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The composition of a sample of wustite is Fe0.93O. What percentage of the iron is present in the form of Fe (III)?
- a)5%
- b)7.08%
- c)15.05%
- d)23.6%
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The composition of a sample of wustite is Fe0.93O. What percentage of ...
In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.
However, here number of Fe2+ present = 0.93
Or No. of Fe2+ ions missing = 0.07
Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14
To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.
In short, 0.93 Fe2+ ions have 0.14 Fe3+ ions
100 Fe2+ ions have = 0.14/0.93 * 100 = 15.05%
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The composition of a sample of wustite is Fe0.93O. What percentage of ...
Given: Composition of wustite = Fe0.93O
To find: Percentage of iron present in the form of Fe(III)
Solution:
1. Determine the oxidation state of iron in wustite:
The formula of wustite is FeO. The oxidation state of oxygen is -2. Let the oxidation state of iron be x.
Fe + O = FeO
x + (-2) = -1
x = +1
Therefore, the oxidation state of iron in wustite is +2.
2. Determine the percentage of iron present in the form of Fe(III):
Fe(III) has an oxidation state of +3. To determine the percentage of iron present in the form of Fe(III), we need to calculate the moles of Fe and Fe(III) in the sample of wustite.
Moles of Fe in wustite = 0.93
Moles of Fe(III) in wustite = 0 (since Fe in wustite has an oxidation state of +2)
Total moles of iron in wustite = 0.93
Therefore, the percentage of iron present in the form of Fe(III) is:
(0/0.93) x 100% = 0%
Hence, option C (15.05%) is incorrect.
Answer: Option A (5%) is the correct answer.
To find: Percentage of iron present in the form of Fe(III)
Solution:
1. Determine the oxidation state of iron in wustite:
The formula of wustite is FeO. The oxidation state of oxygen is -2. Let the oxidation state of iron be x.
Fe + O = FeO
x + (-2) = -1
x = +1
Therefore, the oxidation state of iron in wustite is +2.
2. Determine the percentage of iron present in the form of Fe(III):
Fe(III) has an oxidation state of +3. To determine the percentage of iron present in the form of Fe(III), we need to calculate the moles of Fe and Fe(III) in the sample of wustite.
Moles of Fe in wustite = 0.93
Moles of Fe(III) in wustite = 0 (since Fe in wustite has an oxidation state of +2)
Total moles of iron in wustite = 0.93
Therefore, the percentage of iron present in the form of Fe(III) is:
(0/0.93) x 100% = 0%
Hence, option C (15.05%) is incorrect.
Answer: Option A (5%) is the correct answer.
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The composition of a sample of wustite is Fe0.93O. What percentage of the iron is present in the form of Fe (III)?a)5%b)7.08%c)15.05%d)23.6%Correct answer is option 'C'. Can you explain this answer?
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