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A long shunt compound wound motor is having shunt field resistance, series field resistance and armature resistance of 300 Ω, 0.8 Ω and 0.6 Ω respectively. If the motor is drawings 60 A at 500 V, what is the voltage drop across series field resistance?
  • a)
    48.5 V
  • b)
    46.66 V
  • c)
    36.73 V
  • d)
    35.86 V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A long shunt compound wound motor is having shunt field resistance, se...
Long shunt motor circuit is given as

Current through shunt field = 500/300 = 1.67 A 
∴ Armature current Ia = 58.33A
Voltage across series field resistance
= 58.33 × 0.8
= 46.664 V
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Most Upvoted Answer
A long shunt compound wound motor is having shunt field resistance, se...
Ohms, 100 ohms, and 50 ohms respectively. The shunt field current is 2A and the armature current is 10A. Calculate the terminal voltage of the motor.

To calculate the terminal voltage of the motor, we need to consider the voltage drops across the shunt field resistance, series field resistance, and armature resistance.

Voltage drop across the shunt field resistance (Vsh) = shunt field current (Ish) * shunt field resistance (Rsh)
Vsh = 2A * 300 ohms = 600V

Voltage drop across the series field resistance (Vs) = series field current (Is) * series field resistance (Rs)
The series field current is the same as the armature current, so
Vs = 10A * 100 ohms = 1000V

Voltage drop across the armature resistance (Va) = armature current (Ia) * armature resistance (Ra)
Va = 10A * 50 ohms = 500V

The terminal voltage (Vt) is the sum of the voltage drops:
Vt = Vsh + Vs + Va
Vt = 600V + 1000V + 500V
Vt = 2100V

Therefore, the terminal voltage of the motor is 2100V.
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A long shunt compound wound motor is having shunt field resistance, series field resistance and armature resistance of 300 Ω, 0.8 Ω and 0.6 Ω respectively. If the motor is drawings 60 A at 500 V, what is the voltage drop across series field resistance?a)48.5 Vb)46.66 Vc)36.73 Vd)35.86 VCorrect answer is option 'B'. Can you explain this answer?
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A long shunt compound wound motor is having shunt field resistance, series field resistance and armature resistance of 300 Ω, 0.8 Ω and 0.6 Ω respectively. If the motor is drawings 60 A at 500 V, what is the voltage drop across series field resistance?a)48.5 Vb)46.66 Vc)36.73 Vd)35.86 VCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A long shunt compound wound motor is having shunt field resistance, series field resistance and armature resistance of 300 Ω, 0.8 Ω and 0.6 Ω respectively. If the motor is drawings 60 A at 500 V, what is the voltage drop across series field resistance?a)48.5 Vb)46.66 Vc)36.73 Vd)35.86 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A long shunt compound wound motor is having shunt field resistance, series field resistance and armature resistance of 300 Ω, 0.8 Ω and 0.6 Ω respectively. If the motor is drawings 60 A at 500 V, what is the voltage drop across series field resistance?a)48.5 Vb)46.66 Vc)36.73 Vd)35.86 VCorrect answer is option 'B'. Can you explain this answer?.
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