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The number of terms of the series needed for the sum of the series 50+45+40+….. becomes zero
  • a)
    22
  • b)
    21
  • c)
    20
  • d)
    None
Correct answer is option 'B'. Can you explain this answer?
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The number of terms of the series needed for the sum of the series 50+...
Given series is 50, 45, 40, ...

We need to find the number of terms required to make the sum zero.

Let the number of terms required be n.

Sum of n terms is given by:

S = n/2 [2a + (n-1)d]

where a is the first term, d is the common difference.

Here, a = 50, d = -5

So, S = n/2 [2(50) + (n-1)(-5)]

Simplifying the above expression, we get:

S = n/2 [100 - 5(n-1)]

S = n/2 [105 - 5n]

We need to find the value of n for which S becomes zero.

So, n/2 [105 - 5n] = 0

n(105 - 5n) = 0

n = 0 or n = 21

Since the number of terms cannot be zero, the required number of terms is 21.

Therefore, option B is the correct answer.
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The number of terms of the series needed for the sum of the series 50+45+40+….. becomes zeroa)22b)21c)20d)NoneCorrect answer is option 'B'. Can you explain this answer?
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