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Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.
Correct answer is '18'. Can you explain this answer?
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Consider an instruction pipeline in which a total of 5 cycles is requi...
k = 5
Sk = 3.75
ττ = 300 picosecond = 0.3 ns
The time required to execute n instructions without pipeline = T1 = nkτnkτ
The time required to execute n instructions with pipeline = Tk = [k + (n – 1)]τ
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Consider an instruction pipeline in which a total of 5 cycles is requi...
The pipeline. This means that it takes a total of 5 cycles for the first instruction to go through all stages of the pipeline and complete its execution.
Assuming that the pipeline is fully utilized and has a steady stream of instructions, we can calculate the number of instructions that can be completed in a given number of cycles.
If it takes 5 cycles to complete the first instruction, then in the next cycle (cycle 6), the first instruction will be completed and the second instruction will be in its final stage of execution. In cycle 7, the second instruction will be completed and the third instruction will be in its final stage, and so on.
Therefore, in cycle 5, we have completed 1 instruction.
In cycle 6, we have completed 2 instructions.
In cycle 7, we have completed 3 instructions.
In cycle 8, we have completed 4 instructions.
In cycle 9, we have completed 5 instructions.
So, in 5 cycles, we can complete 5 instructions.
In general, if it takes n cycles to complete the first instruction, then in n cycles, we can complete n instructions.
Assuming that the pipeline is fully utilized and has a steady stream of instructions, we can calculate the number of instructions that can be completed in a given number of cycles.
If it takes 5 cycles to complete the first instruction, then in the next cycle (cycle 6), the first instruction will be completed and the second instruction will be in its final stage of execution. In cycle 7, the second instruction will be completed and the third instruction will be in its final stage, and so on.
Therefore, in cycle 5, we have completed 1 instruction.
In cycle 6, we have completed 2 instructions.
In cycle 7, we have completed 3 instructions.
In cycle 8, we have completed 4 instructions.
In cycle 9, we have completed 5 instructions.
So, in 5 cycles, we can complete 5 instructions.
In general, if it takes n cycles to complete the first instruction, then in n cycles, we can complete n instructions.
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Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer?
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Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer?.
Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer?.
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Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer?, a detailed solution for Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? has been provided alongside types of Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider an instruction pipeline in which a total of 5 cycles is required to complete the execution of the first instruction out of ‘n’ instructions. The speed up factor for the instruction execution without the pipeline compared to instruction pipeline is 3.75. Find the time (in nanoseconds) required to execute ‘n’ instructions without pipeline if maximum stage delay is 300 picoseconds.Correct answer is '18'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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