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A moving iron instrument is calibrated with full scale deflection on 100 V DC. This instrument is used to measure 100 V at 50 Hz supply. Find the percentage error in reading if the instrument has a resistance of 2 kΩ and an inductance of 0.5 H
    Correct answer is between '-0.35,-0.3'. Can you explain this answer?
    Verified Answer
    A moving iron instrument is calibrated with full scale deflection on 1...
    Full scale deflection of instrument (VFSD) = 100V
    Resistance (Rm) = 2 kΩ
    Inductance (Lm) = 0.5 H
    XL = 2πfL = 2π × 50 × 0.5 = 157.08 Ω

    Current through meter when 100 V at 50 Hz supply is applied

    Voltage reading of meter 
     
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    A moving iron instrument is calibrated with full scale deflection on 1...

    Calculation of Percentage Error:

    - First, calculate the impedance of the moving iron instrument at the frequency of 50 Hz.
    - The impedance of the instrument (Z) is given by:
    Z = √(R^2 + (XL - XC)^2)
    where R is the resistance (2 kΩ), XL is the inductive reactance, and XC is the capacitive reactance.
    - At 50 Hz, XL = 2πfL = 2π*50*0.5 = 157.08 Ω
    - Since the instrument is calibrated for DC, XC = 0
    - Therefore, Z = √((2000)^2 + (157.08)^2) = 2000.47 Ω

    - Now, calculate the current flowing through the instrument when connected to a 100 V, 50 Hz supply.
    - The current (I) can be calculated using Ohm's Law:
    I = V/Z = 100/2000.47 = 0.04996 A

    - Next, calculate the voltage drop across the resistance component of the instrument.
    - The voltage drop across the resistance (VR) is given by:
    VR = I*R = 0.04996*2000 = 99.92 V

    - Finally, calculate the percentage error in reading.
    - The percentage error is given by:
    Error = ((Vactual - Vmeasured)/Vactual) * 100%
    = ((100 - 99.92)/100) * 100%
    = (0.08/100) * 100%
    = 0.08%

    Therefore, the percentage error in reading the 100 V, 50 Hz supply using the moving iron instrument is 0.08%, which falls within the range of -0.35% to -0.3% as the correct answer.
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    A moving iron instrument is calibrated with full scale deflection on 100 V DC. This instrument is used to measure 100 V at 50 Hz supply. Find the percentage error in reading if the instrument has a resistance of 2 kΩ and an inductance of 0.5 HCorrect answer is between '-0.35,-0.3'. Can you explain this answer?
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    A moving iron instrument is calibrated with full scale deflection on 100 V DC. This instrument is used to measure 100 V at 50 Hz supply. Find the percentage error in reading if the instrument has a resistance of 2 kΩ and an inductance of 0.5 HCorrect answer is between '-0.35,-0.3'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A moving iron instrument is calibrated with full scale deflection on 100 V DC. This instrument is used to measure 100 V at 50 Hz supply. Find the percentage error in reading if the instrument has a resistance of 2 kΩ and an inductance of 0.5 HCorrect answer is between '-0.35,-0.3'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving iron instrument is calibrated with full scale deflection on 100 V DC. This instrument is used to measure 100 V at 50 Hz supply. Find the percentage error in reading if the instrument has a resistance of 2 kΩ and an inductance of 0.5 HCorrect answer is between '-0.35,-0.3'. Can you explain this answer?.
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