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A 6 pole slip ring induction motor operating on 50 Hz supply is driven by a variable speed prime mover as a frequency changer. If it is operated at 1500 rpm is opposite direction then the supply frequency generated is – (in Hz)
Correct answer is '125'. Can you explain this answer?
Verified Answer
A 6 pole slip ring induction motor operating on 50 Hz supply is driven...
General equation for the frequency of an induction frequency changer is
+ve for opposite direction of rotation
-ve for same direction of rotation
1000 rpm
= 125 HzMost Upvoted Answer
A 6 pole slip ring induction motor operating on 50 Hz supply is driven...
25 Hz.
Explanation:
The synchronous speed of a 6 pole induction motor operated on 50 Hz supply is:
Ns = (120 x f) / P = (120 x 50) / 6 = 1000 rpm
Since the motor is driven at 1500 rpm in the opposite direction, the actual speed of the rotor is:
N = Ns - Nr = 1000 - 1500 = -500 rpm
The slip of the motor is given by:
s = (Ns - N) / Ns = (1000 + 500) / 1000 = 1.5
The frequency generated by the slip ring is given by:
f = s x fsupply = 1.5 x 50 = 75 Hz
However, since the motor is operated in the opposite direction, the frequency generated is:
f = fsupply - fslip = 50 - 75 = -25 Hz
Since negative frequency is not physically possible, we take the absolute value:
|f| = 25 Hz
Therefore, the supply frequency generated by the slip ring motor is 25 Hz.
Explanation:
The synchronous speed of a 6 pole induction motor operated on 50 Hz supply is:
Ns = (120 x f) / P = (120 x 50) / 6 = 1000 rpm
Since the motor is driven at 1500 rpm in the opposite direction, the actual speed of the rotor is:
N = Ns - Nr = 1000 - 1500 = -500 rpm
The slip of the motor is given by:
s = (Ns - N) / Ns = (1000 + 500) / 1000 = 1.5
The frequency generated by the slip ring is given by:
f = s x fsupply = 1.5 x 50 = 75 Hz
However, since the motor is operated in the opposite direction, the frequency generated is:
f = fsupply - fslip = 50 - 75 = -25 Hz
Since negative frequency is not physically possible, we take the absolute value:
|f| = 25 Hz
Therefore, the supply frequency generated by the slip ring motor is 25 Hz.
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Community Answer
A 6 pole slip ring induction motor operating on 50 Hz supply is driven...
Here Ns=120f/p
Ns=(120*50)/6=1000rpm
S=(Ns-Nr)/Nr=1000-(-1500)/1000=2.5
fr=Sf2=2.5*50=125Hz
Ns=(120*50)/6=1000rpm
S=(Ns-Nr)/Nr=1000-(-1500)/1000=2.5
fr=Sf2=2.5*50=125Hz
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A 6 pole slip ring induction motor operating on 50 Hz supply is driven by a variable speed prime mover as a frequency changer. If it is operated at 1500 rpm is opposite direction then the supply frequency generated is – (in Hz)Correct answer is '125'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 6 pole slip ring induction motor operating on 50 Hz supply is driven by a variable speed prime mover as a frequency changer. If it is operated at 1500 rpm is opposite direction then the supply frequency generated is – (in Hz)Correct answer is '125'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6 pole slip ring induction motor operating on 50 Hz supply is driven by a variable speed prime mover as a frequency changer. If it is operated at 1500 rpm is opposite direction then the supply frequency generated is – (in Hz)Correct answer is '125'. Can you explain this answer?.
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