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 In industries titanium is hardened through diffusion of carbon. The concentration of carbon at 1mm into the surface of the titanium slab is 0.25kg/m3 and at 3mm the concentration is 0.68kg/m3. The rate at which the carbon is entering into its surface is 1.27*10-9kg/m2.s. calculate the value of diffusion coefficient of carbon. 
  • a)
    5.91*10-12
  • b)
    5.91*10-10
  • c)
    5.91*10-11
  • d)
    5.91*10-13
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In industries titanium is hardened through diffusion of carbon. The co...
Explanation: J=-D(∂C/∂x)
∂C/∂x= Δc/Δx=(0.25-0.68)/(0.003-0.001)=-215kg/m4
1.27*10-19kg/m2.s= -D*(-215kg/m4)
D=5.91*10-12m2/s.
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In industries titanium is hardened through diffusion of carbon. The co...
Given Data:
Concentration at 1mm, c1 = 0.25 kg/m³
Concentration at 3mm, c2 = 0.68 kg/m³
Rate of carbon entering surface, J = 1.27 × 10⁻⁹ kg/m²s

To find: Diffusion coefficient of carbon, D

Formula: Fick's second law of diffusion
∂c/∂t = D(∂²c/∂x²)

Where,
c = Concentration of carbon
t = Time
x = Distance
D = Diffusion coefficient

CALCULATION:
Let's consider the concentration gradient, ∆c = c2 - c1 = 0.68 - 0.25 = 0.43 kg/m³
Let's consider the distance, ∆x = 3mm - 1mm = 2mm = 0.002m
Let's consider the time, ∆t = 1s

From Fick's second law of diffusion,
J = -D(∆c/∆x)

Substituting the given values,
1.27 × 10⁻⁹ = -D(0.43/0.002)
D = -1.27 × 10⁻⁹ / (0.43/0.002)
D = 5.91 × 10⁻¹² m²/s

Therefore, the diffusion coefficient of carbon is 5.91 × 10⁻¹² m²/s.

ANSWER: Option (A) 5.91 × 10⁻¹²
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In industries titanium is hardened through diffusion of carbon. The concentration of carbon at 1mm into the surface of the titanium slab is 0.25kg/m3and at 3mm the concentration is 0.68kg/m3. The rate at which the carbon is entering into its surface is 1.27*10-9kg/m2.s. calculate the value of diffusion coefficient of carbon.a)5.91*10-12b)5.91*10-10c)5.91*10-11d)5.91*10-13Correct answer is option 'A'. Can you explain this answer?
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