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Two car A and B moves at 54 Km/hr in the same direction and the car B is 300 m ahead of car A. If the car A is accelerated at 6 m/s2 while car B continue to move with the same velocity, calculate the time taken by car A to overtake car B:
  • a)
    10 s
  • b)
    20 s
  • c)
    15 s
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two car A and B moves at 54 Km/hr in the same direction and the car B ...
uA = uB = 54 Km/hr = 15 m/s; aA = 6 m/s2, aB = 0
Car B is 300 m ahead of car A.
Let both move in time t sec.
Distance travelled by A in time t = 300 + Distance travelled by B in time t
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Most Upvoted Answer
Two car A and B moves at 54 Km/hr in the same direction and the car B ...
To solve this problem, we can start by analyzing the motion of the two cars.

Given:
- Car A and Car B are moving in the same direction.
- Car A is initially behind Car B, with a separation distance of 300 meters.
- The velocity of both cars is 54 km/hr.
- Car A is accelerated at a rate of 6 m/s^2.
- Car B continues to move with the same velocity.

We need to find the time taken by Car A to overtake Car B.

Let's break down the problem into steps:

Step 1: Convert the velocity of both cars from km/hr to m/s.
- Velocity of both cars = 54 km/hr = (54 * 1000) / (60 * 60) m/s = 15 m/s

Step 2: Find the relative velocity of Car A with respect to Car B.
- Relative velocity = Velocity of Car A - Velocity of Car B
- Relative velocity = 15 m/s - 15 m/s = 0 m/s

Step 3: Find the time taken by Car A to cover the initial separation distance of 300 meters.
- We can use the equation of motion: s = ut + (1/2)at^2
- Initial velocity of Car A, u = 0 (as Car A starts from rest)
- Acceleration of Car A, a = 6 m/s^2
- Separation distance, s = 300 m
- Time taken, t = ?

Plugging in the values:
300 = 0*t + (1/2)*6*t^2
300 = 3t^2
t^2 = 300/3
t^2 = 100
t = sqrt(100)
t = 10 s

Therefore, Car A will take 10 seconds to cover the initial separation distance of 300 meters.

Step 4: Find the total time taken by Car A to overtake Car B.
- Since the relative velocity is 0 m/s, Car A needs to cover the initial separation distance first and then match the velocity of Car B.
- The time taken to cover the initial separation distance is 10 seconds.
- After that, Car A needs to match the velocity of Car B, which is already moving at 15 m/s.
- So, Car A will take an additional 0 seconds to match the velocity of Car B.

Hence, the total time taken by Car A to overtake Car B is 10 seconds.

Therefore, the correct answer is option 'A' - 10 s.
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Two car A and B moves at 54 Km/hr in the same direction and the car B is 300 m ahead of car A. If the car A is accelerated at 6 m/s2while car B continue to move with the same velocity, calculate the time taken by car A to overtake car B:a)10 sb)20 sc)15 sd)None of theseCorrect answer is option 'A'. Can you explain this answer?
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