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The age of a man is twice the square of the age of his daughter. Eight years hence, the age of the man will be 4 years more than 3 times the age of his daughter. Find their present age.?
Most Upvoted Answer
The age of a man is twice the square of the age of his daughter. Eight...
Hey, here is your answer...

Suppose,
Daughter's present age = x years and man's present age = y years..

Then we have,

⇒y = 2x²
⇒y + 8 = 3(x + 8) + 4

substituting value of y from 1st equn. into 2nd equn...

⇒2x² + 8 = 3(x + 8) + 4
⇒2x² - 3x - 20 = 0
⇒(x - 4)(2x + 5) = 0

so,
either x = 4 or -5/2.

since, age cannot be negative,...

so, x = 4 and y = 2(4)² = 32.

That means the current age of daughter is 4 years and that of father is 32 years..

Hope this helps you.
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The age of a man is twice the square of the age of his daughter. Eight...
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The age of a man is twice the square of the age of his daughter. Eight years hence, the age of the man will be 4 years more than 3 times the age of his daughter. Find their present age.?
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