P. = 50,000 - 45,000
5,000 Rs. 
Therefore, Gain percent = (Gain * 100)/ C.P. 
= (5,000 * 100)/ 45,000
= 11.11% 

During a sale, a shop offered a discount of 10% on the marked price of all the items. What would a customer have to pay for a pair of jeans marked at ₹ 1450 and two shirts marked at ₹ 850 each?
  • a)
    Rs 2,635
  • b)
    Rs 2,835
  • c)
    Rs 2,735
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Sanjana Bose answered
Discount percentage = 10%
The marked price of a pair of jeans = ₹ 1450
Marked Price of a shirt = ₹ 850
(i) M.P. of a pair of jeans = C.P. of two jeans - Discount
(ii) M.P. of a shirt = C.P. of two shirts - Discount
Adding (i) and (ii) will give the amount he has to pay.
M.P of a pair of jeans = 1450
M.P of 2 shirts = 850 × 2 = 1700
Total M.P. = 1450 + 1700 = 3150
Discount on Total M.P =10% of 3150
= (10/100) × 3150
= 315
The amount customer has to pay is = Total M.P - Discount on total M.p
= 3150 - 315 = ₹ 2835

The difference in S.I. and C.I. on a certain sum of money in 2 years at 15% p.a. is Rs.144. Find the sum.
  • a)
    Rs. 6000
  • b)
    Rs. 6200
  • c)
    Rs. 6300
  • d)
    Rs. 6400
Correct answer is option 'D'. Can you explain this answer?

Krish Desai answered
Understanding S.I. and C.I.
When dealing with interest, it's important to distinguish between Simple Interest (S.I.) and Compound Interest (C.I.).
- Simple Interest (S.I.) is calculated on the principal amount only.
- Compound Interest (C.I.) is calculated on the principal plus any interest that has been added to it over previous periods.
Formulae for Calculation
- S.I. for 2 years:
S.I. = (Principal × Rate × Time) / 100
- C.I. for 2 years:
C.I. = Principal × (1 + Rate/100)^Time - Principal
Given Information
- Rate = 15% per annum
- Time = 2 years
- Difference between C.I. and S.I. = Rs. 144
Calculating S.I. and C.I.
1. Calculate S.I.:
- S.I. = (P × 15 × 2) / 100 = (30P) / 100 = 0.3P
2. Calculate C.I.:
- C.I. = P × (1 + 0.15)^2 - P
- C.I. = P × (1.3225) - P = 0.3225P
Finding the Difference
- The difference between C.I. and S.I. is given as Rs. 144:
0.3225P - 0.3P = Rs. 144
- This simplifies to:
0.0225P = Rs. 144
Finding the Principal (P)
- Now, solve for P:
P = Rs. 144 / 0.0225 = Rs. 6400
Conclusion
Thus, the sum of money is Rs. 6400, confirming that the correct answer is option 'D'.

________ means comparing two quantities.
  • a)
    Ratio
  • b)
    Proportion
  • c)
    Percent
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?

A ratio is a relationship between two numbers indicating how many times the first number contains the second.For example, if a bowl of fruit contains eight oranges and six lemons, then the ratio of oranges to lemons is eight to six (that is, 8:6, which is equivalent to the ratio 4:3). Similarly, the ratio of lemons to oranges is 6:8 (or 3:4) and the ratio of oranges to the total amount of fruit is 8:14 (or 4:7).

The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. Calculate the S.I. on the same sum for double the time at half the rate percent per annum.
  • a)
    Rs. 400
  • b)
    Rs. 500
  • c)
    Rs. 600
  • d)
    Rs. 800
Correct answer is option 'B'. Can you explain this answer?

Aditya Shah answered
Let the principal be 100x
First year interest = 10% = 10x
Second year interest =10% = 10/100 *110x =11x
Total interest = 21x
If interest is 21x , principal is 100x
If interest is Rs 525 , principal is = 525 /21x *100x = Rs 2500
Simple interest on Rs 2500 at 5% for 4 years is
2500 x 4 x 5/100= Rs500 

A shopkeeper purchased 500 pieces for Rs 20 each. However 50 pieces were spoiled in the way and had to be thrown away. The remaining were sold at Rs 25 each. Find the gain or loss %.
  • a)
    18%
  • b)
    15%
  • c)
    12.5%
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?

Sai Chopra answered
Given:
Number of pieces purchased = 500
Cost price per piece = Rs 20
Number of spoiled pieces = 50
Selling price per piece = Rs 25

To find: Gain or loss %

Solution:
1. Total cost price:
Cost price per piece * Number of pieces purchased = Rs 20 * 500 = Rs 10,000

2. Total selling price:
Number of remaining pieces = Number of pieces purchased - Number of spoiled pieces = 500 - 50 = 450
Selling price per piece * Number of remaining pieces = Rs 25 * 450 = Rs 11,250

3. Profit or loss:
Profit or loss = Total selling price - Total cost price = Rs 11,250 - Rs 10,000 = Rs 1,250

4. Gain or loss %:
Gain or loss % = (Profit or loss / Total cost price) * 100
= (1250 / 10000) * 100
= 12.5%

Therefore, the gain or loss percentage is 12.5%.

Hence, option C is the correct answer.

The price of a car was Rs 5,00,000 last year. It has increased by 10% this year. What is the price now?
  • a)
    Rs 4,40,000
  • b)
    Rs 5,50,000
  • c)
    Rs 3,00,800
  • d)
    Rs 3,00,400
Correct answer is option 'B'. Can you explain this answer?

Aditya Shah answered
As it was 5,00,000 initially, but now there is an increase of 10%.
so we calculate 10% of 5,00,000 that will be ₹50,000.
Then we have to calculate the new price of bike, (i.e. old + increased) = ₹5,00,000+₹50,000 = ₹5,50,000

The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find the population after 3 years.
  • a)
    29484
  • b)
    28696
  • c)
    24576
  • d)
    30184
Correct answer is option 'A'. Can you explain this answer?

EduRev Class 8 answered
Population after n years is calculated as:
Pn = P0 × (1 + r1) × (1 + r2) × (1 + r3)
Where:
  • P0 is the initial population,
  • r1, r2, r3 are the growth rates for each year.
Given:
  • Initial population P0 = 25000
  • Growth rates:
    • Year 1: 4% = 0.04
    • Year 2: 5% = 0.05
    • Year 3: 8% = 0.08
Now, we can calculate the population after each year:
Year 1:
Population after Year 1 = 25000 × (1 + 0.04) = 25000 × 1.04 = 26000
Year 2:
Population after Year 2 = 26000 × (1 + 0.05) = 26000 × 1.05 = 27300
Year 3:
Population after Year 3 = 27300 × (1 + 0.08) = 27300 × 1.08 = 29484

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