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A binary mixture of oxygen and nitrogen with partial pressures in the ratio 0.21 and 0.79 is contained in a vessel at 300 K. If the total pressure of the mixture is 1 * 10 5 N/m2, find overall mass density 
  • a)
    4.156 kg/m3
  • b)
    3.156 kg/m3
  • c)
    2.156 kg/m3
  • d)
    1.156 kg/m3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A binary mixture of oxygen and nitrogen with partial pressures in the ...
Explanation: For oxygen = 0.269 kg/m3 and for nitrogen = 0.887 kg/m3.
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Most Upvoted Answer
A binary mixture of oxygen and nitrogen with partial pressures in the ...
Explanation:

Given:
Partial pressure of oxygen (PO2) = 0.21 * 1 * 10^5 N/m^2 = 21000 N/m^2
Partial pressure of nitrogen (PN2) = 0.79 * 1 * 10^5 N/m^2 = 79000 N/m^2
Total pressure (Ptotal) = 1 * 10^5 N/m^2
Temperature (T) = 300 K

Calculations:
1. Using Dalton's Law of partial pressures, we can calculate the total number of moles of the mixture as follows:
PO2 + PN2 = Ptotal
21000 + 79000 = 1 * 10^5
100000 = 1 * 10^5
Hence, the total number of moles of the mixture is 1 mole.
2. The ideal gas law equation can be used to find the total volume of the mixture:
PV = nRT
1 * V = 1 * 8.314 * 300
V = 2494.2 m^3
3. The total mass of the mixture can be calculated using the ideal gas equation:
m = (PO2 + PN2) * V / RT
m = (21000 + 79000) * 2494.2 / (8.314 * 300)
m = 1.156 kg
4. Finally, the overall mass density can be found by dividing the total mass by the total volume:
Density = mass / volume
Density = 1.156 / 2494.2
Density ≈ 0.000463 kg/m^3
Therefore, the overall mass density of the binary mixture of oxygen and nitrogen at 300 K is approximately 1.156 kg/m^3.
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A binary mixture of oxygen and nitrogen with partial pressures in the ratio 0.21 and 0.79 is contained in a vessel at 300 K. If the total pressure of the mixture is 1 * 105N/m2, find overall mass densitya)4.156 kg/m3b)3.156 kg/m3c)2.156 kg/m3d)1.156 kg/m3Correct answer is option 'D'. Can you explain this answer?
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