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The radius of gyration of rectangular section (depth D, width B) from a centroidal axis parallel to the width is
  • a)
    D/2
  • b)
    D/√3
  • c)
    D/(2√3)
  • d)
    D/(4√3)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The radius of gyration of rectangular section (depth D, width B) from ...
Radius of gyration is given by:
I = Moment of inertia about C.G
A = Area of the x-section
A = BD
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Most Upvoted Answer
The radius of gyration of rectangular section (depth D, width B) from ...
The correct answer is (b) D/√3.

The radius of gyration, k, is given by the formula:

k = √(I/A)

where I is the second moment of area about the centroidal axis and A is the area of the section.

For a rectangular section with depth D and width B, the second moment of area about an axis parallel to the width is:

I = (B*D^3)/12

And the area of the section is:

A = B*D

Substituting these values into the formula for k, we get:

k = √((B*D^3)/12)/(B*D)

Simplifying this expression, we get:

k = D/√3

Therefore, the answer is (b) D/√3.
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The radius of gyration of rectangular section (depth D, width B) from a centroidal axis parallel to the width isa)D/2b)D/√3c)D/(2√3)d)D/(4√3)Correct answer is option 'C'. Can you explain this answer?
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