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Consider the above problem, if the fluid flow rates and the inlet conditions remain unchanged, workout the lowest temperature to which the oil may be cooled by increasing length of the exchanger
  • a)
    46.62 degree Celsius
  • b)
    56.62 degree Celsius
  • c)
    66.62 degree Celsius
  • d)
    76.62 degree Celsius
Correct answer is option 'C'. Can you explain this answer?
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Consider the above problem, if the fluid flow rates and the inlet cond...
Effectiveness = 1 – [exponential [- NTU (1 – C)]/1 + C].
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Consider the above problem, if the fluid flow rates and the inlet cond...
Given:
Fluid flow rates and inlet conditions remain unchanged
Temperature difference across the exchanger is constant
Length of the exchanger is increased

To find:
Lowest temperature to which the oil may be cooled

Solution:
As the length of the exchanger is increased, the heat transfer area also increases, which increases the overall heat transfer coefficient.

The heat transfer rate equation is given by:
Q = U × A × ΔTlm

where,
Q = Heat transfer rate
U = Overall heat transfer coefficient
A = Heat transfer area
ΔTlm = Logarithmic mean temperature difference

As the temperature difference across the exchanger is constant, the heat transfer rate increases with an increase in U and A.

The outlet temperature of the oil can be calculated by using the equation:
Tout = Tin - Q / (m × Cp)

where,
Tout = Outlet temperature of oil
Tin = Inlet temperature of oil
Q = Heat transfer rate
m = Mass flow rate of oil
Cp = Specific heat of oil

As Q increases with an increase in U and A, the outlet temperature of the oil decreases.

Therefore, by increasing the length of the exchanger, the lowest temperature to which the oil may be cooled is 66.62 degree Celsius, which is option (c).
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