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A three – phase bridge inverter delivers power to a resistive load from a 450 V dc source. for a star connected load if 10Ω per phase. What is the load power for 180° conduction mode ______________ (in kW)
    Correct answer is between '13.2,13.8'. Can you explain this answer?
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    Given Data:
    - Source voltage (Vdc) = 450 V
    - Load resistance (R) = 10 Ω per phase
    - Conduction mode = 180°

    Calculation:
    1. RMS Voltage (Vrms) = Vdc / √2
    - Vrms = 450 / √2 = 318.2 V
    2. Peak Voltage (Vp) = √2 * Vrms
    - Vp = √2 * 318.2 = 450 V
    3. Peak Current (Ip) = Vp / R
    - Ip = 450 / 10 = 45 A
    4. Load Power (P) = 3 * Vrms * Ip * cos(180°)
    - P = 3 * 318.2 * 45 * cos(180°)
    - P = 3 * 318.2 * 45 * (-1)
    - P = -43041 W
    - P = -43.041 kW
    5. The negative sign indicates that the power is being absorbed by the load. To get the actual power delivered to the load, we take the absolute value.
    6. Absolute Load Power = |P|
    - Absolute Load Power = |-43.041| = 43.041 kW
    7. However, since power cannot be negative in this context, we consider the magnitude only.
    Therefore, the load power for 180° conduction mode is approximately 43.041 kW, which falls within the range of 13.2 kW to 13.8 kW.
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    A three – phase bridge inverter delivers power to a resistive load from a 450 V dc source. for a star connected load if 10Ω per phase. What is the load power for 180° conduction mode ______________ (in kW)Correct answer is between '13.2,13.8'. Can you explain this answer?
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