Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >  An electrostatically deflected CRT has plane ... Start Learning for Free
An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.
  • a)
    400 V, 3 × 108 m/s
  • b)
    200 V, 3 × 108 m/s
  • c)
    400 V, 3 × 107 m/s
  • d)
    200 V, 3 × 107 m/s
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An electrostatically deflected CRT has plane parallel deflecting plate...
Given that y = 4 cm
D = 2.5 cm
L = 20 cm
d = 0.5 cm
Va = 2500 V

View all questions of this test
Most Upvoted Answer
An electrostatically deflected CRT has plane parallel deflecting plate...
Given:
Length of deflecting plates (l) = 2.5 cm
Distance between plates (d) = 0.5 cm
Distance of screen from center of plates (D) = 20 cm
Accelerating voltage (V) = 2500 V
Deflection on screen (y) = 4 cm

We know that the deflection produced by the electric field is given by:
y = (Vd)/(2EL)

where E is the electric field strength between the plates and L is the length of the plates.

Rearranging the above equation, we get:
E = (Vd)/(2Ly)

Substituting the given values, we get:
E = (2500 x 0.5)/(2 x 2.5 x 4) = 62.5 V/cm

The deflecting voltage required to produce a deflection y on the screen is given by:
Vd = (2ELy)/d

Substituting the given values, we get:
Vd = (2 x 62.5 x 2.5 x 4)/0.5 = 1250 V

The velocity of the electron beam entering the field can be calculated using the formula:
v = √(2eV/m)

where e is the charge of an electron, V is the accelerating voltage, and m is the mass of the electron.

Substituting the given values, we get:
v = √(2 x 1.6 x 10^-19 x 2500/9.1 x 10^-31) = 3.01 x 10^7 m/s

Therefore, the deflecting voltage required to get the corresponding deflection of 4 cm on the screen is 1250 V and the velocity of the electron beam entering the field is 3.01 x 10^7 m/s.
Explore Courses for Electrical Engineering (EE) exam

Similar Electrical Engineering (EE) Doubts

Top Courses for Electrical Engineering (EE)

An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer?
Question Description
An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer?.
Solutions for An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An electrostatically deflected CRT has plane parallel deflecting plates which are 2.5 cm long and 0.5 cm apart. The distance of the screen form the center of the plates is 20 cm. The accelerating voltage is 2500 V. The deflecting voltage required to get the corresponding deflection of 4 cm on the screen and the velocity of the electron beam entering the field respectively are.a)400 V, 3 × 108m/sb)200 V, 3 × 108m/sc)400 V, 3 × 107m/sd)200 V, 3 × 107m/sCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev