All Exams  >   Electrical Engineering (EE)  >   Electrical Machines  >   All Questions

All questions of Electromechanical Energy Conversion Principles for Electrical Engineering (EE) Exam

In a doubly excited magnetic systems, the magnetic torques and forces act in such a direction as to tend to ___________
  • a)
    decrease the field energy at constant currents
  • b)
    decrease the field co-energy at constant currents
  • c)
    increase the field energy at constant currents
  • d)
    none of the mentioned
Correct answer is option 'C'. Can you explain this answer?

Sanvi Kapoor answered
Te = ∂Wfld(is,irr)/∂θr = ∂Wfld1(is,irr)/∂θr
fe = ∂Wfld(is,ir,x)/∂x = ∂Wfld1(is,ir,x)/∂x
The positive sign in the formula indicates that force/torque acts in a direction as to tend to increase both field energy and co-energy.

The electromagnetic force and/or torque, developed in any physical system, acts in such a direction as to tend to ____________
  • a)
    decrease the magnetic stored energy at constant mmf
  • b)
    decrease the magnetic stored energy at constant flux
  • c)
    increase the magnetic stored energy at constant flux
  • d)
    increase the magnetic stored energy at constant current
Correct answer is option 'B'. Can you explain this answer?

Aman Datta answered
Explanation:

The electromagnetic force and torque are developed in any physical system due to the interaction between magnetic fields and electric currents. These forces and torques can act in different directions depending on the specific configuration of the system. However, in this particular scenario, we are considering the effect of these forces and torques on the magnetic stored energy.

Understanding magnetic stored energy:

Magnetic stored energy refers to the energy stored in a magnetic field. It is proportional to the square of the magnetic flux and inversely proportional to the permeability of the medium. When current flows through a conductor, it creates a magnetic field around it, and this magnetic field stores energy.

The effect of electromagnetic force and torque on magnetic stored energy:

The electromagnetic force and torque developed in a physical system tend to decrease the magnetic stored energy at constant flux. This can be explained as follows:

When a force or torque is applied to a magnetic system, it tends to change the magnetic field configuration. If the force or torque causes the magnetic field to change in such a way that the magnetic flux decreases, then the magnetic stored energy also decreases. This is because the energy stored in the magnetic field is directly proportional to the square of the magnetic flux.

Example:

Let's consider the example of an electromagnetic relay. An electromagnetic relay consists of a coil of wire wound around a soft iron core. When current flows through the coil, it generates a magnetic field that attracts an armature, causing mechanical movement. In this case, if an external force is applied to the armature, it will tend to move in a direction opposite to the magnetic force developed by the coil. This will result in a change in the magnetic field configuration, leading to a decrease in the magnetic flux and consequently, a decrease in the magnetic stored energy.

Conclusion:

In summary, the electromagnetic force and torque developed in any physical system tend to decrease the magnetic stored energy at constant flux. This is because the force or torque causes a change in the magnetic field configuration, resulting in a decrease in the magnetic flux and thus, a decrease in the magnetic stored energy.

Which of the following statements are true about electromagnetic torques and reluctance torques?
(i) electromagnetic torque can exist only if both windings carry current
(ii) reluctance torque depend on the direction of current in stator or rotor windings
(iii) reluctance torque doesn't depend on the direction of current in stator or rotor windings
(iv) electromagnetic torque depend on the direction of currents is and ir
(v) electromagnetic torque doesn't depend on the direction of currents is and ir
  • a)
    (i), (ii), (iii)
  • b)
    (ii), (iii), (v)
  • c)
    (i), (iii), (iv)
  • d)
    (ii), (iii), (iv)
Correct answer is option 'C'. Can you explain this answer?

Prasad Verma answered
The correct answer is option 'C': (i), (iii), (iv).

Explanation:
(i) Electromagnetic torque can exist only if both windings carry current:
- Electromagnetic torque is generated in an electric motor when there is a magnetic field interaction between the stator and rotor windings. This magnetic field is created by the current flowing through both the stator and rotor windings. Therefore, electromagnetic torque can exist only if both windings carry current.

(iii) Reluctance torque doesn't depend on the direction of current in stator or rotor windings:
- Reluctance torque is a type of torque that arises due to the variation in the magnetic reluctance of the magnetic path between the stator and rotor of an electric motor. It is independent of the direction of current in the stator or rotor windings. Reluctance torque is generated when the stator and rotor teeth are not aligned properly, causing a variation in the magnetic reluctance and resulting in torque production.

(iv) Electromagnetic torque depends on the direction of currents in the stator and rotor windings:
- The direction of current in the stator and rotor windings plays a crucial role in determining the direction of the magnetic field produced by these windings. The interaction between the magnetic fields of the stator and rotor windings results in the generation of electromagnetic torque. Therefore, the direction of the currents in the stator and rotor windings directly affects the direction of the electromagnetic torque produced.

In summary, electromagnetic torque requires both windings to carry current, and its direction depends on the direction of currents in the windings. On the other hand, reluctance torque is independent of the direction of current in the windings.

Magnetic stored energy density for iron is given by ______
  • a)
    1/2 B/μ
  • b)
    1/2 B2 μ
  • c)
    1/2 ∅2 Rl
  • d)
    1/2 B2
Correct answer is option 'D'. Can you explain this answer?

Zoya Sharma answered
Magnetic stored energy density for iron is given as
wfld = Wfld/((Length of the magnetic path through Iron)*(Iron area normal to the magnetic flux)) = 1/2 (F∅)/(length*Area) = 1/2 F/length ∅/area = 1/2 H*B
Also, H = B/μ,thus wfld = 1/2 B2/μ.

For a toroid to extract the energy from the supply system, the flux linkages of the magnetic field must be ________
  • a)
    zero
  • b)
    changing or varying
  • c)
    constant
  • d)
    any of the mentioned
Correct answer is option 'B'. Can you explain this answer?

Zoya Sharma answered
dWelec = idφ = eidt, where dWelec = differential electrical energy to coupling field, and if the flux linkages are either constant or zero, i.e, dφ = 0, then dWelec = 0.

The energy stored in a magnetic field is given by ____________ where L = self-inductance and Rl=reluctance.
  • a)
    1/2 Li2
  • b)
    1/2 (mmf*Rl)2
  • c)
    1/2∅Rl
  • d)
    1/2 φ2i
Correct answer is option 'A'. Can you explain this answer?

Anoushka Kumar answered
Explanation:

Magnetic Energy Formula:
- The energy stored in a magnetic field is given by the formula: 1/2 Li^2, where L is the self-inductance of the circuit.

Understanding the Formula:
- The term "1/2" in the formula represents the factor of 1/2 that is commonly used in energy storage calculations.
- The term "Li^2" represents the energy stored in the magnetic field, where L is the self-inductance of the circuit and i is the current flowing through the circuit.

Importance of Self-Inductance:
- Self-inductance (L) is a measure of the ability of a circuit to store energy in its magnetic field when current flows through it.
- The greater the self-inductance of a circuit, the more energy it can store in its magnetic field.

Conclusion:
- Therefore, the correct formula for calculating the energy stored in a magnetic field is 1/2 Li^2, where L is the self-inductance of the circuit.

An electro-mechanical energy conversion device is one which converts _______
  • a)
    Electrical energy to mechanical energy only
  • b)
    Mechanical energy to electrical energy only
  • c)
    Electrical to mechanical and mechanical to electrical
  • d)
    None of the mentioned
Correct answer is option 'C'. Can you explain this answer?

Ameya Gupta answered
An electro-mechanical energy conversion device is one which converts electrical to mechanical and mechanical to electrical.

Explanation:

Electro-mechanical energy conversion devices are devices that are capable of converting electrical energy into mechanical energy and vice versa. These devices are widely used in various applications, ranging from small household appliances to large industrial machinery.

Electrical to mechanical conversion:

When an electro-mechanical energy conversion device converts electrical energy to mechanical energy, it usually involves the interaction of magnetic fields and electric currents. One common example of such a device is an electric motor. In an electric motor, the electrical energy is supplied to the device through the input terminals, which is then converted into mechanical energy. This conversion is achieved by the interaction of the magnetic field produced by the stator and the electric current flowing through the rotor. As a result, the rotor starts rotating, thereby converting electrical energy into mechanical energy.

Mechanical to electrical conversion:

On the other hand, when an electro-mechanical energy conversion device converts mechanical energy to electrical energy, it generally involves the use of generators or alternators. These devices utilize the principle of electromagnetic induction to convert mechanical energy into electrical energy. When a conductor is moved in a magnetic field, an electric current is induced in the conductor. In a generator or alternator, mechanical energy is supplied to the device, which causes the rotor to rotate within a magnetic field. This rotation induces an electric current in the stator windings, thereby converting mechanical energy into electrical energy.

Advantages of electro-mechanical energy conversion devices:

- Versatility: Electro-mechanical energy conversion devices offer the advantage of converting energy from one form to another, allowing for its utilization in different applications.

- Efficiency: These devices are designed to be highly efficient in converting energy, minimizing energy losses and maximizing the overall efficiency of the system.

- Control: Electro-mechanical energy conversion devices can be easily controlled and regulated, allowing for precise manipulation of electrical and mechanical energy.

- Reliability: These devices are known for their reliability and durability, making them suitable for long-term use in various applications.

In conclusion, an electro-mechanical energy conversion device is capable of converting electrical energy to mechanical energy, as well as mechanical energy to electrical energy. This versatility and efficiency make these devices crucial in various electrical engineering applications.

The electromagnetic torque developed in any physical system, and with magnetic saturation neglected, acts in such a direction as to tend to ____________
  • a)
    decrease both the reluctance and inductance
  • b)
    increase both the reluctance and inductance
  • c)
    decrease the reluctance and increase the inductance
  • d)
    increase the reluctance and decrease the inductance
Correct answer is option 'C'. Can you explain this answer?

Ishan Chawla answered
Explanation:

Electromagnetic Torque Development:
- The electromagnetic torque developed in any physical system tends to decrease the reluctance and increase the inductance.
- This is due to the relationship between torque, inductance, and reluctance in an electromagnetic system.

Reluctance and Inductance:
- Reluctance is the opposition of a magnetic circuit to magnetic flux, while inductance is the property of a coil to resist changes in current flow.
- When the electromagnetic torque is developed in a system, it tends to decrease the reluctance, which means reducing the opposition to magnetic flux.
- At the same time, it tends to increase the inductance, which means increasing the property of the coil to resist changes in current flow.

Direction of Torque:
- The direction of the electromagnetic torque developed is such that it tends to optimize the system by decreasing reluctance and increasing inductance.
- This leads to efficient operation and performance of the electromagnetic system.
Therefore, the correct answer is option 'C', which states that the electromagnetic torque developed tends to decrease the reluctance and increase the inductance in a physical system.

Electromagnetic force and/or torque developed in any physical system, acts in such a direction as to tend to ____________
  • a)
    increase both the field energy and co-energy at constant current
  • b)
    increase the field energy and decrease the co-energy at constant current
  • c)
    decrease both the field energy and co-energy at constant current
  • d)
    decrease the field energy and increase the co-energy at constant current
Correct answer is option 'A'. Can you explain this answer?

The correct answer to this question is option 'A': increase both the field energy and co-energy at constant current. Let's discuss the explanation in detail:

Introduction to Electromagnetic Force and Torque:
The electromagnetic force and torque are fundamental concepts in the field of electromagnetism. These forces and torques arise due to the interaction between electric currents and magnetic fields. They play a crucial role in various electrical and electronic systems.

Explanation:
When an electric current flows through a conductor, it creates a magnetic field around it. This magnetic field interacts with other magnetic fields in its vicinity, giving rise to electromagnetic forces and torques. These forces and torques can be attractive or repulsive, depending on the orientation and magnitude of the currents and magnetic fields involved.

The electromagnetic force and torque developed in any physical system tend to increase both the field energy and co-energy at constant current. Let's understand what field energy and co-energy mean:

1. Field Energy:
Field energy refers to the energy stored in the magnetic field surrounding a current-carrying conductor or any other system involving magnetic fields. It is directly proportional to the square of the magnetic field strength and the volume of the region containing the magnetic field.

2. Co-energy:
Co-energy, also known as magnetic potential energy, is the energy associated with the arrangement of magnetic fields in a system. It is a measure of the work done to establish the magnetic field configuration. Co-energy is directly related to the magnetic field strength, the permeability of the medium, and the volume of the region containing the magnetic field.

When the electromagnetic force and torque act in a certain direction, they tend to increase both the field energy and co-energy at constant current. This means that the magnetic field strength and the volume of the region containing the magnetic field increase, resulting in higher stored energy.

Conclusion:
In summary, the electromagnetic force and torque developed in any physical system tend to increase both the field energy and co-energy at constant current. This understanding is crucial in designing and analyzing electrical and electronic systems, where the interaction between electric currents and magnetic fields plays a significant role.

The formula for energy stored in the mechanical system of linear motion type is ______
  • a)
    1/2 Jwr2
  • b)
    1/2 mv2
  • c)
    1/2 mv
  • d)
    Jwr2
Correct answer is option 'B'. Can you explain this answer?

Aman Jain answered
Energy stored in the mechanical system of linear motion type

The correct formula for calculating the energy stored in a mechanical system of linear motion type is option B, which is given as 1/2 mv^2.

Explanation:

1. Understanding mechanical energy:
Mechanical energy refers to the energy possessed by an object due to its motion or position. In the case of linear motion, mechanical energy is associated with the movement of an object along a straight line.

2. Types of mechanical energy:
There are two forms of mechanical energy: kinetic energy and potential energy.
- Kinetic energy (KE) is the energy possessed by an object due to its motion. It depends on the mass (m) and velocity (v) of the object.
- Potential energy (PE) is the energy possessed by an object due to its position or height. It depends on the mass (m) of the object and the height (h) at which it is located.

3. Energy stored in the mechanical system of linear motion:
In the case of linear motion, the energy stored in the mechanical system is solely kinetic energy since there is no change in height or position.
The formula to calculate the kinetic energy is given by KE = 1/2 mv^2, where:
- KE is the kinetic energy of the object.
- m is the mass of the object.
- v is the velocity of the object.

4. Derivation of the formula:
To understand why the formula for energy stored in the mechanical system of linear motion is 1/2 mv^2, let's consider the following steps:

- The work done (W) on an object is given by the product of the force applied (F) and the displacement (d) along the direction of the force, i.e., W = Fd.
- According to Newton's second law of motion, force (F) is given by the product of mass (m) and acceleration (a), i.e., F = ma.
- Substituting the value of force (F) in the work equation, we get W = mad.
- The equation for acceleration (a) is given by the change in velocity (Δv) divided by the change in time (Δt), i.e., a = Δv/Δt.
- Substituting the value of acceleration (a) in the work equation, we get W = m(Δv/Δt)d.
- Rearranging the equation, we get W = mΔv(d/Δt).
- Since velocity (v) is the change in displacement (Δd) divided by the change in time (Δt), i.e., v = Δd/Δt, we can substitute the value of velocity (v) in the work equation, giving W = m(v)(d/Δt).
- The term (d/Δt) represents the average velocity (v_avg) of the object.
- Therefore, the work done (W) can be written as W = m(v)(v_avg).
- The work done (W) is equal to the energy stored in the mechanical system.
- Thus, the energy stored in the mechanical system is given by E = m(v)(v_avg).
- Since v_avg is half of the final velocity (v

When a current of 5A flows through a coil of linear magnetic circuit, it has flux linkages of 2.4 wb-turns. What is the energy stored in the magnetic field of this coil in Joules?
  • a)
    6
  • b)
    12
  • c)
    1.2
  • d)
    2.4
Correct answer is option 'A'. Can you explain this answer?

Given data:
Current (I) = 5A
Flux linkages (Φ) = 2.4 wb-turns

To calculate the energy stored in the magnetic field of the coil, we can use the formula:

Energy (W) = 0.5 * L * I^2

Where,
L = Inductance of the coil
I = Current flowing through the coil

To find the inductance (L), we can use the formula:

L = Φ / I

Substituting the given values, we have:

L = 2.4 wb-turns / 5A
L = 0.48 H

Now, substituting the values of L and I in the energy formula:

W = 0.5 * 0.48 H * (5A)^2
W = 0.5 * 0.48 H * 25A^2
W = 0.5 * 0.48 H * 625
W = 7.5 Joules

Therefore, the energy stored in the magnetic field of the coil is 7.5 Joules.

Since none of the given options match the calculated value, it seems there might be an error in the question or the options provided. However, the closest option to the calculated value is option 'A' with a value of 6 Joules.

The energy storing capacity of magnetic field is about ________ times greater than that of electric field.
  • a)
    50,000
  • b)
    25,000
  • c)
    10,000
  • d)
    40,000
Correct answer is option 'B'. Can you explain this answer?

Snehal Rane answered
Magnetic Field Energy Storage Capacity

The energy storing capacity of magnetic field is given by the formula:

U = (1/2) L I^2

where U is the energy stored in the magnetic field, L is the inductance of the coil, and I is the current flowing through it.

Similarly, the energy storing capacity of electric field is given by the formula:

U = (1/2) C V^2

where U is the energy stored in the electric field, C is the capacitance of the capacitor, and V is the voltage across it.

Comparison of Magnetic Field and Electric Field Energy Storage Capacity

The energy storing capacity of magnetic field is about 25,000 times greater than that of electric field. This can be explained by the following reasons:

1. Inductance vs Capacitance

Inductance is a property of a coil that opposes any change in current flowing through it by inducing a voltage in the opposite direction. It is proportional to the square of the number of turns in the coil and the area enclosed by them. As a result, inductance can be increased by increasing the number of turns or the area of the coil.

Capacitance, on the other hand, is a property of a capacitor that opposes any change in voltage across it by storing charge on its plates. It is proportional to the area of the plates and inversely proportional to the distance between them. As a result, capacitance can be increased by increasing the area of the plates or decreasing the distance between them.

Since inductance can be increased more easily than capacitance, the energy storing capacity of magnetic field is higher than that of electric field.

2. Current vs Voltage

The energy stored in a magnetic field depends on the square of the current flowing through the coil, while the energy stored in an electric field depends on the square of the voltage across the capacitor. Since the current flowing through a coil can be much higher than the voltage across a capacitor, the energy storing capacity of magnetic field is higher than that of electric field.

Applications of Magnetic Field Energy Storage

The high energy storing capacity of magnetic field makes it useful in various applications, such as:

1. Inductors in electronic circuits to store energy and filter out unwanted frequencies.

2. Transformers to transfer energy from one circuit to another.

3. Electric motors and generators to convert electrical energy into mechanical energy and vice versa.

4. Magnetic storage devices such as hard disk drives to store digital data.

Conclusion

In summary, the energy storing capacity of magnetic field is about 25,000 times greater than that of electric field due to the higher inductance of coils and the higher current flowing through them. This makes magnetic field useful in various applications where high energy storage is required.

Consider a magnetic relay with linear magnetization curve in both of its open and closed position. What happens to the electrical energy input to the relay, when the armature moves slowly from open position to closed position?
  • a)
    Welec = Wfld
  • b)
    Welec = Wmech
  • c)
    Welec = Wmech/2+Wfld/2
  • d)
    Welec = 0
Correct answer is option 'C'. Can you explain this answer?

Hiral Kulkarni answered
Explanation:

Energy Conversion in a Magnetic Relay:
- In a magnetic relay, electrical energy is converted into magnetic field energy when the relay is energized.
- This magnetic field then acts on the armature, causing it to move and mechanically switch the relay contacts.

Energy Input during Armature Movement:
- When the armature moves slowly from the open position to the closed position, both mechanical and magnetic energy are involved in the process.
- The electrical energy input to the relay is divided between the mechanical work done in moving the armature and the magnetic field energy.

Calculation of Electrical Energy Input:
- The total electrical energy input (Welec) to the relay during this process can be divided into two parts: the mechanical work done (Wmech) and the magnetic field energy (Wfld).
- Since the armature moves slowly from the open to the closed position, the electrical energy input can be approximated as the average of the mechanical and magnetic energies: Welec = Wmech/2 + Wfld/2.

Conclusion:
- Therefore, the correct answer is option 'C', where the electrical energy input to the relay during the slow movement of the armature from open to closed position is divided equally between the mechanical work done and the magnetic field energy.

For a linear electromagnetic circuit, which of the following statement is true?
  • a)
    Field energy is less than the Co-energy
  • b)
    Field energy is equal to the Co-energy
  • c)
    Field energy is greater than the Co-energy
  • d)
    Co-energy is zero
Correct answer is option 'B'. Can you explain this answer?

Mihir Chawla answered
Field Energy and Co-energy in a Linear Electromagnetic Circuit

In a linear electromagnetic circuit, the field energy and co-energy are important concepts that relate to the energy stored in the system. Let's explore each of these terms and understand their relationship.

Field Energy
The field energy refers to the energy stored in the magnetic field (B) and electric field (E) of the circuit. It represents the energy required to establish and maintain these fields. The field energy is given by the equations:

- Magnetic Field Energy: E_magnetic = (1/2) * L * I^2
- Electric Field Energy: E_electric = (1/2) * C * V^2

Where L is the inductance, I is the current, C is the capacitance, and V is the voltage.

Co-energy
The co-energy, also known as the dual of field energy, is the energy stored in the circuit elements due to the interaction with the magnetic and electric fields. It represents the energy released when the fields collapse or change. The co-energy is given by the equations:

- Magnetic Co-energy: W_magnetic = (1/2) * L * I^2
- Electric Co-energy: W_electric = (1/2) * C * V^2

It is important to note that the co-energy is defined in terms of the variables (current or voltage) that are not directly associated with the energy storage element (inductor or capacitor).

Relationship between Field Energy and Co-energy
In a linear electromagnetic circuit, the field energy and co-energy are equal. This means that the energy stored in the fields is equal to the energy stored in the circuit elements due to their interaction with the fields. Mathematically, we can express this relationship as:

- Magnetic Field Energy = Magnetic Co-energy
- Electric Field Energy = Electric Co-energy

Therefore, the correct statement is option 'B': Field energy is equal to the co-energy.

This relationship is a consequence of the principle of energy conservation, which states that energy cannot be created or destroyed but can only be transformed from one form to another. In a linear electromagnetic circuit, the energy transformations occur between the fields and the circuit elements, resulting in the equality between field energy and co-energy.

By understanding the relationship between field energy and co-energy, we can analyze the energy balance in a linear electromagnetic circuit and design efficient systems that minimize energy losses.

In a doubly excited magnetic system with salient pole type stator and rotor, if the rotor is not allowed to move, then the equation for magnetic field stored energy in establishing the currents from zero to is and ir is __________
  • a)
    Wfld =1/2 is2L+ 1/2 ir2Lr
  • b)
    Wfld = 1/2 is2 Ls + Mrs is ir
  • c)
    Wfld =1/2 isLs + 1/2 ir2 Lr + Mrs is ir
  • d)
    Wfld = 1/2 ir2Lr + Mrs is ir
Correct answer is option 'C'. Can you explain this answer?

Sanvi Kapoor answered
As the rotor is not allowed to move, dWmech = 0, thus dWelec = 0 + dWfld = is+ irr, if in this equation, we introduce the self and mutual inductance terms, (Ψ= Lsis) and integrate the resulting equation from 0 to is, 0 to ir and 0 to iris, the respective terms, finally we get Wfld = 1/2 is2Ls+ 1/2 ir2Lr + Mrs is ir.

Most of the electromagnetic energy conversion devices belong to __________
  • a)
    singly excited magnetic systems
  • b)
    doubly excited magnetic systems
  • c)
    multiply excited magnetic systems
  • d)
    both doubly excited magnetic systems and multiply excited magnetic systems
Correct answer is option 'D'. Can you explain this answer?

Dipika Basak answered
Understanding Electromagnetic Energy Conversion Devices
Electromagnetic energy conversion devices play a crucial role in various applications, including motors, generators, and transformers. These devices can be categorized based on their excitation systems.
Types of Excitation Systems
- Singly Excited Magnetic Systems:
- These systems have only one magnetic field source. They are less common in energy conversion devices as they cannot effectively utilize energy from multiple sources.
- Doubly Excited Magnetic Systems:
- In this configuration, two magnetic fields interact, typically from a rotor and a stator. This allows for better control over the energy conversion process, leading to higher efficiency and performance.
- Multiply Excited Magnetic Systems:
- These systems extend the principle of doubly excited systems to include more than two sources of magnetic excitation. They are generally more complex and can offer enhanced functionality in certain applications.
Significance of Doubly and Multiply Excited Systems
- Most electromagnetic energy conversion devices, such as synchronous machines, induction machines, and certain transformers, involve interactions between multiple magnetic fields.
- The combination of doubly and multiply excited systems allows for:
- Improved torque production
- Enhanced operational flexibility
- Greater efficiency in energy conversion processes
- Therefore, both doubly excited and multiply excited magnetic systems are essential in designing advanced electromagnetic devices, making option 'D' the correct choice.
Conclusion
In summary, the prevalence of both doubly and multiply excited magnetic systems in electromagnetic energy conversion devices reflects their necessity for achieving optimal performance in various electrical engineering applications.

Singly and doubly excited magnetic systems applications are respectively ________
  • a)
    loud speakers and tachometers
  • b)
    synchronous motors and moving iron instruments
  • c)
    DC shunt machines and solenoids
  • d)
    reluctance motors and synchronous motors
Correct answer is option 'D'. Can you explain this answer?

Prasad Saini answered
Singly and doubly excited magnetic systems are two types of magnetic systems used in various electrical applications. Let's understand the applications of these systems in detail:

1. Singly Excited Magnetic Systems:
Singly excited magnetic systems have only one source of excitation, either the field winding or the armature winding. These systems find applications in the following:

- Reluctance Motors: Reluctance motors are simple and robust electric motors that operate based on the principle of varying reluctance. In these motors, the field winding is excited, creating a magnetic field that interacts with the rotor's salient poles. As the rotor rotates, the reluctance between the stator and rotor poles changes, resulting in the generation of torque.

- Synchronous Motors: Synchronous motors are AC motors that operate at a constant speed determined by the frequency of the power source. In these motors, the field winding is excited to create a rotating magnetic field that synchronizes with the rotating magnetic field produced by the stator windings. This synchronization enables the motor to maintain a constant speed and efficiently convert electrical energy into mechanical energy.

2. Doubly Excited Magnetic Systems:
Doubly excited magnetic systems have both field windings and armature windings. These systems find applications in the following:

- Synchronous Motors: Doubly excited synchronous motors are used in applications where precise control of speed and torque is required. These motors have separate field windings and armature windings. The field winding establishes the magnetic field, while the armature winding carries the current that produces the torque. By varying the excitation of the field winding and the current in the armature winding, the speed and torque of the motor can be controlled.

- Moving Iron Instruments: Moving iron instruments are used for measuring current, voltage, and power in electrical systems. These instruments use a movable iron piece (usually in the form of a vane or a disk) that experiences a force when subjected to a magnetic field produced by the field and armature windings. The deflection of the iron piece is proportional to the measured quantity, allowing for accurate measurement.

In summary, singly excited magnetic systems are used in reluctance motors and synchronous motors, while doubly excited magnetic systems find applications in synchronous motors and moving iron instruments.

Chapter doubts & questions for Electromechanical Energy Conversion Principles - Electrical Machines 2025 is part of Electrical Engineering (EE) exam preparation. The chapters have been prepared according to the Electrical Engineering (EE) exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Electromechanical Energy Conversion Principles - Electrical Machines in English & Hindi are available as part of Electrical Engineering (EE) exam. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.

Electrical Machines

19 videos|95 docs|25 tests

Signup to see your scores go up within 7 days!

Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev