The quotient and remainder are x - 2 and -2x + 4 respectively. If the ...
Given, quotient = x - 2 and remainder = -2x + 4.
So, we know that:
x³ - 3x² + x + 2 = g(x) * (x - 2) - 2x + 4
Let's simplify the right-hand side:
x³ - 3x² + x + 2 = g(x) * x - 2g(x) - 2x + 4
Now, let's rearrange the terms:
x³ - 3x² + x + 2 = g(x) * x - 2x - 2g(x) + 4
x³ - 3x² + x + 2 = (g(x) - 2) * x - 2g(x) + 4
Now, we can equate the coefficients of x², x, and the constant term on both sides to get a system of equations:
Coefficient of x²: -3 = g(x) - 2
Coefficient of x: 1 = g(x)
Constant term: 2 = -2g(x) + 4
Solving the system of equations, we get:
g(x) = 1
-3 = g(x) - 2 = -1
2 = -2g(x) + 4
g(x) = 1
Therefore, the polynomial g(x) is x² - x + 1, which is option C.
The quotient and remainder are x - 2 and -2x + 4 respectively. If the ...
Hey there...
I tried attaching the answer... but it doesnt seem to work... so hope this helps..
Taking the polynomial x3 - 3x2 + x+ 2 as P(x), quotient as q(x), remainder as r(x) and the divisor (which is to be found) as g(x).
Applying,
g(x) = P(x) - r(x)/ q(x)
You will get a polynomial x3- 3x2+ 3x -2/ x-2
On dividing, the remainder to be obtained here must be zero.
The quotient in this case will give you the divisor which was to be found out...
i. e. x2 - x + 1
Hope you find this useful... have a good day..
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