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The leakage current of a transistor with usual notation are ICEO = 410 μA, ICBO = 5 μA, and IB = 30μA. Calculate the IC ________mA
    Correct answer is between '2.8,2.9'. Can you explain this answer?
    Verified Answer
    The leakage current of a transistor with usual notation are ICEO= 410 ...
    ICEO = 410 μA, ICBO = 5 μA, IB = 30 μA
    IC­ = βIB + (1 + β) ICBO
    ICEO = (1 + β) ICBO
    410 = (1 + β)5
    β = 81
    IC = 81 × 30 + 82 × 5
    IC = 2.84 mA
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    Most Upvoted Answer
    The leakage current of a transistor with usual notation are ICEO= 410 ...
    The given information is incomplete. The leakage current of a transistor is usually specified in terms of ICEO (Collector-Emitter Leakage Current when the Base-Emitter junction is open), ICBO (Collector-Base Leakage Current when the Emitter-Base junction is open), or ICEO (Collector-Emitter Leakage Current when the Base-Emitter junction is reverse biased). The value provided (410) is not sufficient to determine the leakage current. Please provide the complete information or specify the type of leakage current you are referring to.
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    The leakage current of a transistor with usual notation are ICEO= 410 μA, ICBO= 5 μA, and IB= 30μA. Calculate the IC________mACorrect answer is between '2.8,2.9'. Can you explain this answer?
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