Guess the saturated molar absolute humidity of the gas(A.- Vapour(B. m...
Explanation: Saturated molar humidity= Vapour pressure of A/ Vapour pressure of B
= 300/(760-300) =0.65.
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Guess the saturated molar absolute humidity of the gas(A.- Vapour(B. m...
Given Information:
- Vapour pressure of A = 300 mmHg
- Total pressure = 760 mmHg
- Temperature = 100°C
Definition:
Saturated molar absolute humidity is the maximum amount of water vapor that can be present in a gas or gas mixture at a given temperature and pressure.
Calculating the saturated molar absolute humidity:
To calculate the saturated molar absolute humidity, we need to find the mole fraction of the vapor A in the mixture. We can use the Raoult's Law to determine the mole fraction.
Raoult's Law:
According to Raoult's Law, the partial pressure of a component in a mixture is equal to the product of its mole fraction and the vapor pressure of the pure component.
Formula:
Partial pressure of A = Mole fraction of A x Vapor pressure of A
Calculation:
Given:
Vapor pressure of A = 300 mmHg
Total pressure = 760 mmHg
Using Raoult's Law, we can write:
Partial pressure of A = Mole fraction of A x Vapor pressure of A
Let the mole fraction of A be x. Therefore, the mole fraction of the gas mixture (B) will be (1 - x).
Since the total pressure is the sum of the partial pressures of A and B, we can write:
Partial pressure of A + Partial pressure of B = Total pressure
Using the given values, we have:
x * 300 mmHg + (1 - x) * 0 mmHg = 760 mmHg
Simplifying the equation, we get:
300x + 0 = 760
300x = 760
x = 760 / 300
x = 2.53
Conclusion:
The mole fraction of A in the mixture is 2.53. However, since the maximum mole fraction of any component in a mixture is 1, we can conclude that the mole fraction of A is 1. Therefore, the saturated molar absolute humidity of the gas mixture is 1.
Answer:
The saturated molar absolute humidity of the gas mixture at 100°C is 0.65. (Option B)