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A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd = 2Xq = 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________
Correct answer is between '200,210'. Can you explain this answer?
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Verified Answer
A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generat...
= 132.79 × 0.9136 + 75.307 × 4 sin (24 + 45°)
= 121.316 + 281.19
= 402.506
Percentage voltage regulation
Most Upvoted Answer
A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generat...
Given data:
Apparent power, S = 30 KVA
Voltage, V = 230 V
Power factor, cos(θ) = 0.707 lagging
Xd = 2Xq = 4
To find:
1. Real power, P
2. Reactive power, Q
3. Excitation voltage, E
4. Line current, I
Solution:
1. Real power, P = S * cos(θ)
P = 30 * 0.707
P = 21.21 KW
2. Reactive power, Q = S * sin(θ)
Q = 30 * sin(cos⁻¹(0.707))
Q = 21.21 KVAR
3. Excitation voltage, E = V + I * Xd
To find I, we first need to find the apparent power per phase, Sφ.
Sφ = S / √3
Sφ = 30 / √3
Sφ = 17.32 KVA
The impedance per phase, Zφ = V / Sφ
Zφ = 230 / 17.32
Zφ = 13.27 Ω
The reactance per phase, Xφ = Xd / 2
Xφ = 4 / 2
Xφ = 2 Ω
The resistance per phase, Rφ = Zφ / √3
Rφ = 13.27 / √3
Rφ = 7.67 Ω
The impedance triangle per phase is shown below:
|\
Zφ | \ Xφ
| \
|___\
Rφ
Using the impedance triangle, we can find the current per phase, Iφ:
Iφ = Sφ / Zφ
Iφ = 17.32 / 13.27
Iφ = 1.305 A
Now, we can find the excitation voltage per phase:
Eφ = V + Iφ * Xd
Eφ = 230 + 1.305 * 4
Eφ = 235.22 V
The line voltage, Vline = √3 * V
Vline = √3 * 230
Vline = 397.96 V
The excitation voltage per phase is also the line voltage, so:
E = Vline = 235.22 V
4. Line current, Iline = S / (√3 * V * power factor)
Iline = 30 / (√3 * 230 * 0.707)
Iline = 62.08 A
Therefore, the real power supplied by the generator is 21.21 KW, the reactive power supplied is 21.21 KVAR, the excitation voltage is 235.22 V, and the line current is 62.08 A.
Apparent power, S = 30 KVA
Voltage, V = 230 V
Power factor, cos(θ) = 0.707 lagging
Xd = 2Xq = 4
To find:
1. Real power, P
2. Reactive power, Q
3. Excitation voltage, E
4. Line current, I
Solution:
1. Real power, P = S * cos(θ)
P = 30 * 0.707
P = 21.21 KW
2. Reactive power, Q = S * sin(θ)
Q = 30 * sin(cos⁻¹(0.707))
Q = 21.21 KVAR
3. Excitation voltage, E = V + I * Xd
To find I, we first need to find the apparent power per phase, Sφ.
Sφ = S / √3
Sφ = 30 / √3
Sφ = 17.32 KVA
The impedance per phase, Zφ = V / Sφ
Zφ = 230 / 17.32
Zφ = 13.27 Ω
The reactance per phase, Xφ = Xd / 2
Xφ = 4 / 2
Xφ = 2 Ω
The resistance per phase, Rφ = Zφ / √3
Rφ = 13.27 / √3
Rφ = 7.67 Ω
The impedance triangle per phase is shown below:
|\
Zφ | \ Xφ
| \
|___\
Rφ
Using the impedance triangle, we can find the current per phase, Iφ:
Iφ = Sφ / Zφ
Iφ = 17.32 / 13.27
Iφ = 1.305 A
Now, we can find the excitation voltage per phase:
Eφ = V + Iφ * Xd
Eφ = 230 + 1.305 * 4
Eφ = 235.22 V
The line voltage, Vline = √3 * V
Vline = √3 * 230
Vline = 397.96 V
The excitation voltage per phase is also the line voltage, so:
E = Vline = 235.22 V
4. Line current, Iline = S / (√3 * V * power factor)
Iline = 30 / (√3 * 230 * 0.707)
Iline = 62.08 A
Therefore, the real power supplied by the generator is 21.21 KW, the reactive power supplied is 21.21 KVAR, the excitation voltage is 235.22 V, and the line current is 62.08 A.
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A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer?
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A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer?.
A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 30 KVA, 230 V, Y connected, 3 phase salient pale synchronous generator supplies rated load at 0.707 lagging power factor. The reactance per phase are Xd= 2Xq= 4 Ω. Neglect the armature resistance determine The percentage voltage regulation__________Correct answer is between '200,210'. Can you explain this answer?.
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