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A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous motor has direct axis synchronous reactance Xd = 1.8 Ω and quadrature axis synchronous reactance Xq = 1.2 Ω. If the armature resistance is negligible and full load power factor is 0.8 log. The power angle is-
    Correct answer is between '-37,-36'. Can you explain this answer?
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    A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous ...

    For logging load in salient pole motor,

    ψ = 0.338°
    δ + ψ = 3.338°
    ⇒ δ = 0.338° - 36.86° = -36.52°
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    A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous ...
    Ohms and quadrature axis synchronous reactance Xq= 1.5 ohms. The stator resistance per phase is 0.1 ohms.

    (a) Calculate the synchronous reactance per phase.

    Synchronous reactance per phase, Xs = √(Xd^2 + Xq^2)
    Xs = √(1.8^2 + 1.5^2) = 2.3 ohms

    (b) Calculate the per phase synchronous impedance.

    Per phase synchronous impedance, Zs = √(R^2 + Xs^2)
    where R is the stator resistance per phase
    Zs = √(0.1^2 + 2.3^2) = 2.3 ohms

    (c) Calculate the per phase voltage induced in the motor at full load when the power factor is 0.8 lagging.

    At full load, the apparent power input to the motor is 60 MVA or 60,000 kVA.
    The per phase apparent power input is 60,000/3 = 20,000 kVA.
    The power factor is 0.8 lagging, so the per phase real power input is 20,000 x 0.8 = 16,000 kW.

    Per phase voltage induced, Vph = (P / (3 x V x cosφ)) + (j x Q / (3 x V x sinφ))
    where V is the line voltage, φ is the phase angle between the voltage and current, and Q is the per phase reactive power.
    At full load, Q = √(S^2 - P^2) = √(20,000^2 - 16,000^2) = 12,649 kVAR
    Vph = (16,000 x 10^3) / (3 x 11 x 10^3 x 0.8) + (j x 12,649 x 10^3 / (3 x 11 x 10^3 x 0.6))
    Vph = 108.7 - j 120.8 kV

    (d) Calculate the per phase current at full load.

    Per phase current, Iph = S / (3 x Vph)
    Iph = 20,000 x 10^3 / (3 x 108.7 x 10^3) = 193.8 A
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    A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous motor has direct axis synchronous reactance Xd= 1.8 Ω and quadrature axis synchronous reactance Xq= 1.2 Ω. If the armature resistance is negligible and full load power factor is 0.8 log. The power angle is-Correct answer is between '-37,-36'. Can you explain this answer?
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    A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous motor has direct axis synchronous reactance Xd= 1.8 Ω and quadrature axis synchronous reactance Xq= 1.2 Ω. If the armature resistance is negligible and full load power factor is 0.8 log. The power angle is-Correct answer is between '-37,-36'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous motor has direct axis synchronous reactance Xd= 1.8 Ω and quadrature axis synchronous reactance Xq= 1.2 Ω. If the armature resistance is negligible and full load power factor is 0.8 log. The power angle is-Correct answer is between '-37,-36'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 60 MVA, 11 kV, 50 Hz, Y connected, 3 phase salient pole synchronous motor has direct axis synchronous reactance Xd= 1.8 Ω and quadrature axis synchronous reactance Xq= 1.2 Ω. If the armature resistance is negligible and full load power factor is 0.8 log. The power angle is-Correct answer is between '-37,-36'. Can you explain this answer?.
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