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LCR series circuit with 100Ω resistance is connected to an AC source of 200V and angular frequency 300 radians per second. When only the capacitance is removed, the current lags behind the voltage by 60°. When only the inductance is removed, the current leads the voltage by 60°. Calculate the average power dissipated in LCR circuit in watts.
    Correct answer is '200'. Can you explain this answer?
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    ALCRseries circuit with100Ωresistance is connected to anACsource...

    Impedance of circuit = R

    The correct answer is: 200
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    ALCRseries circuit with100Ωresistance is connected to anACsource...
    Understanding the LCR Circuit
    In an LCR series circuit, the relationship between voltage and current is influenced by resistance (R), inductance (L), and capacitance (C). Here, we have a 100Ω resistor connected to an AC source of 200V at an angular frequency of 300 radians per second.
    Phase Angles and Impedance
    - When only the capacitance is removed, the current lags the voltage by 60°.
    - When only the inductance is removed, the current leads the voltage by 60°.
    These phase angles indicate that the circuit exhibits both inductive and capacitive characteristics.
    Calculating Impedance
    Using the phase angles:
    - For the inductive case (current leading), the impedance is mainly reactive with a lagging angle.
    - For the capacitive case (current lagging), the impedance is also reactive but with a leading angle.
    Power Factor and Average Power
    The average power (P) dissipated in an LCR circuit can be calculated using the formula:
    P = V * I * cos(ϕ)
    Where:
    - V = voltage (200V)
    - I = current through the circuit
    - cos(ϕ) = power factor
    With the given angles (60°), the power factor is cos(60°) = 0.5.
    Current Calculation
    The current (I) can be calculated using Ohm's law:
    I = V / R = 200V / 100Ω = 2A
    Final Power Calculation
    Now, substituting the values:
    P = 200V * 2A * 0.5 = 200 watts.
    Conclusion
    Thus, the average power dissipated in the LCR circuit is 200 watts, confirming the calculated result.
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    Community Answer
    ALCRseries circuit with100Ωresistance is connected to anACsource...

    Impedance of circuit = R

    The correct answer is: 200
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    ALCRseries circuit with100Ωresistance is connected to anACsource of200Vand angular frequency 300radians per second. When only the capacitance is removed, the current lags behind the voltage by 60°. When only the inductance is removed, the current leads the voltage by 60°. Calculate the average power dissipated inLCRcircuit in watts.Correct answer is '200'. Can you explain this answer?
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    ALCRseries circuit with100Ωresistance is connected to anACsource of200Vand angular frequency 300radians per second. When only the capacitance is removed, the current lags behind the voltage by 60°. When only the inductance is removed, the current leads the voltage by 60°. Calculate the average power dissipated inLCRcircuit in watts.Correct answer is '200'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about ALCRseries circuit with100Ωresistance is connected to anACsource of200Vand angular frequency 300radians per second. When only the capacitance is removed, the current lags behind the voltage by 60°. When only the inductance is removed, the current leads the voltage by 60°. Calculate the average power dissipated inLCRcircuit in watts.Correct answer is '200'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ALCRseries circuit with100Ωresistance is connected to anACsource of200Vand angular frequency 300radians per second. When only the capacitance is removed, the current lags behind the voltage by 60°. When only the inductance is removed, the current leads the voltage by 60°. Calculate the average power dissipated inLCRcircuit in watts.Correct answer is '200'. Can you explain this answer?.
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