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A single-phase bridge inverter delivers power to a series connected RLC load with R=20, and L = 100. The periodic time. T = 0.1 msec. What value of C should the load have in order to obtain load commutation for the SCRs. The thyristor turn-off time is 10µsec. Take circuit turn off time as 1.5 t₁. Assume that load current contains only fundamental component?
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A single-phase bridge inverter delivers power to a series connected RL...
Understanding Load Commutation in a Series RLC Circuit
To achieve load commutation for the SCRs in a series RLC load, specific conditions regarding the capacitance (C) need to be satisfied.
Given Parameters
- Resistance, R = 20 Ohms
- Inductance, L = 100 mH
- Periodic time, T = 0.1 ms
- Thyristor turn-off time = 10 µs
- Circuit turn-off time = 1.5 * t₁
Calculating Time Periods
- The fundamental frequency (f) can be determined as:
- f = 1/T = 10 kHz
- The time period for the fundamental component (t₁) is:
- t₁ = 1/f = 0.1 ms = 100 µs
Determine the Circuit Turn-off Time
- Therefore, the circuit turn-off time is:
- Circuit turn-off time = 1.5 * t₁ = 1.5 * 100 µs = 150 µs
Reactance and Impedance Calculations
- To ensure proper commutation, we need to establish the relationship between R, L, and C. The total impedance Z can be determined as:
- Z = √(R² + (ωL - 1/ωC)²)
Where ω = 2πf.
- The load current should ideally return to zero within the thyristor turn-off time.
Finding Capacitance (C)
- The following condition must hold for successful commutation:
- t₁ ≥ R/C (where R is the resistance)
- Rearranging gives us:
- C = R * (1/t₁)
- Substituting R = 20 Ohms and t₁ = 100 µs:
- C = 20 * (1/100 µs) = 200 nF
Conclusion
To ensure load commutation for the SCRs, the capacitance (C) of the load should be approximately 200 nF. This arrangement guarantees the load current returns to zero within the specified time frame, allowing for reliable operation of the thyristors.
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A single-phase bridge inverter delivers power to a series connected RLC load with R=20, and L = 100. The periodic time. T = 0.1 msec. What value of C should the load have in order to obtain load commutation for the SCRs. The thyristor turn-off time is 10µsec. Take circuit turn off time as 1.5 t₁. Assume that load current contains only fundamental component?
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A single-phase bridge inverter delivers power to a series connected RLC load with R=20, and L = 100. The periodic time. T = 0.1 msec. What value of C should the load have in order to obtain load commutation for the SCRs. The thyristor turn-off time is 10µsec. Take circuit turn off time as 1.5 t₁. Assume that load current contains only fundamental component? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase bridge inverter delivers power to a series connected RLC load with R=20, and L = 100. The periodic time. T = 0.1 msec. What value of C should the load have in order to obtain load commutation for the SCRs. The thyristor turn-off time is 10µsec. Take circuit turn off time as 1.5 t₁. Assume that load current contains only fundamental component? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase bridge inverter delivers power to a series connected RLC load with R=20, and L = 100. The periodic time. T = 0.1 msec. What value of C should the load have in order to obtain load commutation for the SCRs. The thyristor turn-off time is 10µsec. Take circuit turn off time as 1.5 t₁. Assume that load current contains only fundamental component?.
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