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A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.
Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?  
  • a)
    1.36*10-5
  • b)
    1.96*10-5
  • c)
    1.96*10-1
  • d)
    1.96*10-7
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of wate...
Explanation: Calculate D1m from the equation, D1m=(1-Y1)/(∑〖Yj/Dij〗)
D1m=0.465cm2/s
Use the equation, N1=(D1mC/l)*ln⁡〖(1-Yil)/(1-Y10)〗, where Yil=0(dry air) and Y10=0.023 (17.53/760).
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Most Upvoted Answer
A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of wate...
°C. Assuming ideal gas behavior, what is the partial pressure of hydrogen in the mixture?

To determine the partial pressure of hydrogen, we first need to calculate the total pressure of the mixture. Since the total pressure is given as 1 atm, we can use this information to find the partial pressure of hydrogen.

To find the partial pressure of hydrogen, we need to calculate the mole fraction of hydrogen in the mixture. The mole fraction is calculated by dividing the number of moles of hydrogen by the total number of moles in the mixture.

Let's assume we have 100 moles of the mixture. Since the mixture is 60% hydrogen and 40% oxygen, we have 60 moles of hydrogen and 40 moles of oxygen.

The mole fraction of hydrogen is therefore:

Mole fraction of hydrogen = Number of moles of hydrogen / Total number of moles in the mixture
= 60 / 100
= 0.6

Now that we have the mole fraction of hydrogen, we can calculate the partial pressure of hydrogen using Dalton's Law of Partial Pressures. According to Dalton's Law, the partial pressure of a gas in a mixture is equal to the mole fraction of that gas multiplied by the total pressure of the mixture.

Partial pressure of hydrogen = Mole fraction of hydrogen * Total pressure of the mixture
= 0.6 * 1 atm
= 0.6 atm

Therefore, the partial pressure of hydrogen in the mixture is 0.6 atm.
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A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?a)1.36*10-5b)1.96*10-5c)1.96*10-1d)1.96*10-7Correct answer is option 'B'. Can you explain this answer?
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A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?a)1.36*10-5b)1.96*10-5c)1.96*10-1d)1.96*10-7Correct answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?a)1.36*10-5b)1.96*10-5c)1.96*10-1d)1.96*10-7Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?a)1.36*10-5b)1.96*10-5c)1.96*10-1d)1.96*10-7Correct answer is option 'B'. Can you explain this answer?.
Solutions for A mixture of 60% hydrogen and 40% oxygen is blowing over a pan of water at 1atm pressure. The bulk gas temperature is 30°c and the water temperature is 20°C. The vapor pressure of water at this temperature is 17.53mm Hg. The concentration of moisture in the bulk gas is negligible and the diffusivity values are DO2-H2O=0.357cm2/s,DH2-H2O=0.972cm2/s at 34°C and DH2-O2=0.891cm2/s at 43°C.Q. What is the value of the flux (kmol/m3.s) of water vapor through a stagnant film of estimated thickness 1.5mm on the water surface?a)1.36*10-5b)1.96*10-5c)1.96*10-1d)1.96*10-7Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemical Engineering. Download more important topics, notes, lectures and mock test series for Chemical Engineering Exam by signing up for free.
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