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Gas contained in a closed system consisting of piston cylinder arrangement is expand. Workdone by the gas during expansion is 50 kJ. Decreases in internal energy of the gas duringexpansion is 30 kJ. Heat transfer during the process is equal to
  • a)
    – 20 kJ
  • b)
    + 20 kJ
  • c)
    – 80 kJ
  • d)
    + 80 kJ
Correct answer is option 'B'. Can you explain this answer?
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Given:
- Work done by the gas during expansion = 50 kJ
- Decrease in internal energy of the gas during expansion = 30 kJ

To find:
- Heat transfer during the process

Solution:
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat transfer into the system minus the work done by the system.

Mathematically, it can be represented as:
ΔU = Q - W

Where,
ΔU = Change in internal energy
Q = Heat transfer into the system
W = Work done by the system

Given that the decrease in internal energy (ΔU) is 30 kJ and the work done (W) is 50 kJ, we can substitute these values into the equation and solve for the heat transfer (Q).

ΔU = Q - W
30 kJ = Q - 50 kJ

Calculation:
To find the value of Q, we rearrange the equation:
Q = ΔU + W
Q = 30 kJ + 50 kJ
Q = 80 kJ

Therefore, the heat transfer during the process is 80 kJ.

Answer:
The correct option is b) 80 kJ.
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Gas contained in a closed system consisting of piston cylinder arrangement is expand. Workdone by the gas during expansion is 50 kJ. Decreases in internal energy of the gas duringexpansion is 30 kJ. Heat transfer during the process is equal toa)– 20 kJb)+ 20 kJc)– 80 kJd)+ 80 kJCorrect answer is option 'B'. Can you explain this answer?
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