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Sinusoidal peak potential is 200 volt with frequency 50Hz. It is represented by the equation
  • a)
    E = 200 sin 50t
  • b)
    E = 200 sin 314t
  • c)
    E = 200sin 50t
  • d)
    E =200sin 314t
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Sinusoidal peak potential is 200 volt with frequency 50Hz. It is repre...
Given peak potential is 200v
so, amplitude is 200
and frequency is 50Hz
so angular frequency is 2.πx50 = 314/sec
so the value is
E = 200sin(314t)
Hence option B is the correct answer.
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Community Answer
Sinusoidal peak potential is 200 volt with frequency 50Hz. It is repre...
Given peak potential is 200v
so, amplitude is 200
and frequency is 50Hz
so angular frequency is 2.πx50 = 314/sec
so the value is
E = 200sin(314t)
Hence option B is the correct answer.
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Sinusoidal peak potential is 200 volt with frequency 50Hz. It is represented by the equationa)E = 200 sin 50tb)E = 200 sin 314tc)E = 200sin 50td)E =200sin 314tCorrect answer is option 'B'. Can you explain this answer?
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