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The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)
- a)1.25 m/s
- b)1.67 m/s
- c)2.00 m/s
- d)2.50 m/s
Correct answer is option 'B'. Can you explain this answer?
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The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The...
Depth of flow = D/2
Wetted area of the sewer (A)
Wetted perimeter (P) = πD/2
Hydraulic mean radius (R) = A/P = D/4
Velocity or flow rate through the sewer,
Most Upvoted Answer
The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The...
's roughness coefficient as 0.013)
We can use the Manning's formula to calculate the flow rate of the sewer:
Q = (1.49/n) * A * R^(2/3) * S^(1/2)
where Q is the flow rate (m^3/s), n is Manning's roughness coefficient (0.013), A is the cross-sectional area of the sewer (m^2), R is the hydraulic radius (m), and S is the slope of the sewer (1 in 900).
First, we need to calculate the cross-sectional area of the sewer. Since the diameter is 4 m, the radius is 2 m. The cross-sectional area of a circle is A = pi * r^2, so:
A = pi * (2)^2 = 12.57 m^2
Next, we need to calculate the hydraulic radius, which is the ratio of the cross-sectional area to the wetted perimeter. Since the sewer is running half full, the wetted perimeter is half the circumference of the circle:
P = pi * d * H
where d is the diameter (4 m) and H is the hydraulic depth (2 m). Therefore:
P = pi * 4 * 2/2 = 12.57 m
The hydraulic radius is then:
R = A / P = 12.57 / 12.57 = 1 m
Finally, we can calculate the flow rate using the Manning's formula:
Q = (1.49/0.013) * 12.57 * 1^(2/3) * (1/900)^(1/2) = 0.53 m^3/s
Therefore, the flow rate of the sewer when running half full is 0.53 m^3/s.
We can use the Manning's formula to calculate the flow rate of the sewer:
Q = (1.49/n) * A * R^(2/3) * S^(1/2)
where Q is the flow rate (m^3/s), n is Manning's roughness coefficient (0.013), A is the cross-sectional area of the sewer (m^2), R is the hydraulic radius (m), and S is the slope of the sewer (1 in 900).
First, we need to calculate the cross-sectional area of the sewer. Since the diameter is 4 m, the radius is 2 m. The cross-sectional area of a circle is A = pi * r^2, so:
A = pi * (2)^2 = 12.57 m^2
Next, we need to calculate the hydraulic radius, which is the ratio of the cross-sectional area to the wetted perimeter. Since the sewer is running half full, the wetted perimeter is half the circumference of the circle:
P = pi * d * H
where d is the diameter (4 m) and H is the hydraulic depth (2 m). Therefore:
P = pi * 4 * 2/2 = 12.57 m
The hydraulic radius is then:
R = A / P = 12.57 / 12.57 = 1 m
Finally, we can calculate the flow rate using the Manning's formula:
Q = (1.49/0.013) * 12.57 * 1^(2/3) * (1/900)^(1/2) = 0.53 m^3/s
Therefore, the flow rate of the sewer when running half full is 0.53 m^3/s.
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The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer?
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The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer?.
The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The diameter of circular sewer laid at a slope of 1 in 900 is 4 m. The flow rate of the sewer when running half full will be (take Manning’s coefficient, n = 0.02)a)1.25 m/sb)1.67 m/sc)2.00 m/sd)2.50 m/sCorrect answer is option 'B'. Can you explain this answer?.
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