The two bulbs as in the above question are connected in series to a 20...
Understanding Bulbs in Series
When two bulbs are connected in series, the same current flows through both. The potential drop across each bulb depends on its resistance, which is influenced by its power rating (watts).
Power and Resistance Relationship
- The power rating of a bulb (in watts) is defined by the formula:
Power (P) = Voltage (V) × Current (I)
- For bulbs connected in series, the voltage drop across each bulb can be calculated using their resistances.
Calculating Resistance
- The resistance (R) can be derived from the power rating:
R = V^2 / P
- Assuming both bulbs are rated for the same voltage, the bulb with lower wattage (40 watts) has a higher resistance compared to the higher wattage (100 watts) bulb.
Applying Ohm's Law
- In a series circuit, the total voltage (200 volts) is shared among the components.
- The voltage drop (V) across each bulb can be calculated using Ohm's Law:
V = I × R
- Since the 40-watt bulb has higher resistance, it will drop more voltage than the 100-watt bulb when current flows through.
Conclusion
- Therefore, the potential drop across the 40-watt bulb is greater than the potential drop across the 100-watt bulb.
- This leads to the correct answer being option 'B': The potential drop across the 40-watt bulb is greater than the potential drop across the 100-watt bulb.
Understanding these principles clarifies how voltage divides in a series circuit based on resistance.
The two bulbs as in the above question are connected in series to a 20...
The question is incomplete. plz provide all info