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Normal depth in open channel flow is
  • a)
    the depth measured normal to the channel bed
  • b)
    the depth of flow in the channel corresponding to uniform flow
  • c)
    the depth of flow in the channel corresponding to steady flow
  • d)
    vertical distance between the bed of the channel to the free liquid surface
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

Open channel flow is the flow of liquid in a channel with a free surface exposed to the atmosphere. Normal depth is an important parameter in open channel flow. It is defined as the depth of flow in the channel corresponding to uniform flow.

Factors affecting normal depth:
- Channel slope
- Channel roughness
- Flow rate
- Channel geometry

Calculation of normal depth:
The normal depth can be calculated using the Manning's equation for uniform flow. It is given by:

Q = (1/n) * A * R^(2/3) * S^(1/2)

where,
Q = flow rate
n = Manning's roughness coefficient
A = cross-sectional area of flow
R = hydraulic radius
S = channel slope

For uniform flow, the slope of the energy line is equal to the slope of the channel bed. At normal depth, the energy line coincides with the water surface. Hence, the slope of the energy line is equal to the slope of the water surface. At normal depth, the hydraulic radius is maximum and equal to the depth of flow.

Significance of normal depth:
The normal depth is important in the design of open channels as it determines the channel geometry for a given flow rate. It is also used in the analysis of open channel flow to predict the water surface profile and the flow rate.

Conclusion:
Normal depth in open channel flow is the depth of flow in the channel corresponding to uniform flow. It is an important parameter in the design and analysis of open channels. It is calculated using Manning's equation for uniform flow and is affected by various factors such as channel slope, roughness, flow rate, and geometry.
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Normal depth in open channel flow isa)the depth measured normal to the channel bedb)the depth of flow in the channel corresponding to uniform flowc)the depth of flow in the channel corresponding to steady flowd)vertical distance between the bed of the channel to the free liquid surfaceCorrect answer is option 'B'. Can you explain this answer?
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