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Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.
  • a)
    452.2N/mm²
  • b)
    468.6N/mm²
  • c)
    512.2N/mm²
  • d)
    None of the listed 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Find the shear stress in the spring wire used to design a helical comp...
Explanation: τ=K x 8PC/πd² where K=[4C-1/4C-4]+0.615/C.
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Most Upvoted Answer
Find the shear stress in the spring wire used to design a helical comp...
To find the shear stress in the spring wire, we can use the formula:

Shear stress = Load / (Wire diameter * Number of active coils * Spring index)

Given:
Load = 1200 N
Wire diameter = 7 mm
Spring index = 6

First, we need to calculate the number of active coils. The number of active coils can be calculated using the formula:

Number of active coils = Total number of coils - Number of inactive coils

Since it is a helical compression spring, the number of inactive coils is given by:

Number of inactive coils = (Wire diameter) / (Mean coil diameter)

The mean coil diameter can be calculated using the formula:

Mean coil diameter = Outside diameter - Wire diameter

Given:
Spring index = 6
Wire diameter = 7 mm

We can assume the outside diameter to be 7 times the wire diameter:

Outside diameter = Spring index * Wire diameter = 6 * 7 mm = 42 mm

Now we can calculate the mean coil diameter:

Mean coil diameter = Outside diameter - Wire diameter = 42 mm - 7 mm = 35 mm

Now we can calculate the number of inactive coils:

Number of inactive coils = Wire diameter / Mean coil diameter = 7 mm / 35 mm = 0.2

Since the number of inactive coils cannot be a decimal, we can round it up to 1. Therefore, the number of inactive coils is 1.

Now we can calculate the number of active coils:

Number of active coils = Total number of coils - Number of inactive coils = Total number of coils - 1

To find the total number of coils, we can use the formula:

Total number of coils = Spring index * Number of active coils

Given:
Spring index = 6
Number of active coils = Total number of coils - 1

We need to solve these two equations simultaneously to find the number of active coils:

Number of active coils = 6 * Number of active coils - 1

Simplifying the equation:

5 * Number of active coils = 1

Number of active coils = 1 / 5 = 0.2

Since the number of active coils cannot be a decimal, we can round it up to 1. Therefore, the number of active coils is 1.

Now we can calculate the shear stress:

Shear stress = Load / (Wire diameter * Number of active coils * Spring index)
Shear stress = 1200 N / (7 mm * 1 * 6)
Shear stress = 1200 N / 42 mm
Shear stress = 28.57 N/mm

Therefore, the shear stress in the spring wire is approximately 28.57 N/mm.
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Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.a)452.2N/mm²b)468.6N/mm²c)512.2N/mm²d)None of the listedCorrect answer is option 'B'. Can you explain this answer?
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Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.a)452.2N/mm²b)468.6N/mm²c)512.2N/mm²d)None of the listedCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.a)452.2N/mm²b)468.6N/mm²c)512.2N/mm²d)None of the listedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.a)452.2N/mm²b)468.6N/mm²c)512.2N/mm²d)None of the listedCorrect answer is option 'B'. Can you explain this answer?.
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