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Find smallest number that leaves remainder 3, 5, 7 when divided by 4, 6, 8 respectively.
  • a)
    23
  • b)
    25
  • c)
    35
  • d)
    37
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find smallest number that leaves remainder 3, 5, 7 when divided by 4, ...
See carefully the difference between the divisor and remainder is having a certain trend. i.e.4 – 3 = 6 – 5 = 8 – 7=1
In such questions, take LCM of divisors and subtract the common difference from it.Now the LCM of 4, 6, 8 = 24Therefore the required number here = 24 – 1 = 23 (option ‘A’)
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Most Upvoted Answer
Find smallest number that leaves remainder 3, 5, 7 when divided by 4, ...
Smallest number leaving remainders 3, 5, 7 when divided by 4, 6, 8 respectively
To find the smallest number that leaves the given remainders when divided by the specified numbers, we need to consider the least common multiple (LCM) of the divisors.
- Finding the LCM of 4, 6, 8
The LCM of 4, 6, and 8 is 24. This means the number we are looking for should be 24 more than a multiple of 4, 6, and 8.
- Adding the respective remainders
Adding the given remainders (3, 5, 7) to the LCM (24), we get:
24 + 3 = 27 (for remainder 3 when divided by 4)
24 + 5 = 29 (for remainder 5 when divided by 6)
24 + 7 = 31 (for remainder 7 when divided by 8)
- Checking for the smallest number
Among these numbers, the smallest one is 27, which leaves remainders 3, 5, and 7 when divided by 4, 6, and 8 respectively.
Therefore, the correct answer is option A - 23.
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Find smallest number that leaves remainder 3, 5, 7 when divided by 4, 6, 8 respectively.a)23b)25c)35d)37Correct answer is option 'A'. Can you explain this answer?
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