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 For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.
  • a)
    True
  • b)
    False
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For liquid molecular diffusion of A and B, steady state equimolar coun...
Explanation: For equimolar counter diffusion, the one component flux is negative of other.
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For liquid molecular diffusion of A and B, steady state equimolar coun...
Explanation:

Introduction:
Liquid molecular diffusion refers to the process of movement of molecules from an area of high concentration to an area of low concentration. In the case of equimolar counter diffusion, two different species, A and B, diffuse through each other in opposite directions.

Equimolar Counter Diffusion:
Equimolar counter diffusion occurs when two species, A and B, are present in equal molar amounts and diffuse through each other. In this process, the flux of A is equal in magnitude but opposite in direction to the flux of B. This means that if the flux of A is positive, the flux of B will be negative and vice versa.

Steady State:
In steady state diffusion, the concentrations of A and B do not change with time. This means that the flux of A and B will be constant over time. In equimolar counter diffusion, the flux of A and B will be equal in magnitude but opposite in direction, resulting in a net flux of zero.

Negative Flux:
In the given statement, it is mentioned that the net flux of A is negative of the net flux of B. This means that if the flux of A is positive, the flux of B will be negative and vice versa. This is consistent with the concept of equimolar counter diffusion, where the flux of A and B are equal in magnitude but opposite in direction.

Conclusion:
Based on the principles of equimolar counter diffusion and steady state molecular diffusion, the statement that the net flux of A is negative of the net flux of B is true. The flux of A and B will have equal magnitude but opposite direction, resulting in a net flux of zero.
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For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.a)Trueb)FalseCorrect answer is option 'A'. Can you explain this answer?
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