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A number consisting of two digits is seven times the sum of its digit. When 27 is subtracted from the number, the digits are reversed. Find the find . How to find it? What is the method to find it.?
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Problem: A number consisting of two digits is seven times the sum of its digits. When 27 is subtracted from the number, the digits are reversed. Find the number.

Solution:

Let the tens digit be x and the units digit be y.

Therefore, the number can be expressed as 10x + y.

According to the problem, we have:

10x + y = 7(x + y) (since the number is seven times the sum of its digits)

Expanding and simplifying the above equation, we get:

3x = 6y

x = 2y

Substituting x = 2y in 10x + y = 7(x + y), we get:

y = 5

Therefore, x = 10 - y = 5

Hence, the original number is 10x + y = 10(5) + 5 = 55.

When 27 is subtracted from the number, we get:

55 - 27 = 28

The digits of 28 are reversed to get the original number 82.

We can verify that 82 is indeed seven times the sum of its digits (8 + 2 = 10 and 7 x 10 = 70).

Therefore, the answer is 55.

Answer: The number is 55.
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A number consisting of two digits is seven times the sum of its digit. When 27 is subtracted from the number, the digits are reversed. Find the find . How to find it? What is the method to find it.?
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