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An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere?
Most Upvoted Answer
An ideal inductor takes a current of 10 ampere when connected to a 125...
Given information:
- Current through an ideal inductor (IL) = 10 A
- Voltage across the inductor (VL) = 125 V
- Frequency of the AC supply (f) = 50 Hz
- Current through a pure resistor (IR) = 12.5 A
- Voltage across the resistor (VR) = 125 V
- Voltage across the series combination of the inductor and resistor (Vtotal) = 100 V
- Frequency of the AC supply (f) = 40 Hz
Calculating the inductive reactance:
- In an AC circuit, the inductive reactance (XL) is given by the formula: XL = VL / IL
- Substituting the given values: XL = 125 V / 10 A = 12.5 Ω
Calculating the resistance:
- The resistance (R) can be calculated using Ohm's Law: R = VR / IR
- Substituting the given values: R = 125 V / 12.5 A = 10 Ω
Calculating the total impedance:
- Impedance (Z) in an AC circuit is given by the formula: Z = √(R^2 + XL^2)
- Substituting the calculated values: Z = √(10 Ω^2 + 12.5 Ω^2) ≈ √(100 Ω + 156.25 Ω) ≈ √256.25 Ω ≈ 16.01 Ω
Calculating the total current:
- The total current (Itotal) can be calculated using Ohm's Law: Itotal = Vtotal / Z
- Substituting the given values: Itotal = 100 V / 16.01 Ω ≈ 6.24 A
Conclusion:
The current through the circuit when the inductor and resistor are connected in series across a 100 V, 40 Hz supply is approximately 6.24 A.
- Current through an ideal inductor (IL) = 10 A
- Voltage across the inductor (VL) = 125 V
- Frequency of the AC supply (f) = 50 Hz
- Current through a pure resistor (IR) = 12.5 A
- Voltage across the resistor (VR) = 125 V
- Voltage across the series combination of the inductor and resistor (Vtotal) = 100 V
- Frequency of the AC supply (f) = 40 Hz
Calculating the inductive reactance:
- In an AC circuit, the inductive reactance (XL) is given by the formula: XL = VL / IL
- Substituting the given values: XL = 125 V / 10 A = 12.5 Ω
Calculating the resistance:
- The resistance (R) can be calculated using Ohm's Law: R = VR / IR
- Substituting the given values: R = 125 V / 12.5 A = 10 Ω
Calculating the total impedance:
- Impedance (Z) in an AC circuit is given by the formula: Z = √(R^2 + XL^2)
- Substituting the calculated values: Z = √(10 Ω^2 + 12.5 Ω^2) ≈ √(100 Ω + 156.25 Ω) ≈ √256.25 Ω ≈ 16.01 Ω
Calculating the total current:
- The total current (Itotal) can be calculated using Ohm's Law: Itotal = Vtotal / Z
- Substituting the given values: Itotal = 100 V / 16.01 Ω ≈ 6.24 A
Conclusion:
The current through the circuit when the inductor and resistor are connected in series across a 100 V, 40 Hz supply is approximately 6.24 A.
Community Answer
An ideal inductor takes a current of 10 ampere when connected to a 125...
Crt ans is a). could u explain how
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An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere?
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An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere?.
An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ideal inductor takes a current of 10 ampere when connected to a 125volt, 50 hertz AC supply. A pure resistor across the same source takes 12.5 ampere. If the two are connected in series across a 100volt, 40hertz supply, the current through the circuit will be. a) 7 ampere b) 12.5 ampere c) 20 ampere d) 25 ampere?.
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