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The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.
Correct answer is between '7,8'. Can you explain this answer?
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Verified Answer
The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transfor...
Output at ¾ full load and unit power factor =
Total loss = 420.92 – 412.5 = 8.42 KW
Loss is equally divided b/w iron and copper loss
Copper loss = 7.48299
Percentage resistance = 
Percentage impedance = 10%
Percentage reactance = 
∴ Percentage regulation = 
= 1.74 × 0.8 + 9.84 × 0.6
= 1.392 + 5.91 = 7.30%
Most Upvoted Answer
The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transfor...
A certain load. The load at which the maximum efficiency occurs can be calculated using the following formula:
Load at maximum efficiency = (Rated output × √Maximum efficiency) ÷ √3 × Rated voltage
Where:
Rated output = 550 KVA
Maximum efficiency = 98% (expressed as a decimal, i.e. 0.98)
Rated voltage = 3300 V
Load at maximum efficiency = (550 × 0.98^(1/2)) ÷ (√3 × 3300)
Load at maximum efficiency = 172.4 A
Therefore, the load at which the maximum efficiency of the transformer occurs is 172.4 A.
Load at maximum efficiency = (Rated output × √Maximum efficiency) ÷ √3 × Rated voltage
Where:
Rated output = 550 KVA
Maximum efficiency = 98% (expressed as a decimal, i.e. 0.98)
Rated voltage = 3300 V
Load at maximum efficiency = (550 × 0.98^(1/2)) ÷ (√3 × 3300)
Load at maximum efficiency = 172.4 A
Therefore, the load at which the maximum efficiency of the transformer occurs is 172.4 A.
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The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer?
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The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer?.
The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum efficiency of 550 KVA, 3300/430 V, 50 Hz 1 ϕ transformer is 98% and occurs at ¾ full load, unity power factor. If the impedance is 10%, calculate the regulation (in %) at full load at 0.8 P.F lagging.Correct answer is between '7,8'. Can you explain this answer?.
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