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A condenser of 250 µF is connected in parallel to a coil of inductance 0.16 mH and effective resistance 20 W. The resonant frequency will be ______ (give Answer in KHz)
    Correct answer is '80º KHz'. Can you explain this answer?
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    A condenser of 250 µF is connected in parallel to a coil of induc...

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    A condenser of 250 µF is connected in parallel to a coil of induc...
    Given information:
    - Condenser of 250 F
    - Coil of inductance 0.16 mH and effective resistance 20 W

    To find:
    Resonant frequency in KHz

    Solution:

    1. Resonant Frequency:
    The resonant frequency of an RLC circuit can be calculated using the formula:

    f_res = 1 / (2π√(LC))

    Where:
    f_res = Resonant frequency
    L = Inductance
    C = Capacitance

    2. Capacitive Reactance:
    The capacitive reactance (Xc) of the condenser can be calculated using the formula:

    Xc = 1 / (2πfC)

    Where:
    Xc = Capacitive reactance
    f = Frequency
    C = Capacitance

    3. Inductive Reactance:
    The inductive reactance (Xl) of the coil can be calculated using the formula:

    Xl = 2πfL

    Where:
    Xl = Inductive reactance
    f = Frequency
    L = Inductance

    4. Impedance:
    The impedance (Z) of the RLC circuit can be calculated using the formula:

    Z = √(R^2 + (Xl - Xc)^2)

    Where:
    Z = Impedance
    R = Resistance
    Xl = Inductive reactance
    Xc = Capacitive reactance

    5. Resonance condition:
    At resonance, the capacitive and inductive reactances are equal, i.e., Xl = Xc.

    6. Calculation:
    Using the given values, we can calculate the resonant frequency as follows:

    Xc = 1 / (2πfC)
    Xl = 2πfL

    At resonance, Xl = Xc, so we can equate the above two equations:

    2πfL = 1 / (2πfC)

    Simplifying the equation further:

    f^2 = 1 / (4π^2LC)

    Taking the square root of both sides:

    f = 1 / (2π√(LC))

    Substituting the given values:

    f = 1 / (2π√(0.16 mH * 250 F))
    f ≈ 1 / (2π√(0.16 * 0.00025))
    f ≈ 1 / (2π√(0.00004))
    f ≈ 1 / (2π * 0.00632)
    f ≈ 1 / (0.0398)
    f ≈ 25.13 Hz

    Converting the frequency to KHz:

    f ≈ 25.13 * 10^-3 KHz
    f ≈ 0.02513 KHz

    Therefore, the resonant frequency is approximately 0.02513 KHz or 25.13 Hz.
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    A condenser of 250 µF is connected in parallel to a coil of inductance 0.16 mH and effective resistance 20 W. The resonant frequency will be ______ (give Answer in KHz)Correct answer is '80º KHz'. Can you explain this answer?
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