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Silver chloride dissolves in excess of NH4OH. The cation present in this solution is
- a)Ag+
- b)[Ag(NH3)2]+
- c)[Ag(NH3)4]+
- d)[Ag(NH3)6]+
Correct answer is option 'B'. Can you explain this answer?
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Silver chloride dissolves in excess of NH4OH. The cation present in th...
Explanation:
When silver chloride (AgCl) is dissolved in excess NH4OH (ammonium hydroxide), it forms a complex ion called [Ag(NH3)2]+.
AgCl Dissociation:
AgCl dissociates in water to form Ag+ and Cl- ions.
AgCl(s) ↔ Ag+(aq) + Cl-(aq)
Formation of Complex Ion:
When NH4OH is added in excess, it reacts with Ag+ ions to form a complex ion.
Ag+(aq) + 2NH3(aq) → [Ag(NH3)2]+ (aq)
The reaction involves the coordination of two NH3 molecules (ammonia) with the Ag+ ion to form a complex ion. This complex ion is stable in solution and responsible for the dissolution of silver chloride.
Other Options:
a) Ag: This is the silver cation, but it is not the correct answer because silver chloride does not dissolve in water to form Ag+ ions.
c) [Ag(NH3)4]+: This complex ion has four coordinated NH3 molecules with the Ag+ ion. It is not the correct answer because silver chloride does not form this complex ion.
d) [Ag(NH3)6]+: This complex ion has six coordinated NH3 molecules with the Ag+ ion. It is not the correct answer because silver chloride does not form this complex ion.
Correct Answer:
b) [Ag(NH3)2]+: This complex ion has two coordinated NH3 molecules with the Ag+ ion. It is the correct answer because silver chloride dissolves in excess NH4OH to form this complex ion.
Overall, the dissolution of silver chloride in excess NH4OH involves the formation of a complex ion [Ag(NH3)2]+, which is responsible for the presence of the Ag+ cation in the solution.
When silver chloride (AgCl) is dissolved in excess NH4OH (ammonium hydroxide), it forms a complex ion called [Ag(NH3)2]+.
AgCl Dissociation:
AgCl dissociates in water to form Ag+ and Cl- ions.
AgCl(s) ↔ Ag+(aq) + Cl-(aq)
Formation of Complex Ion:
When NH4OH is added in excess, it reacts with Ag+ ions to form a complex ion.
Ag+(aq) + 2NH3(aq) → [Ag(NH3)2]+ (aq)
The reaction involves the coordination of two NH3 molecules (ammonia) with the Ag+ ion to form a complex ion. This complex ion is stable in solution and responsible for the dissolution of silver chloride.
Other Options:
a) Ag: This is the silver cation, but it is not the correct answer because silver chloride does not dissolve in water to form Ag+ ions.
c) [Ag(NH3)4]+: This complex ion has four coordinated NH3 molecules with the Ag+ ion. It is not the correct answer because silver chloride does not form this complex ion.
d) [Ag(NH3)6]+: This complex ion has six coordinated NH3 molecules with the Ag+ ion. It is not the correct answer because silver chloride does not form this complex ion.
Correct Answer:
b) [Ag(NH3)2]+: This complex ion has two coordinated NH3 molecules with the Ag+ ion. It is the correct answer because silver chloride dissolves in excess NH4OH to form this complex ion.
Overall, the dissolution of silver chloride in excess NH4OH involves the formation of a complex ion [Ag(NH3)2]+, which is responsible for the presence of the Ag+ cation in the solution.
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Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer?
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Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer?.
Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Silver chloride dissolves in excess of NH4OH. The cation present in this solution isa)Ag+b)[Ag(NH3)2]+c)[Ag(NH3)4]+d)[Ag(NH3)6]+Correct answer is option 'B'. Can you explain this answer?.
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