Which of the following complexes exhibit the highest paramagnetic beha...
The highest paramagnetic behavior in a complex is usually observed when there are unpaired electrons present. Unpaired electrons have magnetic moments that align with an external magnetic field, leading to paramagnetic behavior. Let's analyze each complex to determine which one exhibits the highest paramagnetic behavior.
1) [Co(OX)2(H2O)2]-
This complex is a cobalt(III) complex with two oxalate ligands and two water ligands. Cobalt(III) has a d6 electronic configuration, where all the d orbitals are paired. Therefore, this complex does not have any unpaired electrons and exhibits no paramagnetic behavior.
2) [Ti(NH3)6]3+
This complex is a titanium(III) complex with six ammonia ligands. Titanium(III) has a d1 electronic configuration, meaning it has one unpaired electron. Therefore, this complex exhibits some paramagnetic behavior.
3) [V(gly)(OH)2(NH3)2]
This complex is a vanadium(III) complex with a glycine ligand, two hydroxide ligands, and two ammonia ligands. Vanadium(III) has a d2 electronic configuration, where there are two unpaired electrons. Thus, this complex exhibits more paramagnetic behavior compared to the previous two complexes.
4) [Fe(en)(bpy)(NH3)2]2+
This complex is an iron(III) complex with an ethylenediamine (en) ligand, a bipyridine (bpy) ligand, and two ammonia ligands. Iron(III) has a d5 electronic configuration, where there are five unpaired electrons. Therefore, this complex exhibits the highest paramagnetic behavior among the given complexes.
In summary, the complex [Fe(en)(bpy)(NH3)2]2+ exhibits the highest paramagnetic behavior due to the presence of five unpaired electrons.
Which of the following complexes exhibit the highest paramagnetic beha...
Is it A?
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