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A single-phase full bridge inverter Is fed from a dc source such that fundamental. Component of output voltage is 230 V. Find the R.M.S value of diode current. For the following loads: R = 2 Ω, XL= 8 Ω, XC = 6 Ω
Correct answer is between '17,18'. Can you explain this answer?
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A single-phase full bridge inverter Isfed from a dc source such that f...
= 81.317 A
R.M.S value of diode current
= 0.1507 × √2 × 81.317 = 17.328 A
Most Upvoted Answer
A single-phase full bridge inverter Isfed from a dc source such that f...
Since the inverter is a single-phase full bridge inverter, it uses four diodes in a bridge configuration. The output voltage is a square wave with a peak value of 230 V.
For a resistive load of R = 2 Ω, the current through the load can be calculated as:
I = V/R = 230/2 = 115 A
Since the load current flows through two diodes at any given time, the diode current can be calculated as:
Id = I/2 = 115/2 = 57.5 A
The RMS value of the diode current can then be calculated as:
Irms = Id/sqrt(2) = 57.5/sqrt(2) = 40.68 A
Therefore, the RMS value of the diode current for a resistive load of R = 2 Ω is approximately 40.68 A.
For a resistive load of R = 2 Ω, the current through the load can be calculated as:
I = V/R = 230/2 = 115 A
Since the load current flows through two diodes at any given time, the diode current can be calculated as:
Id = I/2 = 115/2 = 57.5 A
The RMS value of the diode current can then be calculated as:
Irms = Id/sqrt(2) = 57.5/sqrt(2) = 40.68 A
Therefore, the RMS value of the diode current for a resistive load of R = 2 Ω is approximately 40.68 A.
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A single-phase full bridge inverter Isfed from a dc source such that fundamental. Component of output voltage is 230 V. Find the R.M.S value of diode current. For the following loads: R = 2 Ω, XL= 8 Ω, XC= 6 ΩCorrect answer is between '17,18'. Can you explain this answer?
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A single-phase full bridge inverter Isfed from a dc source such that fundamental. Component of output voltage is 230 V. Find the R.M.S value of diode current. For the following loads: R = 2 Ω, XL= 8 Ω, XC= 6 ΩCorrect answer is between '17,18'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase full bridge inverter Isfed from a dc source such that fundamental. Component of output voltage is 230 V. Find the R.M.S value of diode current. For the following loads: R = 2 Ω, XL= 8 Ω, XC= 6 ΩCorrect answer is between '17,18'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase full bridge inverter Isfed from a dc source such that fundamental. Component of output voltage is 230 V. Find the R.M.S value of diode current. For the following loads: R = 2 Ω, XL= 8 Ω, XC= 6 ΩCorrect answer is between '17,18'. Can you explain this answer?.
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