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A tree is broken by wind and its upper part touches the ground at a point 10 metres from the foot of the tree and makes an angle of 45° with the ground. The entire length of the tree is
- a)20 m
- b)10(1+√2)m
- c)10 m
- d)10√2 m
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A tree is broken by wind and its upper part touches the ground at a po...
Base = 10m
Angle of elevation = 45 degree
tan 45 ^ = P / b ( Let p supoose h )
1= h / 10
h = 10 m
height of half tree = 10 m
Now the length of broken part i.e, hypotenuse
H^2 = P ^2 + B ^2
H ^2 = 10^2 + 10 ^2
H ^2 = 100 +100
H = root under 100
H = 10 root 2
Hence , the length of entire tree = 10 + 10 root2
10 ( 1 + root 2 )
That's why B is the correct optipn .
Angle of elevation = 45 degree
tan 45 ^ = P / b ( Let p supoose h )
1= h / 10
h = 10 m
height of half tree = 10 m
Now the length of broken part i.e, hypotenuse
H^2 = P ^2 + B ^2
H ^2 = 10^2 + 10 ^2
H ^2 = 100 +100
H = root under 100
H = 10 root 2
Hence , the length of entire tree = 10 + 10 root2
10 ( 1 + root 2 )
That's why B is the correct optipn .
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Community Answer
A tree is broken by wind and its upper part touches the ground at a po...
° with the ground. The height of the tree before it was broken is:
Let's call the height of the tree "h". We can use the tangent function to find h:
tan(45°) = h/10
h = 10 tan(45°)
h ≈ 10 meters
Therefore, the height of the tree before it was broken was approximately 10 meters.
Let's call the height of the tree "h". We can use the tangent function to find h:
tan(45°) = h/10
h = 10 tan(45°)
h ≈ 10 meters
Therefore, the height of the tree before it was broken was approximately 10 meters.
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A tree is broken by wind and its upper part touches the ground at a point 10 metres from the foot of the tree and makes an angle of 45° with the ground. The entire length of the tree isa)20 mb)10(1+√2)mc)10 md)10√2 mCorrect answer is option 'B'. Can you explain this answer?
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