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sin3A =cos (A-26),where3A is an acute angle ,find the value of A
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Most Upvoted Answer
sin3A =cos (A-26),where3A is an acute angle ,find the value of A Relat...
Given us,
3a is an acute angle
sin3a = cos(a - 26)
=> cos(90-3a)= cos(a -26)
=> 90 - 3a = a - 26
=> -3a - a = - 26-90
=> -4a = -116
=> a = -116/-4
=> a = 29
hence, a= 29

hope its help you.
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sin3A =cos (A-26),where3A is an acute angle ,find the value of A Related: Ratio Complementary Angle?
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