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From a point on the ground which is 15m away from the foot of a tower, the angle of elevation is found to be 60°. The height of the tower is
- a)10m
- b)15√3m
- c)10√3m
- d)20√3m
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
From a point on the ground which is 15m away from the foot of a tower,...
Let the height of the tower be h meters.
In triangle AOB tan 60° = AB/OA
Therfore the height of the tower is 15√3 meters
Most Upvoted Answer
From a point on the ground which is 15m away from the foot of a tower,...
°. Find the height of the tower.
We can use trigonometry to solve this problem. Let's draw a diagram:
```
/|
/ |
h / | 15m
/ |
/θ___|
15m
```
We want to find the value of h, the height of the tower. We know that the angle of elevation is 60°, which means that the angle θ in the triangle is 30° (since the two angles add up to 90°). We can use the tangent function to find h:
```
tan(30°) = h/15m
h = 15m * tan(30°)
h = 8.66m (rounded to two decimal places)
```
Therefore, the height of the tower is approximately 8.66 meters.
We can use trigonometry to solve this problem. Let's draw a diagram:
```
/|
/ |
h / | 15m
/ |
/θ___|
15m
```
We want to find the value of h, the height of the tower. We know that the angle of elevation is 60°, which means that the angle θ in the triangle is 30° (since the two angles add up to 90°). We can use the tangent function to find h:
```
tan(30°) = h/15m
h = 15m * tan(30°)
h = 8.66m (rounded to two decimal places)
```
Therefore, the height of the tower is approximately 8.66 meters.
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Community Answer
From a point on the ground which is 15m away from the foot of a tower,...
15√3 m
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From a point on the ground which is 15m away from the foot of a tower, the angle of elevation is found to be60°. The height of the tower isa)10mb)15√3mc)10√3md)20√3mCorrect answer is option 'B'. Can you explain this answer?
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