3 moles of A and 4 moles of B are mixed together and allowed to come i...
Equilibrium extent of the reaction is the ratio of the amount of product formed to the amount of reactant consumed at equilibrium. In this case, we are given the initial moles of reactants and the amount of product formed at equilibrium. To find the equilibrium extent, we need to determine the moles of reactants consumed and the moles of product formed.
Given:
Initial moles of A = 3
Initial moles of B = 4
Moles of C formed at equilibrium = 1
Let's assume x moles of A react and y moles of B react to form the product.
|Reactant/ Product|Initial moles|Change in moles|Equilibrium moles|
|---|---|---|---|
|A|-3|-x|3-x|
|B|-4|-4y|4-4y|
|C|0|y|y|
|D|0|3y|3y|
According to the balanced equation, the stoichiometry of the reaction is as follows:
A(g) + 4B(g) → 2C(g) + 3D(g)
From the stoichiometry, we can see that 1 mole of C is formed for every 4 moles of B reacted. Therefore, the moles of B reacted can be calculated as follows:
4 moles of B → 2 moles of C
4y moles of B → y moles of C
Since we are given that 1 mole of C is formed at equilibrium, we can write the equation:
y = 1
Now, let's calculate the moles of A reacted using the stoichiometry:
3 moles of A → 2 moles of C
3-x moles of A → (2/3)(3-x) moles of C
Since we are given that 1 mole of C is formed at equilibrium, we can write the equation:
(2/3)(3-x) = 1
Solving the equation, we get:
2(3-x) = 3
6 - 2x = 3
2x = 6-3
2x = 3
x = 3/2
Therefore, the moles of A reacted is 3/2.
Now, we can calculate the equilibrium extent of the reaction:
Equilibrium extent = Moles of C formed at equilibrium / Initial moles of A
Equilibrium extent = 1 mole / 3 moles
Equilibrium extent = 1/3
Hence, the correct answer is option C, 1/3.
3 moles of A and 4 moles of B are mixed together and allowed to come i...
Que mai minor mistake h equation mai a k samne 3 aayga n then solve it