All Exams >
Class 10 >
Mathematics (Maths) Class 10 >
All Questions
All questions of Some Applications to Trigonometry for Class 10 Exam
If the length of a shadow cast by a pole is √3 times the length of the pole, then the angle of elevation of the sun is- a)45°
- b)60°
- c)30°
- d)90°
Correct answer is option 'C'. Can you explain this answer?
If the length of a shadow cast by a pole is √3 times the length of the pole, then the angle of elevation of the sun is
a)
45°
b)
60°
c)
30°
d)
90°
|
Anjana Khatri answered |
Consider the height of tower be h
∴ height of shadow =√3h .
In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30degree.
Therefore, angle of elevation is 30degree .
The upper part of a tree broken by the wind falls to the ground without being detached. The top of the broken part touches the ground at an angle of 30° at a point 8m from the foot of the tree. The original height of the tree is- a)8m
- b)24m
- c)24√3m
- d)8√3m
Correct answer is option 'D'. Can you explain this answer?
The upper part of a tree broken by the wind falls to the ground without being detached. The top of the broken part touches the ground at an angle of 30° at a point 8m from the foot of the tree. The original height of the tree is
a)
8m
b)
24m
c)
24√3m
d)
8√3m
|
Kiran Mehta answered |
If the angle of elevation of a cloud from a point 60 metres above a lake is 30o and the angle of depression of its reflection in the lake is 60°, then the height of the cloud above the lake is
- a)30 m
- b)120 m
- c)200 m
- d)500 m
Correct answer is option 'B'. Can you explain this answer?
If the angle of elevation of a cloud from a point 60 metres above a lake is 30o and the angle of depression of its reflection in the lake is 60°, then the height of the cloud above the lake is
a)
30 m
b)
120 m
c)
200 m
d)
500 m
|
Neha Patel answered |
Let AB be the surface of the lake and P be the point of observation such that AP = 60 m. Let C be the position of the cloud and C be its reflection in the lake.
Then CB =
Draw PM⊥CB
Let CM = h
∴ CB = h + 60 m
The angle of elevation of the top of a tower from a point on the ground and at a distance of 30m from its foot is 30°. The height of the tower is- a)30 m
- b)30√3 m
- c)10√3 m
- d)10 m
Correct answer is option 'C'. Can you explain this answer?
The angle of elevation of the top of a tower from a point on the ground and at a distance of 30m from its foot is 30°. The height of the tower is
a)
30 m
b)
30√3 m
c)
10√3 m
d)
10 m
|
Raghav Bansal answered |
Hence the height of the tower is 10√3 meters.
Two men are on opposite sides of a tower. They observe the angles of elevation of the top of the tower as 30° and 45° respectively. If the height of the tower is 100m, then the distance between them is- a)100(√3−1)m
- b)100(1−√3)m
- c)100(√3+1)m
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
Two men are on opposite sides of a tower. They observe the angles of elevation of the top of the tower as 30° and 45° respectively. If the height of the tower is 100m, then the distance between them is
a)
100(√3−1)m
b)
100(1−√3)m
c)
100(√3+1)m
d)
none of these
|
Kamna Science Academy answered |
The angles of elevation of the top of a tower from two points on the ground at distances 8m and 18m from the base of the tower and in the same straight line with it are complementary. The height of the tower is- a)8m
- b)16m
- c)12m
- d)18m
Correct answer is option 'C'. Can you explain this answer?
The angles of elevation of the top of a tower from two points on the ground at distances 8m and 18m from the base of the tower and in the same straight line with it are complementary. The height of the tower is
a)
8m
b)
16m
c)
12m
d)
18m
|
|
Mysterio Man answered |
Let AB= height of the tower=?,
and angle of elevations be ,
angle ACB =@ and angle ADB=90-@( as both the angles are complementary angles),
in right triangle ABC tan@=AB/BC,
tan@=AB/8---(1).,
in right triangle ABD tan(90-@)=AB/18,
we know that tan (90-@)=cot@,
so, cot@=AB/18,--(2),
Cot@=1/tan@,
from( 1)&(2),
AB/8=1/AB/18,
AB/8=18/AB,
AB²=18×8,
AB=√18×8=√3×3×2×2×2×2=3×2×2=12m
and angle of elevations be ,
angle ACB =@ and angle ADB=90-@( as both the angles are complementary angles),
in right triangle ABC tan@=AB/BC,
tan@=AB/8---(1).,
in right triangle ABD tan(90-@)=AB/18,
we know that tan (90-@)=cot@,
so, cot@=AB/18,--(2),
Cot@=1/tan@,
from( 1)&(2),
AB/8=1/AB/18,
AB/8=18/AB,
AB²=18×8,
AB=√18×8=√3×3×2×2×2×2=3×2×2=12m
The angle of elevation of the sun, when the length of the shadow of a tree is equal to the height of the tree, is:- a)45°
- b)60°
- c)30°
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
The angle of elevation of the sun, when the length of the shadow of a tree is equal to the height of the tree, is:
a)
45°
b)
60°
c)
30°
d)
None of these
|
|
Ananya Das answered |
Consider the diagram shown above where QR represents the tree and PQ represents its shadow
We have, QR = PQ
Let ∠QPR = θ
tan θ = QR/PQ = 1 (since QR = PQ)
⇒ θ = 45°
Let ∠QPR = θ
tan θ = QR/PQ = 1 (since QR = PQ)
⇒ θ = 45°
i,e., required angle of elevation = 45°
A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45o. Then the height (in meters) of the tower is- a)25
- b)25√3
- c)12.5
- d)25√2
Correct answer is option 'A'. Can you explain this answer?
A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45o. Then the height (in meters) of the tower is
a)
25
b)
25√3
c)
12.5
d)
25√2
|
Vikram Kapoor answered |
A point on the ground which is 25 m away from the foot of the tower i. BC= 25 m
Let the height of the tower be x
The angle of elevation of the tower is found to be 45 degree.i.e.∠ACB=45°
In ΔABC
Using trigonometric ratios
Hence the height of the tower is 25 m.
Hence the height of the tower is 25 m.
A 20 m long ladder touches the wall at a height of 10 m. The angle which the ladder makes with the horizontal is- a)450
- b)300
- c)900
- d)600
Correct answer is option 'B'. Can you explain this answer?
A 20 m long ladder touches the wall at a height of 10 m. The angle which the ladder makes with the horizontal is
a)
450
b)
300
c)
900
d)
600
|
|
Anjana Khatri answered |
ATQ , perpendicular /hypotenuse= 10/20
i.e sinθ = 10/ 20
sinθ= 1/2
so, sin 30 deg= 1/2
required angle = 30 Deg
Tree is broken by the wind the top struck the ground at 30° at a distance of 30m. away from the root. Find the height of the tree.
- a)45.9
- b)88.60
- c)54.63
- d) 51.96
Correct answer is option 'D'. Can you explain this answer?
Tree is broken by the wind the top struck the ground at 30° at a distance of 30m. away from the root. Find the height of the tree.
a)
45.9
b)
88.60
c)
54.63
d)
51.96
|
|
Neha Patel answered |
let ,
the height of standing part of the tree be = h
the height of fallen part (forms hypotenuse) be = x
then the total height of the tree will be = h + x
now,
tan 30 = h/30 m
1/√3 = h/30 m
30/√3 = h
⇒ h= 30/√3 m .... 1
similarly,
cos 30 = 30 m/ x
√3/2 = 30 / x
√3x = (30)2
√3x = 60 m
⇒ x = 60 / √3 m ....2
( we now have both value of h and x )
on adding equation1 & 2 :
⇒ h + x = 30 /√3 +60 /√3
=90 /√3 m
= 60√3 m
so , the total height of the tree is 60√3 m .
A man is standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60° and angle of depression of the base of the hill as 30°. What is the height of the hill?- a)
- b)24 m
- c)32 m
- d)
Correct answer is option 'C'. Can you explain this answer?
A man is standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60° and angle of depression of the base of the hill as 30°. What is the height of the hill?
a)
b)
24 m
c)
32 m
d)
|
|
Mubeena Akhter answered |
A tree casts a shadow 4 m long on the ground, when the angle of elevation of the sun is 45o. The height of the tree is:- a)5.2 m
- b)4 m
- c)3 m
- d)4.5 m
Correct answer is option 'B'. Can you explain this answer?
A tree casts a shadow 4 m long on the ground, when the angle of elevation of the sun is 45o. The height of the tree is:
a)
5.2 m
b)
4 m
c)
3 m
d)
4.5 m
|
|
Nisha Choudhury answered |
In a triangle with one angle being 90 degrees (which the tree makes with the ground) and the other being 45 degrees (the angle of elevation), the 3rd angle is bound to be 45 degrees (180 - 90 - 45 = 45).
We also know that sides opposite to equal angles are equal.
Hence, the height of the tree will also be 4m.
Let AC be the rope whose length is 20 m, and AB be the vertical pole of height h m and the angle of elevation of A at point C on the ground is 30°.
- a)10 m
- b)21 m
- c)19 m
- d)17 m
Correct answer is option 'A'. Can you explain this answer?
Let AC be the rope whose length is 20 m, and AB be the vertical pole of height h m and the angle of elevation of A at point C on the ground is 30°.
a)
10 m
b)
21 m
c)
19 m
d)
17 m
|
|
Ananya Das answered |
Fif. 9.11
i.e., ∠ACB = 30°
In right triangle ABC, we have
Hence, the height of the pole is 10 m.
The ___________ of an object is the angle formed by the line of sight with the horizontal when the object is below the horizontal level.- a)line of sight
- b)angle of elevation
- c)angle of depression
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
The ___________ of an object is the angle formed by the line of sight with the horizontal when the object is below the horizontal level.
a)
line of sight
b)
angle of elevation
c)
angle of depression
d)
none of these
|
|
Silent Nisarg answered |
Angel of deppression
An observer 1.5 m tall is 28.5 m away from a tower. The angle of elevation of the top of the tower from his eyes is 45°. The height of the tower is- a)10 m
- b)40 m
- c)30 m
- d)20 m
Correct answer is option 'C'. Can you explain this answer?
An observer 1.5 m tall is 28.5 m away from a tower. The angle of elevation of the top of the tower from his eyes is 45°. The height of the tower is
a)
10 m
b)
40 m
c)
30 m
d)
20 m
|
Nk Classes answered |
To solve for the height of the tower, we use the tangent function. The angle of elevation is 45°, and the horizontal distance from the observer to the tower is 28.5 m.
Let the height of the tower be h. The observer's eye level is 1.5 m, so the difference in height between the top of the tower and the observer's eyes is h−1.5h.
An electric pole is tied from the top to a point (some distance away from the base) on the ground using a string. The ratio of the height of pole to the string is √3 : 2, then the angle of elevation of the top from the point on the ground is- a)30°
- b)45°
- c)60°
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
An electric pole is tied from the top to a point (some distance away from the base) on the ground using a string. The ratio of the height of pole to the string is √3 : 2, then the angle of elevation of the top from the point on the ground is
a)
30°
b)
45°
c)
60°
d)
none of these
|
EduRev Class 10 answered |
The horizontal distance between two towers is 140 m. The angle of elevation of the top of the first tower when seen from the top of the second tower is 30o. If the height of the second tower is 60 m then, the height of the first tower is- a)140.83 m
- b)135 m
- c)139.5 m
- d)142 m
Correct answer is option 'A'. Can you explain this answer?
The horizontal distance between two towers is 140 m. The angle of elevation of the top of the first tower when seen from the top of the second tower is 30o. If the height of the second tower is 60 m then, the height of the first tower is
a)
140.83 m
b)
135 m
c)
139.5 m
d)
142 m
|
|
Amit Sharma answered |
The second tower is smaller than the first tower so let the height of the first tower is h So a part of it is equal to 60m so the remaining height is h-60 m
Tan 30=perpendicular/base
Tan 30=perpendicular/base
If the shadow of a boy ‘x’ metres high is 1.6m and the angle of elevation of the sun is 45°, then the value of ‘x’ is- a)2m
- b)0.8m
- c)3.6m
- d)1.6m
Correct answer is option 'D'. Can you explain this answer?
If the shadow of a boy ‘x’ metres high is 1.6m and the angle of elevation of the sun is 45°, then the value of ‘x’ is
a)
2m
b)
0.8m
c)
3.6m
d)
1.6m
|
|
Nk Classes answered |
The given information indicates:
- Height of the boy = x meters
- Shadow length = 1.6 meters
- Angle of elevation = 45 degrees
Using the trigonometric relation for a 45 degree angle
Substitute the values:
Thus, the height of the boy is 1.6 meters.
A tree is broken by wind and its upper part touches the ground at a point 10 metres from the foot of the tree and makes an angle of 45° with the ground. The entire length of the tree is- a)20 m
- b)10(1+√2)m
- c)10 m
- d)10√2 m
Correct answer is option 'B'. Can you explain this answer?
A tree is broken by wind and its upper part touches the ground at a point 10 metres from the foot of the tree and makes an angle of 45° with the ground. The entire length of the tree is
a)
20 m
b)
10(1+√2)m
c)
10 m
d)
10√2 m
|
|
Drishti Kumari answered |
Base = 10m
Angle of elevation = 45 degree
tan 45 ^ = P / b ( Let p supoose h )
1= h / 10
h = 10 m
height of half tree = 10 m
Now the length of broken part i.e, hypotenuse
H^2 = P ^2 + B ^2
H ^2 = 10^2 + 10 ^2
H ^2 = 100 +100
H = root under 100
H = 10 root 2
Hence , the length of entire tree = 10 + 10 root2
10 ( 1 + root 2 )
That's why B is the correct optipn .
Angle of elevation = 45 degree
tan 45 ^ = P / b ( Let p supoose h )
1= h / 10
h = 10 m
height of half tree = 10 m
Now the length of broken part i.e, hypotenuse
H^2 = P ^2 + B ^2
H ^2 = 10^2 + 10 ^2
H ^2 = 100 +100
H = root under 100
H = 10 root 2
Hence , the length of entire tree = 10 + 10 root2
10 ( 1 + root 2 )
That's why B is the correct optipn .
If the shadow of a tower is 30m long, when the sun’s elevation is 30°. The length of the shadow, when the sun’s elevation is 60°is- a)10m
- b)20m
- c)30m
- d)40m
Correct answer is option 'A'. Can you explain this answer?
If the shadow of a tower is 30m long, when the sun’s elevation is 30°. The length of the shadow, when the sun’s elevation is 60°is
a)
10m
b)
20m
c)
30m
d)
40m
|
Bhavya Banerjee answered |
Therefore, the length of the shadow is 10m long.
If the length of a shadow of a tower is increasing, then the angle of elevation of the sun is- a)neither increasing nor decreasing
- b)decreasing
- c)increasing
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
If the length of a shadow of a tower is increasing, then the angle of elevation of the sun is
a)
neither increasing nor decreasing
b)
decreasing
c)
increasing
d)
none of these
|
|
Nk Classes answered |
As the length of the shadow of a tower increases, the sun moves closer to the horizon. This means the angle of elevation of the sun decreases because the angle between the line of sight to the sun and the ground becomes smaller.
Thus, the angle of elevation is decreasing.
If the altitude of the sun is 60°, the height of a tower which casts a shadow of length 90m is- a)60m
- b)90m
- c)60√3m
- d)90√3m
Correct answer is option 'D'. Can you explain this answer?
If the altitude of the sun is 60°, the height of a tower which casts a shadow of length 90m is
a)
60m
b)
90m
c)
60√3m
d)
90√3m
|
|
Kamna Science Academy answered |
We are given:
- Angle of elevation (θ) = 60 degree
- Shadow length (L) = 90 m
- Height of the tower (h) needs to be calculated.
The relationship between the height of the tower (h) and the shadow length (L) is given by:
A man is standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60° and angle of depression of the base of the hill as 30°. What is the height of the hill?- a)24√3 m
- b)24 m
- c)8√3 m
- d)32 m
Correct answer is option 'D'. Can you explain this answer?
A man is standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60° and angle of depression of the base of the hill as 30°. What is the height of the hill?
a)
24√3 m
b)
24 m
c)
8√3 m
d)
32 m
|
|
Mysterio Man answered |
A kite is flying at a height of 200m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 45°. The length of the string, assuming that there is no slack in the string is- a)100m
- b)200m
- c)100√2m
- d)200√2m
Correct answer is option 'D'. Can you explain this answer?
A kite is flying at a height of 200m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 45°. The length of the string, assuming that there is no slack in the string is
a)
100m
b)
200m
c)
100√2m
d)
200√2m
|
|
Madhavan Choudhury answered |
Degrees.
To find the length of the string, we can use trigonometry.
Let's call the length of the string "x". We can use the tangent function to find x:
tan(45) = opposite/adjacent
tan(45) = 200/x
Now we can solve for x:
x = 200/tan(45)
Using a calculator, we find:
x ≈ 200
Therefore, the length of the string is approximately 200 meters.
To find the length of the string, we can use trigonometry.
Let's call the length of the string "x". We can use the tangent function to find x:
tan(45) = opposite/adjacent
tan(45) = 200/x
Now we can solve for x:
x = 200/tan(45)
Using a calculator, we find:
x ≈ 200
Therefore, the length of the string is approximately 200 meters.
If the angles of depression from the top of a tower of height 40 m to the top and bottom of a tree are 45° and 60° respectively, then the height of the tree is- a)
- b)
- c)
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
If the angles of depression from the top of a tower of height 40 m to the top and bottom of a tree are 45° and 60° respectively, then the height of the tree is
a)
b)
c)
d)
None of the above
|
|
EduRev Class 10 answered |
A tower of height 40 m is given, and the angles of depression from the top of the tower to:
- The top of the tree = 45°
- The bottom of the tree = 60°
We need to find the height of the tree (h).
Step 1: Use trigonometry for the angles of depression
Let:
Let:
- The distance between the base of the tower and the base of the tree = d
- The height of the tree = h
From the 45° angle (to the top of the tree):
The formula is:
tan(45°) = (Height of the tower - Height of the tree) / Distance (d)
Since tan(45°) = 1:
1 = (40 - h) / d
d = 40 - h (1)
From the 60° angle (to the bottom of the tree):
The formula is:
tan(60°) = Height of the tower / Distance (d)
Since tan(60°) = √3:
√3 = 40 / d
d = 40 / √3 (2)
Step 2: Solve the equations
Equate d from equations (1) and (2):
40 - h = 40 / √3
Rearrange to solve for h:
h = 40 - (40 / √3)
Rationalize the denominator:
h = 40 - (40√3 / 3)
h = (120 / 3) - (40√3 / 3)
h = (40 (3 - √3)) / 3
The height of the tree is:
b) (40 / 3) (3 - √3)
A kite is flying at a height of 90m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. The length of the string, assuming that there is no slack in the string is- a)45m
- b)60m
- c)60√3m
- d)90√3m
Correct answer is option 'C'. Can you explain this answer?
A kite is flying at a height of 90m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. The length of the string, assuming that there is no slack in the string is
a)
45m
b)
60m
c)
60√3m
d)
90√3m
|
|
Nk Classes answered |
We are given:
- Height of the kite (h) = 90 m
- Angle of inclination (θ) = 60°
- The length of the string (L) is the hypotenuse of the right triangle formed.
From a point P on the level ground, the angle of elevation of the top of a tower is 30°. If the tower is 100m high, the distance between P and the foot of the tower is- a)100√3m
- b)200√3m
- c)300√3m
- d)150√3m
Correct answer is option 'A'. Can you explain this answer?
From a point P on the level ground, the angle of elevation of the top of a tower is 30°. If the tower is 100m high, the distance between P and the foot of the tower is
a)
100√3m
b)
200√3m
c)
300√3m
d)
150√3m
|
Keerthana Singh answered |
Let QR be the height of the tower, then QR = 100 mQ And angle of elevation of the top of the tower be ∠PPR = 30°
Therefore, the distance between P and the foot of the tower is 100√3 metres.
A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. If the angle made by the rope with the ground level is 45°, then the height of the pole is- a)20m
- b)10√2m
- c)15√2m
- d)20√2m
Correct answer is option 'C'. Can you explain this answer?
A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. If the angle made by the rope with the ground level is 45°, then the height of the pole is
a)
20m
b)
10√2m
c)
15√2m
d)
20√2m
|
|
EduRev Class 10 answered |
The height of the pole is 15√2 m.
If the length of the shadow of a tower is √3 times that of its height, then the angle of elevation of the sun is- a)30°
- b)45°
- c)60°
- d)75°
Correct answer is option 'A'. Can you explain this answer?
If the length of the shadow of a tower is √3 times that of its height, then the angle of elevation of the sun is
a)
30°
b)
45°
c)
60°
d)
75°
|
|
Ananya Das answered |
Let AB be the tree and AP be the shadow.
Let AB = x meters. Then AP = x√3 meters
Also ∠APB = θ
In right angled triangle ABP
Let AB = x meters. Then AP = x√3 meters
Also ∠APB = θ
In right angled triangle ABP
Therfore the angle of elevation of the Sun is 30°.
From a point on the ground which is 15m away from the foot of a tower, the angle of elevation is found to be 60°. The height of the tower is- a)10m
- b)15√3m
- c)10√3m
- d)20√3m
Correct answer is option 'B'. Can you explain this answer?
From a point on the ground which is 15m away from the foot of a tower, the angle of elevation is found to be 60°. The height of the tower is
a)
10m
b)
15√3m
c)
10√3m
d)
20√3m
|
Anisha Basak answered |
Let the height of the tower be h meters.
In triangle AOB tan 60° = AB/OA
Therfore the height of the tower is 15√3 meters
A bridge across a river makes an angle of 45° with the river bank. If the length of the bridge across the river is 200m, then the breadth of the river is- a)100m
- b)200m
- c)100√2m
- d)200√2m
Correct answer is option 'C'. Can you explain this answer?
A bridge across a river makes an angle of 45° with the river bank. If the length of the bridge across the river is 200m, then the breadth of the river is
a)
100m
b)
200m
c)
100√2m
d)
200√2m
|
Neha Sharma answered |
A bridge across a river makes an angle of 45 with the river bank. If the length of the bridge across the river is 150 m, then find the width of the river.
A contractor planned to install a slide for the children to play in a park. If he prefers to have a slide whose top is at a height of 1.5m and is inclined at an angle of 30° to the ground, then the length of the slide would be- a)1.5m
- b)2√3m
- c)√3m
- d)3m
Correct answer is option 'D'. Can you explain this answer?
A contractor planned to install a slide for the children to play in a park. If he prefers to have a slide whose top is at a height of 1.5m and is inclined at an angle of 30° to the ground, then the length of the slide would be
a)
1.5m
b)
2√3m
c)
√3m
d)
3m
|
|
Nk Classes answered |
We are given:
- Height of the slide: h=1.5 m
- Angle of inclination: θ=30
- We need to find the length of the slide (l).
The relationship between the height (h), the length of the slide (l), and the angle of inclination (θ) is given by:
The length of the slide is 3 m.
If the length of the shadow of a tower is equal to its height, then the angle of elevation of the sun is- a)30°
- b)45°
- c)60°
- d)65°
Correct answer is option 'B'. Can you explain this answer?
If the length of the shadow of a tower is equal to its height, then the angle of elevation of the sun is
a)
30°
b)
45°
c)
60°
d)
65°
|
Om Khanna answered |
Let AB be the tower and AC be its shadow
And AB = AC= x m
Let the angle of elevation of the sun be θ.
Then ∠ACB = θ
In right angled triangle ABC
Therefore, the angle of elevation of the Sun is 45°.
A tower stands vertically on the ground. From a point C on the ground, which is 20 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45 degrees. The height of the tower is
- a)15 m
- b)8 m
- c)20 m
- d)10 m
Correct answer is option 'C'. Can you explain this answer?
A tower stands vertically on the ground. From a point C on the ground, which is 20 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45
degrees
. The height of the tower isa)
15 m
b)
8 m
c)
20 m
d)
10 m
|
|
Rohan Kapoor answered |
Angle of elevation =45 degrees
Base=20 m
Height of the tower=perpendicular
We have tan 45=P/B
1=P/20
P=20 m
Hence the height of the tower is 20 metres.
Base=20 m
Height of the tower=perpendicular
We have tan 45=P/B
1=P/20
P=20 m
Hence the height of the tower is 20 metres.
Chapter doubts & questions for Some Applications to Trigonometry - Mathematics (Maths) Class 10 2025 is part of Class 10 exam preparation. The chapters have been prepared according to the Class 10 exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Class 10 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Some Applications to Trigonometry - Mathematics (Maths) Class 10 in English & Hindi are available as part of Class 10 exam.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Mathematics (Maths) Class 10
127 videos|584 docs|79 tests
|
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup