Explanation:

In this question, we are given a group of numbers and letters and we need to identify the one that does not belong to the group. Let's analyze each option:

a) 1P6
b) 2Y4
c) 2T0
d) 1R8
e) 1M3

To find the odd one out, we need to look for a pattern or similarity among the options.

Pattern Analysis:

Looking at the options, we can identify that all the options consist of a combination of a number, a letter, and another number. The first and third characters in each option are numbers, while the second character is a letter.

Identifying the Odd One Out:

Now, let's analyze each option individually to find the odd one out:

a) 1P6: The first character is '1', the second character is 'P' (a letter), and the third character is '6' (a number). This option follows the pattern.

b) 2Y4: The first character is '2', the second character is 'Y' (a letter), and the third character is '4' (a number). This option follows the pattern.

c) 2T0: The first character is '2', the second character is 'T' (a letter), and the third character is '0' (a number). This option follows the pattern.

d) 1R8: The first character is '1', the second character is 'R' (a letter), and the third character is '8' (a number). This option follows the pattern.

e) 1M3: The first character is '1', the second character is 'M' (a letter), and the third character is '3' (a number). This option follows the pattern.

Conclusion:

Upon analyzing all the given options, we can observe that all the options follow the same pattern of having a number, a letter, and another number. Therefore, the option '2Y4' is the odd one out as it also follows the pattern but is different from the rest of the options.